I hope my question is not too basic here.

I have a very specific setting and I am trying to not use "big theorems". I hope someone can give me a hint.


Let $J/k$ be the Jacobian of a hyperelliptic curve of genus $2$ curve $H$ with one rational point at infinity $\infty$.
Consider $\iota:H\to J$ given by the usual embedding $\iota(P)=[P-\infty]$. Let $\Theta:=\text{Im}(\iota)$. 

I need to use that $\deg\iota^*\Theta=2$, that is, $\iota^*\Theta=2\infty$. Poincare's formula helps as this is equivalent to calculate the self intersection $\Theta\bullet\Theta$, but I think a simpler argument could help using that $J$ is the jacobian of a hyperelliptic curve $H$ (which has a symmetric theta divisor isomorphic to $H$).

I want to calculate this special case by hand but I have some problems understanding the pullback of $\Theta$ under $\iota$.

I saw a proof in the book $\textit{Diophantine geometry - An Introduction}$  by Silverman and Hindry, theorem A.8.2.1 for general jacobians and non-symmetric Theta divisors but I think in this genus $2$ case it can be simpler.

Also there is this question http://mathoverflow.net/questions/139929/pullback-of-theta-divisor 
Which is also very general.

I am working over $\overline{\mathbb{F}_q}$, and I am trying not to abuse of the $\mathbb{C}$ proofs and then using Lefschetz principle.