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Graham Leuschke
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A necessary and sufficient condition for your question to have a positive answer is that $A$ be equidimensional, that is, $\mathrm{dim} (A/\mathfrak{p}) = \mathrm{dim}(A)$ for every minimal prime $\mathfrak p$. This eliminates exactly the phenomenon in Charles Staats' example.

Graham Leuschke
  • 5.8k
  • 2
  • 29
  • 37