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Paul Fabel
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No, even if Y=[0,1]. The piecewise linear continuous nondecreasing surjection $f:[0,1] \rightarrow [0,1]$ which maps [1/3,2/3] to 1/2 and is otherwise 1-1 and linear has no continuous section.

Paul Fabel
  • 2k
  • 15
  • 23