Let $L/K$ be a quadratic extension of number field $K$.
Let $\sigma$ be a generator of $Gal(L/K)$.

Let $E/K$ be an elliptic curve defined over $K$ and $Sha(E/K)$ be its Tate-Shafarevich group.
$Gal(L/K)$ acts on $Sha(E/L)$ naturally(cf. https://mathoverflow.net/questions/448399/how-galois-group-acts-on-tate-shafarevich-group).


There is a canonical isomorphism $\tau: E(L)\cong E_D(L)$ given by $(x,y)\mapsto (x, y/\sqrt{D})$.

On the other hand , there exists an  isomorphism $\phi: Sha(E/L)\cong Sha(E_D/L)$ induced by $\tau$ though I cannot write down the map between them.

What I want to prove is 

> $\sigma \phi(C)=-\phi \sigma(C)$ for all $C \in Sha(E/L)$


$\sigma \tau=-\tau \sigma$ holds because we can calculate its coordinates explicitly, but I cannot calculate both $\sigma \phi$ and $\phi \sigma$, so I'm having difficulty to prove $\sigma \phi(C)=-\phi \sigma(C)$ for all $C \in Sha(E/L)$. How can I overcome this trouble and prove $\sigma \phi(C)=-\phi \sigma(C)$ for all $C \in Sha(E/L)$ ? 

Thank you in advance.