Ethan Akin's <a href="http://www.sciencedirect.com/science/article/pii/0022404978900324">"proof"</a> that all vector bundles are stably trivial, and hence the $K$-theory of any space must vanish:

Let $V$ be a vector bundle over the base space $B$.  Let $T$ be a trivial bundle of the same rank as $V$.  To show that $V$ is stably trivial, it suffices to prove that $$V\oplus V=V\oplus T$$.

Let $P$ be the principal bundle associated with $V$.  Pull $P$ back over itself to get a bundle $Q$:

[![enter image description here][1]][1]

Then $Q$ (together with the map to $B$) is the principal bundle associated to $V\oplus V$.  But the bundle $Q\rightarrow P$ clearly has a section, namely the diagonal map (viewing $Q$ as a subspace of $P\times P$).  Thus $Q=P\times GL_n$, which (together with the same map to $B$) is the principal bundle associated to $V\oplus T$.  


  [1]: https://i.sstatic.net/BVYRc.gif