The answer is yes, already for an affine variety.
The following example is taken by Dimca's book Singularities and topology of hypersurfaces, see page 102 and page 105. We work over $\mathbb{C}$.
Let $V \subset \mathbb{P}^n$ be a hypersurface and $U:=\mathbb{P}^n \setminus V$ its complement. Since $V$ is very ample, $U$ is an affine variety. Then we have the following
Proposition. Assume that $V$ has $k$ irreducible components $V_1, \ldots, V_k$ with $\deg V_i =d_i$. Then $$H_1(U)=\mathbb{Z}^{k-1} \oplus \mathbb{Z}/d \mathbb{Z},$$ where $d$ denotes the greatest common divisor of the $d_i$.
If moreover $V$ has only normal crossing singularities in codimension $1$, then $\pi_1(U)$ is abelian, hence it is isomorphic to the group $H_1(U)$ given above.
In particular, if $V$ is irreducible and normal of degree $d$, one has $$\pi_1(U)=\mathbb{Z}/d \mathbb{Z}.$$