Return to Revisions

2 of 2

replaced http://math.stackexchange.com/ with https://math.stackexchange.com/

edited Apr 13, 2017 at 12:19

1
2
3

A Chebotarev-free argument is given by our own @Pete L Clark here:

https://math.stackexchange.com/questions/6976/proving-that-an-integer-is-the-n-th-power

answered Jul 5, 2013 at 4:52

96.4k
11
153
366