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Felix Goldberg
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Try $A=\begin{bmatrix}0 & 1\\\\ 1 & 0\\\\ 0 & 0\end{bmatrix}$ and $B=\begin{bmatrix}0 & 1\\\\ 0 & 0\\\\ 1 & 1\end{bmatrix}$. Then $rank([A,B])=3$ but $rank(A)=rank(B)=2$.

Felix Goldberg
  • 7k
  • 4
  • 31
  • 55