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Geoff Robinson
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These things are well studied in the literature. You probably want to restrict to irreducible subgroups, and it's probably just as well to work with ${\rm GL}(3,K).$ In such a low dimensions, the Schur index usually will not play a role. The Schur index usually arises because it can happen that a complex irreducible character $\chi$ may take values in a field $K,$ but might not be afforded by a representation over $\chi.$ There is, however, a smallest integer $m_{K}(\chi)$ such that the character $m_{K}(\chi) \chi$ is afforded by a representation over $\chi.$ For $3$-dimensional representations over $K,$ we will not have $m_{K}(\chi) >1,$ and $3$-dimensional irreducible complex representations will be realisable over the field of their character. Similarly, except in degenerate cases, we won't have irreducible representations over $K$ which are not absolutely irreducible, since such a a representation would break up over some extension field of $K$ as a sum of Galois conjugate repesentations of the same degree.

Geoff Robinson
  • 44.4k
  • 5
  • 123
  • 169