First, let me state that I am not a formally-trained mathematician, therefore please forgive my approximations and help me correct my errors. Second, I am looking for prior work related to what I would like to call *Hypertype Theory*. What follows is a short introduction to the topic. But before that, here are a few specific questions that will hopefully make this question less open-ended.

 

## Questions

  1. Where can we find prior work on the subject?
  2. Does $\mathbb{H}_n$ converge toward $\mathbb{R}$?
  3. What would be a simple way of establishing such a convergence?
  4. What are examples of important numbers that appear in $\mathbb{H}_{n\ge4}$?
  5. Could the proposed notation be improved upon?
 

 

## Introduction

The basic idea is this: a group is roughly defined with a triplet of two operators and an identity term, while a field is made of two such triplets plus a distributivity law. But what do we get with a third triplet? And what if an unlimited number of such triplets could be added in a recursive manner? Would such an object exhibit any valuable properties?

Interestingly, there is one such object, and it can be constructed in a quite straightforward fashion by using Albert Bennett’s [commutative hyperoperations](https://en.m.wikipedia.org/wiki/Hyperoperation#Commutative_hyperoperations). Most importantly, this object is isomorphic to a strict superset of $\mathbb{Q}$ and to a strict subset of $\mathbb{R}$, while possibly converging toward $\mathbb{R}$.

 

## Commutative Operators

$a\overset{1}{\oplus}b = e ^ {ln(a)} + e ^ {ln(b)} = a + b$

$a\overset{2}{\oplus}b = e ^ {ln(a)} × e ^ {ln(b)} = a × b$ 

$a\overset{3}{\oplus}b = e ^ {ln(a) × ln(b)} = a ^ {ln(b)} = b ^ {ln(a)}$

$a\overset{4}{\oplus}b = e ^ {\displaystyle e ^ {ln(ln(a)) × ln(ln(b))}}$

$\cdots$

$\displaystyle a\overset{n+1}{\oplus}b = e ^ {ln(a)\overset{n}{\oplus}ln(b)}$

   

## Non-Commutative Operators

$a\overset{1}{\ominus}b = e ^ {ln(a)} - e ^ {ln(b)} = a - b$

$a\overset{2}{\ominus}b = e ^ {ln(a)} ÷ e ^ {ln(b)} = a ÷ b$ 

$a\overset{3}{\ominus}b = e ^ {ln(a) ÷ ln(b)} = a ^ {1 ÷ ln(b)}$

$a\overset{4}{\ominus}b = e ^ {\displaystyle e ^ {ln(ln(a)) ÷ ln(1 ÷ ln(b))}}$

$\cdots$

$a\overset{n+1}{\ominus}b = e ^ {ln(a)\overset{n}{\ominus}ln(b)}$

 

## Identity Terms

$i_1 = 0$

$i_2 = 1$

$i_3 = e$

$i_4 = e ^ e$

$\cdots$

$i_{n+1} = e ^ {i_n} = e \upuparrows (n - 1) \quad (n > 1)$

 

## Core Identities

From these definitions, we can recursively prove the following core identities:

$a\overset{n}{\ominus}i_n = i_n$

$a = b \Longleftrightarrow a\overset{n}{\ominus}b = i_n$

$a\overset{n}{\ominus}(b\overset{n}{\ominus}c) = c\overset{n}{\ominus}(b\overset{n}{\ominus}a)$

$(a\overset{n}{\oplus}b)\overset{n}{\ominus}c = a\overset{n}{\ominus}(c\overset{n}{\ominus}b)$

In general, these core identities can be used as axiomatic definitions, but it just so happens that we can prove them when the operators are defined using commutative hyperoperators. This ensures that we are not dealing with purely-theoretical objects.

 

## Group Properties

From the core identities stated above, we can prove the following properties:

 

**$\overset{n}{\ominus}$ Anticommutativity**

$a\overset{n}{\ominus}b = i_n\overset{n}{\ominus}(b\overset{n}{\ominus}a)$

 

**$\overset{n}{\oplus}$ Left and Right Identity**

$i_n\overset{n}{\oplus}a = a\overset{n}{\oplus}i_n = a$

 

**$\overset{n}{\oplus}$ Left and Right Identity**

$i_n\overset{n}{\oplus}a = a\overset{n}{\oplus}i_n = a$

 

**$\overset{n}{\oplus}$ Commutativity**

$a\overset{n}{\oplus}b = b\overset{n}{\oplus}a$

 

## Additional Properties

Along the way, the following properties can be established as well:

 

**Double Reverse**

$i_n\overset{n}{\ominus}(i_n\overset{n}{\ominus}a) = a$

 

**Associative Commutativity**

$(a\overset{n}{\ominus}b)\overset{n}{\ominus}c = (a\overset{n}{\ominus}c)\overset{n}{\ominus}b$

 

**Affine Equivalence**

$a\overset{n}{\ominus}b = c \Longleftrightarrow a\overset{n}{\ominus}c = b$

 

**Dual Substitution**

$a\overset{n}{\oplus}b = a\overset{n}{\ominus}(i_n\overset{n}{\ominus}b)$

 

**Dual Identities**

$(a\overset{n}{\ominus}b)\overset{n}{\oplus}b = a$

$(a\overset{n}{\oplus}b)\overset{n}{\ominus}b = a$

 

## Hypertypes

We define a sequence of hypertypes by granting the hypertype $\mathbb{H}_n$ the triplet $(\overset{n}{\oplus}, \overset{n}{\ominus}, i_n)$ and all the triplets granted to its predecessors. This makes $\mathbb{H}_1$ isomorphic to $\mathbb{Z}$ and $\mathbb{H}_2$ isomorphic to $\mathbb{Q}$, while $\mathbb{H}_3$ is isomorphic to a strict subset of $\mathbb{R}$, which we call *exponential* numbers $\mathbb{E}$.

We have yet to study distributivity properties on hypertypes for $n > 2$.

We call our structure *Hypertypes* instead of *Hypergroups* for three main reasons: first, *Hypergroups* refer to an already-existing collection of objects that have nothing to do with *Hypertypes*; second, we are interested in developing the *Hypertype Theory* in the context of Type Theory, without relying on any of the axioms of Set Theory; third, we are interested in treating commutative operators separately from their non-commutative duals.

The third point is of critical importance: in order to properly handle real-world measures like temperatures that are non-additive (physicists and statisticians call them *intensive*), we must be able to distinguish them from measures that are additive (*extensive*). Therefore, our hierarchy of types should add one operator at a time, always starting with the non-commutative operator. Therefore, for every hypertype $\mathbb{H}_n$, we will have an intensive sub-hypertype $\mathbb{H}_{\bar{n}}$ defined with the non-commutative operator but without its commutative dual.

This approach is nicely supported by the fact that the Core Properties defined above are written with affine-style identites focused on the non-commutative operator. Therefore, we can properly define the commutative operator from its non-commutative dual. This approach also reduces the number of axiomatic definitions that need to be stated when defining the two operators.

 

## Notation

The notation introduced above is especially useful for $n = 3$. Therefore, we suggest that the index $n$ can be ommitted whenever it is equal to $3$. Doing so, we would benefit from a single-symbol notation for the commutative power law and its inverse.

$a \oplus b = a\overset{3}{\oplus}b = e ^ {ln(a) × ln(b)} = a ^ {ln(b)} = b ^ {ln(a)}$

$a \ominus b = a\overset{3}{\ominus}b = e ^ {\frac{ln(a)}{ln(b)}} = a ^ {\frac{1}{ln(b)}}$

Alternatively, if we were to limit ourselves to symbols found on most keyboards, we would suggest:

$a \# b = a\overset{3}{\oplus}b = e ^ {ln(a) × ln(b)} = a ^ {ln(b)} = b ^ {ln(a)}$

$a \backslash b = a\overset{3}{\ominus}b = e ^ {\frac{ln(a)}{ln(b)}} = a ^ {\frac{1}{ln(b)}}$

 

## Request

If any of this is of any value, please let me know, because I really have no clue.

 

## Credits

Many thanks to the following people for their contributions:

  - [@Henry](https://math.stackexchange.com/users/6460/henry) for having found the triplet for $\mathbb{H}_3$.
  - [Prof N J Wildberger](https://www.youtube.com/user/njwildberger) for being such an inspiration to young contrarian mathematicians.