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Simon Wadsley
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By considering a^0 and 0^b, it seems reasonable to me to define 0^0 to be 0 or 1 depending on what you're up to. Of course you could argue that you just shouldn't define 0^0 for this reason.

This might be considered cheating as an answer to question 2 though because I'm really extending a map for N^2 to (0,0) in two different ways.

Simon Wadsley
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