I ask about an idea to prove this formula:
$Γ(1/2-iβ)=((√π)/(√(coshπβ)))exp(-i(2ϑ(β)+βln2π+arctan(tanh(1/2)πβ)))$
where $ϑ(β)$ is the Riemann Siegel function.
I ask about an idea to prove this formula:
$Γ(1/2-iβ)=((√π)/(√(coshπβ)))exp(-i(2ϑ(β)+βln2π+arctan(tanh(1/2)πβ)))$
where $ϑ(β)$ is the Riemann Siegel function.