It is not a finite dimensional Lie group. For example, all of the maps $$ \Phi\bigl(z,[a,b]\bigr) = \bigl(z, [a+p(z),b]\bigr), $$ where $p:\mathbb{C}^\ast\to \mathbb{C}$ is holomorphic, belong to this group. More generally, the automorphism group is essentially the semi-direct product of $\mathbb{C}^\ast$ with the group of holomorphic mappings $p:\mathbb{C}^\ast\to PSL(2,\mathbb{C})$.
To see this, note that the foliation of $\mathbb{C}^\ast\times \mathbb{P}^1$ by the fibers $\{z\}\times \mathbb{P}^1$ for $z\in\mathbb{C}^\ast$ must be preserved by any automorphism, since these are the only compact complex curves that represent a generator of the second homology group (with the orientation given by the complex structure). Thus, every automorphism $\Phi$ has a corresponding automorphism $\phi:\mathbb{C}^\ast\to\mathbb{C}^\ast$ that intertwines $\Phi$ and $\phi$ with the projection $\mathbb{C}^\ast\times\mathbb{P}^1\to\mathbb{C}^\ast$ onto the first factor. Of course $\phi$ is represented by scalar multiplication by a nonzero complex number $\lambda$, and the map $\Phi\mapsto\lambda$ is a homomorphism from this automorphism group to $\mathbb{C}^\ast$. The kernel of this homomorphism is clearly the group of holomorphic mappings $p:\mathbb{C}^\ast\to PSL(2,\mathbb{C})$, as this latter group is the full group of automorphisms of $\mathbb{P}^1$.