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Chris
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Regarding a proof in Bourbaki's Topological Vector Spaces

In Bourbaki's TVS Chapter IV Section 5, the last part of the proof of Proposition 2(in the 4th line from the bottom), it states that "Since $u(X)$ is a compact subset in $K$..."

Why this is true? (Actually one only needs to show the set $\{u(x_m)|m\in N \}$ is bounded for the proof to get through). Thanks in advance.

Chris
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