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fixed the statement.
Igor Rivin
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A conjecturally easier version of matrix Descartes rule of signs.

This is (quite obviously) inspired by this question. Let $C_i$ be symmetric positive definite matrices. Then is it true that there is exactly one symmetric positive definite $X$ such that $F(X) = X^n - \sum_{i=0}^n C_i \circ X^i = 0$, where $\circ$ denotes the Schur (component-wise) product (and exponentiation is with respect to that same product) Notice that unlike in the inspiring question, the Schur product is commutative.

Igor Rivin
  • 96.4k
  • 11
  • 153
  • 366