I would like to ask a follow up on a [question I asked some days ago][1]. Consider the function $$f_{n}(x)=e^{-x^2}x^n.$$ and the function $$h_p(x):=e^{-\vert x \vert^p}.$$ My goal then was to analyze $$ F_2(y):=\frac{(f_2*h_2)(y)}{(f_0*h_2)(y)}- \left(\frac{(f_1*h_2)(y) }{(f_0*h_2)(y)}\right)^2$$ and Iosif Pinelis showed that this expression is constant. Now instead of convolving with $e^{-x^2}$ one could convolve with a function that decays slower than $e^{-x^2}$ for example $e^{-\vert x \vert}.$ That is, we then get $$ F_1(y):=\frac{(f_2*h_1)(y)}{(f_0*h_1)(y)}- \left(\frac{(f_1*h_1)(y) }{(f_0*h_1)(y)}\right)^2.$$ Mathematica shows that $F_1$ is now not at all constant but has a unique maximum at $0$ and decreases from there. On the other hand one can consider the faster decaying function $e^{-x^4}$ and consider $$ F_4(y):=\frac{(f_2*h_4)(y)}{(f_0*h_4)(y)}- \left(\frac{(f_1*h_4)(y) }{(f_0*h_4)(y)}\right)^2.$$ In this case, the function has a unique minimum at $y=0$ and increases from there. **Question:** Can we show that $F_p$ has a global maximum at zero for $p>2$ and a global minimum at zero for $p<2$? **Further observations:** All functions $F_p$ are positive by the Cauchy-Schwarz inequality. So to summarize for - slow decay - $F_1$ has a unique minimum (Fig. 1) [![][2]][2] - medium decay-$F_2$ is a constant function. - fast decay - $F_4$ has a unique maximum (Fig. 2). [![][3]][3] I also checked the function $e^{-\vert x \vert^{2+10^{-4}}}$, i.e. with an exponent slightly above $2$ [![][4]][4] and it seems the function has the expected behaviour, i.e. there exists a unique maximum at zero and the function decays from there. One sees the opposite effect by convolving with $e^{-\vert x \vert^{2-10^{-4}}}.$ [![][5]][5] **Addendum:** I also checked for log-convexity/log-concavity. Apparently, the functions $F_p$ are not log-convex or log-concave in general. And finally, I computed the first derivative for convolving with $e^{-\vert x \vert^p}$ at $p=2$ by numerically differentiating [![][6]][6] [1]: https://i.sstatic.net/2NvRL.jpg [2]: https://i.sstatic.net/VIFOi.jpg [3]: https://i.sstatic.net/H1N0U.jpg [4]: https://i.sstatic.net/4HMAP.jpg [5]: https://i.sstatic.net/Caurg.jpg [6]: https://i.sstatic.net/0uVdR.jpg