So far as I know, there is no compelling evidence to support this conjecture.  (And some leading arithmetic geometers think it is false.)  Rather, there are some very interesting consequences of this conjecture, e.g. a solution of the Inverse Galois Problem over Q^{solv}: in other words, for any finite group G, there exists a tower of radical extensions 

K_0 = Q, K_1 = K_0(a_0^{1/n_0}) < K_2 = K_1(a_1^{1/n_1}) < ... <= K_n

and a Galois extension L/K_n with Galois group isomorphic to G.  It also shows that geometrically irreducible algebraic varieties "acquire rational points" in a very different way from irreducible zero-dimensional varieties (which have a unique minimal 
splitting field which need not be solvable).  

Of course, interesting things which follow from a conjecture are, if anything, evidence _against_ the truth of the conjecture, although they support the claim that the _question_ is interesting. 

There is one impressive result towards this conjecture, namely the Ciperiani-Wiles theorem: let C_{/Q} be a genus one curve with points everywhere locally and semistable Jacobian elliptic curve E.  Then C(Q^{solv}) is nonempty.

On the negative side, there is a paper of Ambrus Pal which constructs, for each sufficiently large integer g, a curve C of genus g over a field K which does not admit any points over the maximal solvable extension of K.  (Here K is not a number field.)

On the other hand, as far as I know, it is still open to find an absolutely irreducible variety V/Q which fails to have rational points over the maximal _metabelian extension_ of Q, i.e., over (Q^{ab})^{ab}.  For some thoughts about this, see

http://www.math.uga.edu/~pete/abeliantalk.pdf