R[x,y]/(y^2-x^3-\pi x^2) gives the coordinate ring of a bad cubic curve, where \pi is a uniformizer in R.  Remove the origin (which is the one singular point), and projectivize the curve by adding a point at infinity, so your group has an identity.

The generic fiber (treating \pi as a unit) is then the smooth part of a nodal cubic, yielding <b>G</b><sub>m</sub>, and the special fiber (setting \pi to zero) is the smooth part of a cuspdal cubic, yielding <b>G</b><sub>a</sub>.