A nice geometric way of endowing a Grassmann manifold with a metric (understood here as a *distance*, and not directly as a *Riemannian metric*) is to use the [Hausdorff distance][1] for subsets of the round sphere.

Consider $V$ a real vector space of dimension $n$ endowed with an inner product, and let $Gr_k(V)$ be the Grassmannian of $k$-planes on $V$. Let $x,y\in Gr_k(V)$, and denote by $S_x$ and $S_y$ the subspheres of the unit sphere $S_V=\{v\in V:\|v\|=1\}$ defined by intersecting it with the subspaces $x$ and $y$ respectively. Then $S_x,S_y\subset S_V$ are closed subsets and the distance between $x,y\in Gr_k(V)$ can be defined as the Hausdorff distance between these sets:
$$dist(x,y)=dist_H(S_x,S_y).$$


Note that this distance **does not coincide** with the symmetric space distance on $Gr_k(V)=SO(n)/SO(k)SO(n-k)$. As explained in the paper of Neretin in Michor's answer, the symmetric space distance is computed in terms of the [*principal angles*][2] between two subspaces (namely, it is the square root of the sum of the squares of these angles); while the above distance defined in terms of the Hausdorff distance of closed sets in the unit sphere measures exactly the largest principal angle between subspaces, ignoring all the other smaller principal angles.


  [1]: http://en.wikipedia.org/wiki/Hausdorff_distance
  [2]: http://en.wikipedia.org/wiki/Principal_angles