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Questions tagged [set-theory]

forcing, large cardinals, descriptive set theory, infinite combinatorics, cardinal characteristics, forcing axioms, ultrapowers, measures, reflection, pcf theory, models of set theory, axioms of set theory, independence, axiom of choice, continuum hypothesis, determinacy, Borel equivalence relations, Boolean-valued models, embeddings, orders, relations, transfinite recursion, set theory as a foundation of mathematics, the philosophy of set theory.

16 questions from the last 7 days
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Diamonds on supercompact $\kappa$ after a $\kappa$-c.c. forcing

Let $\kappa$ be supercompact. Then the (supercompact) Laver diamond holds at $\kappa$: There is $f:\kappa\to V_\kappa$ such that for all $\lambda\geq \kappa$ and $x\in H(\lambda^+)$ there is $j:V\to M$...
Yujun Wei's user avatar
3 votes
0 answers
65 views

Diamonds at $\omega_2$ under PFA

Let $\lambda$ be a cardinal, and $S\subset \lambda^+$ be stationary. A $\diamondsuit^+(S)$-sequence is a sequence $\langle \mathcal{A}_\alpha\mid \alpha\in S\rangle$ such that each $\mathcal{A}_\alpha\...
Yujun Wei's user avatar
2 votes
1 answer
139 views

An uncountable measurable subset of $\Bbb R$ containing no nonempty perfect set

$\newcommand\R{\Bbb R}$Assuming the axiom of choice, is there an uncountable Lebesgue-measurable subset $S$ of $\R$ that contains no nonempty perfect set? Of course, such a set $S$, if it exists, ...
Iosif Pinelis's user avatar
0 votes
0 answers
86 views

How near are a groupoid and its 'preorderification'?

As remarks, a groupoid is a category with only (categorical) isomorphisms as its morphisms and a preorder is a category only having one morphism between each object. If we choose one isomorphism by ...
categoricalequivalent's user avatar
5 votes
0 answers
85 views

Query about extender embeddings

This seems as though it should be a result which is possible to prove but I was just wondering if I have it right and also if there is a source for it. Suppose that $j:V_{\alpha} \rightarrow V_{\beta}$...
Rupert's user avatar
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-2 votes
0 answers
72 views

There is a typo in Stall's textbook on Set Theory: unable to prove the trichotomy of sets (m ∈ n or m = n, or n ∈ m) [migrated]

Here is the textbook, chapter 7, page 300. This lemma seems very of important, and I've spend about 8 hours trying to figure it out, but I'm unable to prove even the weaker version of the lemma (only ...
Iaroslav Baranov's user avatar
2 votes
0 answers
60 views

Consistency of Sigma-V-2 uniformization with AD

Is ZF + AD consistent with: For every real $r$, every true $Σ^V_2(r)$ statement has a $Δ^V_2(r)$ example? DC is provable in ZF + every true $Σ^V_2$ statement has a $Δ^V_2$ example (i.e. witness). ...
Dmytro Taranovsky's user avatar
3 votes
1 answer
130 views

Forcing equivalence and equal generic extensions

Two forcing notions $\Bbb P$ and $\Bbb Q$ could be defined to be forcing equivalent if the associated complete Boolean algebras are isomorphic (so, the CBA's formed by considering the regular opens of ...
Tristan vd Vlugt's user avatar
2 votes
2 answers
121 views

Existence of k-complete uniform ultrafilter over a regular cardinal, k is strongly compact

This is a question about set theory. Let $\kappa\leq \lambda$ be infinite cardinals such that $\kappa$ is strongly compact and $\lambda$ is regular. My question is: how to construct a $\kappa$-...
Chris's user avatar
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5 votes
1 answer
145 views

Does there exist a section of $\mathcal{P}(\kappa)\to\mathcal{P}(\kappa)/(\text{fin})$ that is "nearly Boolean"?

The following might be a somewhat esoteric question: Does there exist an infinite cardinal $\kappa$ and a section $f$ of the quotient map $\pi:\mathcal{P}(\kappa)\to\mathcal{P}(\kappa)/(\text{fin})$ (...
David Gao's user avatar
  • 2,830
8 votes
0 answers
193 views

Can $\mathbb{C}$ have a "doppelganger" in $L(\mathbb{R})$ with countable automorphism group?

Working in $\mathsf{ZFC}$ + large cardinals (a proper class of Woodins, to be precise), is there a field $F\in L(\mathbb{R})$ such that $V\models F\cong\mathbb{C}$ and $L(\mathbb{R})\models\vert\...
Noah Schweber's user avatar
6 votes
1 answer
548 views

Destroying scales

Suppose $\lambda$ is a cardinal with uncountable cofinality and $C\subseteq\lambda$ is a club of ordertype cf$(\lambda)$. Let $f=\langle f_\xi\mid\xi<\lambda^+\rangle$ be a scale consisting of ...
Seba Thei's user avatar
  • 533
-2 votes
0 answers
78 views

Every well-ordered set is isomorphic to an unique ordinal? [closed]

Every well-ordered set $W$ is isomorphic to a unique ordinal Proof: We start with some well-ordered set $W$. We attempt to construct a bijective map from $W$. Let us consider this class $$\{(x, \...
Duck Gia's user avatar
1 vote
0 answers
79 views

How strong is separation + reflection without transitivity?

Consider a theory $T$ with a binary relation $\in$ and the following axiom schemas: $\exists u \forall x (x \in u \leftrightarrow x \in a \land \phi)$ where $u$ is not free in $\phi$. This is the ...
user76284's user avatar
  • 2,203
5 votes
1 answer
459 views

NBG, ZFC+I, and Global Choice

In Shulman's 2008 paper 'Set Theory for Category Theory', he includes amongst the axioms of $\sf NBG$ the axiom of limitation of size. Being well known to imply the axiom of global choice, it seems to ...
Noah Laikin's user avatar
1 vote
0 answers
97 views

Is this theory synonymous with ZF + Global Choice?

$\textbf{Logic:}$ Mono-sorted first order logic with equality. $\textbf{Extralogical Primitives: } <, \in$ Define: $x > y \iff y < x \\ x \leq y \iff x < y \lor x=y \\ x \not > y \iff \...
Zuhair Al-Johar's user avatar