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Difference between a partial selector and a selector...

In Kharazishvili's "Nonmeasurable Sets and Functions" there is the following theorem: There exists a subset $X$ of $\mathbb{R}$ which is a Vitali set and a Bernstein set. The proof is as follows: ...
George Lazou's user avatar
1 vote
2 answers
405 views

Cardinality of the set of countable dense subgroups of the reals up to isomorphism.

Joel David Hamkins in an answer to my question Countable Dense Sub-Groups of the Reals points out that "one can find an uncountable chain of countable dense additive subgroups of $\mathbb{R}$ whose ...
George Lazou's user avatar
2 votes
1 answer
404 views

Follow up question on union of disjoint Vitali sets...

Since I haven't received a satisfactory answer to my initial question I'm going to ask a somewhat weaker one... This time we say $X$ is a Vitali set in the closed interval $[0, 1]$ with respect to $\...
George Lazou's user avatar
8 votes
3 answers
846 views

A compactness property for Borel sets

Is the following generalised compactness property of Borel sets in a Polish space consistent with ZFC? ($*$) Let $\mathcal{B}$ be a family of $\aleph_1$-many Borel sets. If $\bigcap \mathcal{B} = \...
Alex Simpson's user avatar
7 votes
1 answer
2k views

Universally measurable sets and weak topology

After I posted this question, a couple of months ago, and got from MO-users several good hints, I think i'm ready, after some study, to ask another related question (or rather, to focus on the main ...
user avatar
6 votes
2 answers
492 views

Distinct, non-homeomorphic, profinite topologies on a given abstract group ?

Just a silly little question which arose in connection with infinite Galois groups and their Krull topology:- can a given abstract group be endowed with distinct, non-homeomorphic, profinite ...
Stephan F. Kroneck's user avatar
3 votes
1 answer
1k views

$\Delta_{2}^{1}$-hard set?

Hello everybody! I'm interested in $\Delta_{2}^{1}$ subsets of Polish spaces, i.e. those sets that are both $\Pi_{2}^{1}$ and $\Sigma_{2}^{1}$ in the boldface hierarchy of Polish spaces. There is a ...
user avatar
5 votes
1 answer
523 views

Injections to binary sequences that preserve order

Suppose we have a countable set S with a total order. Can we give an injection from S to the set of finite binary sequences that end in all zeros that preserves the ordering? The order on binary ...
Jules's user avatar
  • 493
3 votes
0 answers
251 views

What is the origin of the metrization problem for compact convex sets?

The following is an ``old question in analysis:'' Is it true that every perfectly normal compact convex subset of a locally convex topological vector space is metrizable? Here perfectly normal means ...
Justin Moore's user avatar
  • 3,547
3 votes
2 answers
994 views

measurability of integrated functions

DISCLAIMER: I'm not a mathematician, but a computer scientist, so I hope the question is not trivial (or perhaps I hope so, in order to get a definitive answer). Anyway it's not a homework, as ...
user avatar
5 votes
2 answers
655 views

$C^n$ And Forcing: Reading a Recent Paper By Kunen

While reading a recent paper by Kunen arxiv.org/abs/0912.3733, which deals with PFA and the existence of certain differentiable functions, (defined on all of $\mathbb{R}$) which map certain $\aleph_1$-...
Not Mike's user avatar
  • 1,615
11 votes
2 answers
721 views

Inconsistency and workaday independence.

Set-theoretic topologists, for example, encounter many propositions that turn out independent from set theory. Sometimes these results require novel forcing arguments, but often they simply rely on ...
David Feldman's user avatar
24 votes
0 answers
2k views

Subfields of $\mathbb{C}$ isomorphic to $\mathbb{R}$ that have Baire property, without Choice

While sitting through my complex analysis class, beginning with a very low level introduction, the teacher mentioned the obvious subfield of $\mathbb{C}$ isomorphic to $\mathbb{R}$, and I then ...
user avatar
3 votes
1 answer
617 views

How to make an ultranet

The only examples of ultranets/ultrafilters described in Bourbaki and Willard are the trivial ones (generated by a single point). I know that their existence relies in general on the axiom of choice ...
Gabriel Furstenheim's user avatar
1 vote
3 answers
688 views

How to show the cardinality of nonisometric compact metric spaces is the continuum

It is asserted in A Course in Metric Geometry by Burago, Burago, Ivanov that there can be no more than continuum of mutually nonisometric compact spaces How is this proven? Its clear that there ...
Otis Chodosh's user avatar
  • 7,197
12 votes
3 answers
1k views

If Q is a subset of the plane of size less than continuum, then does every closed F in Q extend to a closed connected G in the plane with the same trace on Q? (Or is this independent of ZFC?)

This question arises in connection with this MO question and especially with Sergei Ivanov's wonderful answer, which showed that for any countable set $Q\subset\mathbb{R}^2$ and every closed set $F\...
Joel David Hamkins's user avatar
26 votes
2 answers
5k views

Does Arzelà-Ascoli require choice?

Inspired by a recent Math.SE question entitled Where do we need the axiom of choice in Riemannian geometry?, I was thinking of the Arzelà--Ascoli theorem. Let's state a very simple version: ...
Nate Eldredge's user avatar
3 votes
1 answer
4k views

A sequence with no convergent subsequence without choice

By Tychonoff Theorem $\prod_{\mathbb R} [0,1]$ is compact and since $\mathbb R=2^{\omega}$, if for $\alpha \in 2^{\omega}$, $x_n(\alpha)=\alpha(n)$ then if we consider a subsequence $x_{n_0}, x_{n_1}, ...
Rachid Atmai's user avatar
  • 3,804
9 votes
2 answers
3k views

Compact Hausdorff spaces without isolated points in ZF

$S$ is uncountable := $\vert\mathbb{N}\vert<\vert S\vert$ $S$ is noncountable := $\vert S\vert \not\leq \vert\mathbb{N}\vert$ $(X,T)$ is a nice space := $(X,T)$ is a compact Hausdorff space ...
user avatar
4 votes
2 answers
452 views

A family of subsets with a "gluing" property

Somewhat in line with this previous MathOverflow question: I'm looking at a combinatorial structure consisting of a finite set $S$ of objects, and a family $F$ of designated subsets of $S$. We call ...
joshuahhh's user avatar
  • 306
32 votes
3 answers
6k views

Is "compact implies sequentially compact" consistent with ZF?

Over at the nForum, we've been discussing sequential compactness. The discussion led me to realise that I naively assumed that nets were simply Big Sequences, and that I could make a reasonable guess ...
Andrew Stacey's user avatar
14 votes
4 answers
2k views

Products of Baire spaces

I could not find any references about this fact. I apologize if this is completely trivial, but is the product of two Baire spaces, or for that matter of finitely many of them a Baire space? Now is a ...
Rachid Atmai's user avatar
  • 3,804
5 votes
2 answers
1k views

Improvements of the Baire Category Theorem under (not CH)?

The Baire category theorem implies that a nonempty complete metric space without isolated points must be uncountable. In many situations I have encountered, the "natural examples" of ...
Pete L. Clark's user avatar
3 votes
3 answers
444 views

Shape of long sequences in C(ω_1)

Apologies for the vague title - I couldn't come up with a single sentence that summarised this problem well. If you can, please edit or suggest a better one! This question is also rather specific and ...
David R. MacIver's user avatar
5 votes
0 answers
558 views

continuous selection of a multivalued function?

The title is probably a bit too broad. I frequently encountered the following situation: suppose I need to select a solution to a linear equation from a compact set. Can I make this selection ...
gondolier's user avatar
  • 1,839
-3 votes
2 answers
314 views

Dispensing with the notion of infinity for the sake of coverings [closed]

Instead of taking a one to one correspondence meaning each set has the same number of elements. why not use the concept of coverings of topology? The irrational numbers covers the whole numbers but ...
user4904's user avatar
  • 117
107 votes
9 answers
36k views

solving $f(f(x))=g(x)$

This question is of course inspired by the question How to solve f(f(x))=cosx and Joel David Hamkins' answer, which somehow gives a formal trick for solving equations of the form $f(f(x))=g(x)$ on a ...
Kevin Buzzard's user avatar
80 votes
5 answers
6k views

How do the compact Hausdorff topologies sit in the lattice of all topologies on a set?

This question is about the space of all topologies on a fixed set X. We may order the topologies by refinement, so that τ ≤ σ just in case every τ open set is open in σ. ...
Joel David Hamkins's user avatar
11 votes
5 answers
1k views

Confusion over a point in basic category theory

"Let Top be the category of topological spaces." If I see a definition like this, in which homeomorphic (isomorphic in the category) spaces are not identified together, then for each given topological ...
Cary's user avatar
  • 1,207
47 votes
4 answers
4k views

Which topological spaces admit a nonstandard metric?

My question is about the concept of nonstandard metric space that would arise from a use of the nonstandard reals R* in place of the usual R-valued metric. That is, let us define that a topological ...
Joel David Hamkins's user avatar
37 votes
14 answers
5k views

What are interesting families of subsets of a given set?

Motivation The usual starting point of both Topology and Measure Theory is the definition of a family of subsets of a set $S$. Indeed, one defines a topology on $S$ to be a family of subsets ...
José Figueroa-O'Farrill's user avatar
24 votes
2 answers
1k views

Which are the rigid suborders of the real line?

Which are the rigid suborders of the real line? If A is any set of reals, then it can be viewed as an order structure itself under the induced order (A,<). The question is, when is this structure ...
Joel David Hamkins's user avatar
36 votes
4 answers
4k views

How far is Lindelöf from compactness?

A while ago I heard of a nice characterization of compactness but I have never seen a written source of it, so I'm starting to doubt it. I'm looking for a reference, or counterexample, for the ...
Guillermo Mantilla's user avatar

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