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4 votes
1 answer
198 views

Does hereditary and connected imply that the underlying ring $k$ of a $k$-algebra is a field?

All rings are assumed to be associative and have a 1. Let $k$ be a commutative artininan ring and $R$ a finitely generated $k$-algebra. Is it true that if $R$ is connected and hereditary, then $k$ is ...
kevkev1695's user avatar
11 votes
1 answer
159 views

Are all indecomposable $\mathbb{Z}_+$-modules over the character ring of a group, character rings of a subgroup?

A $\mathbb Z_+$-algebra is an algebra $A$ over $\mathbb C$ with given basis $\{v_i\}$ such that $$v_iv_j=\sum_k n_{ijk}v_k,\hspace{10mm}n_{ijk}\in\mathbb Z_{\geq0}.$$ An example of such an object is ...
shin chan's user avatar
  • 301
7 votes
1 answer
284 views

Does the choice of the algebraically closed field of characteristic $p$ have influence on the module category?

Let $G$ be a finite group and $p$ be a prime number dividing $|G|$. Let $k$ be the algebraic closure of $\mathbb{F}_p$. Let $K$ be another algebraically closed field of characteristic $p$ which is not ...
LSt's user avatar
  • 237
3 votes
1 answer
171 views

Modules with special properties

$\DeclareMathOperator\End{End}$Let $A$ be a finite dimensional algebra and $M$ an indecomposable (right) module with the property that every nilpotent element of $\End_A(M)$ annihilates the socle $\...
Mare's user avatar
  • 26.5k
5 votes
1 answer
713 views

Absolutely irreducible representation and splitting field

Let $A$ be a finite-dimensional algebra over a field $F$. A representation $M$ of $A$ is called absolutely irreducible if $M\otimes_FE$ is irreducible as a representation of $A\otimes_FE$ for all ...
Hebe's user avatar
  • 951
3 votes
1 answer
270 views

Thin representations for quiver algebras

A representation $M$ of a quiver is called thin when $M$ has a dimension vector consisting only of 0 or 1 entries. When $A=kQ$ is a path algebra for a tree $Q$, then there is the nice result that ...
Mare's user avatar
  • 26.5k
2 votes
1 answer
197 views

Top and bottom composition factors of $M$ are isomorphic

Let $k$ be a field and $N$ a finite group. Let $M$ be a projective indecomposable $kN$-module. Since the algebra $kN$ is symmetric, it follows that the top and bottom composition factors of $M$ are ...
user666's user avatar
  • 51
2 votes
1 answer
160 views

MAGMA-question concerning the transformation of a $kG$ -module $M$ into a right ideal of the group algebra

Let $G$ be a finite group and $k$ be a finite field of characteristic $p>0$ such that $p\mid |G|$. Let $M$ be a $kG$-module which has an embedding $M\hookrightarrow kG^{reg}$ into the regular $kG$-...
Bernhard Boehmler's user avatar
4 votes
1 answer
159 views

Effect of extending scalars on maps of modules

Let $k$ be a field and $R$ be a $k$-algebra. Let $M$ and $N$ be left $R$-modules. Finally, let $\ell$ be a field extension of $k$. We thus have an $\ell$-algebra $\ell \otimes R$, and both $\ell \...
Laura's user avatar
  • 43
4 votes
1 answer
135 views

Global splitting field for algebras

Let $A$ be a finite dimensional algebra. A field $K$ is a splitting field for an indecomposable $A$-module $M$ in case the local algebra $End_A(M)/(rad(End_A(M))$ is 1-dimensional. $K$ is called a ...
Mare's user avatar
  • 26.5k
3 votes
1 answer
244 views

Left module which cannot be made into a bimodule?

Let $A$ be a noncommutative unital algebra, defined over $\mathbb{C}$ say. What is an example of a left $A$-module $M$ that does not admit a right $A$-module structure giving $M$ the structure of a ...
Fofi Konstantopoulou's user avatar
2 votes
1 answer
143 views

A weak Schur's lemma for non-semisimple finite dimensional algebras

Let $B \subseteq C$ be an inclusion of finite dimensional (associative) algebras over a field $k$. Assume that $C$ is a free $B$-module. Let $\bigoplus_i U_i$ be a decomposition of $B$ into ...
Sebastien Palcoux's user avatar
5 votes
1 answer
192 views

Given a representation-infinite algebra, when is every AR component infinite?

Let $A$ be a finite dimensional algebra over an algebraically closed field $K$. The Auslander-Reiten quiver $\Gamma_A$ of $A$ is a means of presenting the category of finitely generated right $A$-...
Iteraf's user avatar
  • 482
6 votes
3 answers
446 views

Is the category of symmetric bimodules over a commutative ring closed under extensions?

Let $A$ be a commutative ring, and consider the category of bimodules over $A$. An $A$-bimodule $M$ is called symmetric if $a\cdot m = m \cdot a$ for all $a \in A$, $m \in M$. Is the category of ...
Symmetric's user avatar
1 vote
1 answer
149 views

Finding modules to check for finite global dimension

Given a finite dimensional algebra $A$ and a generator-cogenerator $M$ and let $B:=End_A(M)$. $B$ has finite global dimension iff every $A$-module has finite $add(M)$-resolution dimension, which is ...
Mare's user avatar
  • 26.5k
6 votes
1 answer
302 views

Endomorphism ring of bimodules

Given an algebra $A$ with a right $A$-module $M$ with $End_A(M) \cong A$. Then we can view $M$ as a natural $A$-bimodule. When is $M$ as a bimodule indecomposable and what is its endomorphism ring as ...
Mare's user avatar
  • 26.5k
4 votes
1 answer
382 views

Non-existence of projective covers

I didn't get the argument of Example 7.3.11, page 123, from the representation theory book of Peter Webb, available also online at: http://www-users.math.umn.edu/~webb/RepBook/RepBookLatex.pdf In ...
user103474's user avatar
2 votes
1 answer
263 views

Nonnegatively graded algebra $A$ finitely generated as $k$-algebra iff $A_0$ finitely generated, $A_{>0}$ finitely generated as $A$-module?

This is related to my question here. My question is as follows. How do I see that a nonnegatively graded algebra $A$ is finitely generated as a $k$-algebra if and only if $A_0$ is finitely generated ...
Jakob W's user avatar
  • 349
5 votes
1 answer
394 views

Classification of indecomposable modules in tame hereditary algebras

An algebra $A$ is said to be tame if the isomorphism classes of indecomposable $A$-modules in each dimension occur in a finite number of 1-parameter families. $A$ is said to be of finite ...
Iteraf's user avatar
  • 482
1 vote
1 answer
271 views

Rank of a locally free $\mathbb Z[G]$-module

This is a basic question. Let $G$ be a finite group, $M$ a finitely generated $\mathbb Z[G]$-module so that the $\mathbb Z_p[G]$-module $M_p$ is free for all prime numbers $p$, i.e. is locally free. ...
eddie's user avatar
  • 255
7 votes
1 answer
456 views

Hopfian modules

My question is slightly motivated by basic results in linear algebra, for example, that if $F$ is a field then a surjective linear map $F^n \rightarrow F^n$ is injective. More generally, any ...
Mark Wildon's user avatar
  • 11.2k
9 votes
1 answer
473 views

Why do we want $p$-permutation modules in splendid equivalences?

First Rickard (in Splendid Equivalences: Derived Categories and Permutation Modules ) and then Rouquier (Block theory via stable and Rickard equivalences, Appendix A.1) define splendid equivalences ...
AnalysisStudent0414's user avatar
8 votes
1 answer
387 views

Jordan-Hölder-like statements for modules with $\Delta$-filtrations over a quasihereditary algebra

Definitions Let $A$ be an Artin algebra (for instance, take $A$ to be a finite dimensional algebra over some field) and label the isomorphism classes of simple $A$-modules by the elements of a ...
3 A's's user avatar
  • 425
2 votes
1 answer
404 views

Example of a Frobenius algebra that is not projective over a Frobenius subalgebra

I'd like to know an example of a Frobenius algebra $A$, with a subalgebra $B$ that is itself a Frobenius algebra, such that $A$ is not projective as a left $B$-module. I don't require any ...
Alistair Savage's user avatar
18 votes
2 answers
1k views

Does base extension reflect the property of being isomorphic?

Let L/K be a (separable?) field extension, let A be a finite dimensional algebra over K, and let M and N be two A-modules. Let $A' = L \otimes_K A$ be the algebra given by extension of scalars, and ...
Noah Snyder's user avatar
  • 28.1k
7 votes
1 answer
262 views

Description of modules over self-injective algebras of finite representation type

Is there any description of indecomposable modules and irreducible morphisms over self-injective algebras of finite representation type? I am interested mainly in such a description for nonstandard ...
Yury's user avatar
  • 71
28 votes
4 answers
5k views

When are modules and representations not the same thing?

I've been trying for a while to get a real concrete handle on the relationship between representations and modules. To frame the question, I'll put here the standard situation I have in mind: A ring $...
Aleks Kissinger's user avatar