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Quadratic algebras and Koszul algebras

Let $A$ be a quadratic algebra and $B$ the Ext-algebra of $A$. In case $A$ is a Koszul algebra, we should have that the global dimension of $A$ plus one is equal to the Loewy length of $B$ (is there a ...
Mare's user avatar
  • 26.5k
12 votes
1 answer
564 views

Representations of degenerate Clifford algebras

Given a real finite-dimensional vector space $V$ with a symmetric bilinear form $b$, we define the Clifford algebra $Cl(V,b)$ as the quotient of the tensor algebra $\bigotimes V$ by the two sided ...
José Figueroa-O'Farrill's user avatar
3 votes
0 answers
49 views

$c$-matrix reduction in hereditary algebras

Let $k$ be an algebraically closed field, $Q$ be a finite connected quiver and $Q'$ a subquiver of $Q$. Let $C$ be the $c$-matrix of a chamber of the scattering diagram/semi-invariant picture of $kQ$. ...
Ying Zhou's user avatar
  • 417
3 votes
1 answer
175 views

If the sum of a right (principal) ideal with a left one contains an invertible element and the product is zero then do they contain idempotents?

I am trying to solve a problem on additive categories, that gives the following question on (non-commutative unital associative) rings: if for elements $a$ and $b$ of a ring $R$ we have $ab=0$ and $a+...
Mikhail Bondarko's user avatar
3 votes
0 answers
71 views

$\Omega^2(S) \cong \tau(S)$ for simple modules

Let $A$ be an Artin algebra with $\Omega^2(S) \cong \tau(S)$ for each simple module $S$. Is $A$ a quasi-Frobenius (=selfinjective) algebra? Here $\tau$ denotes the Auslander-Reiten translate, which is ...
Mare's user avatar
  • 26.5k
1 vote
0 answers
146 views

Characterisation of projective modules over tensor products of fields

Let $k$ be a field and $L_1$ and $L_2$ finite field extensions of $k$. Let $A:=L_1 \otimes_k L_2$ as an algebra. Question: Given a finitely generated $A$-module $M$, do we have that $M$ is ...
Mare's user avatar
  • 26.5k
4 votes
2 answers
337 views

When is $\Omega^1$ an equivalence?

Let $C$ be an abelian category with enough projectives and $\underline{C}$ the stable category of $C$ that is obtained by factoring out projective modules. When is the functor $\Omega^1 : \underline{...
Mare's user avatar
  • 26.5k
9 votes
0 answers
371 views

Duality between coalgebras and (pseudocompact) algebras - uniqueness

The following result is well-known. It can for example be found in [Iovanov: The representation theory of profinite algebras, Theorem 1.0.2]. For definitions, see below. Let $k$ be a field. The ...
Julian Kuelshammer's user avatar
2 votes
0 answers
201 views

Homological conjecture for finite dimensional algebras

In the theory of finite dimensional algebras there are many homological conjectures. When working over an algebraically closed field it is well known that any such algebra is Morita equivalent to a ...
Mare's user avatar
  • 26.5k
3 votes
0 answers
97 views

Infinite-dimensional wild commutative algebras with non-trivial units

Let $A$ be an arbitrary (not necessarily finite-dimensional) associative algebra over an algebraically closed field $K$, and let $\mathrm{fin\,}A$ denote the category of finite-dimensional $A$-modules....
Iteraf's user avatar
  • 482
4 votes
1 answer
159 views

Question on $n$-regular modules

Let $A$ be finite dimensional connected algebra. A simple module $S$ is called $n$-regular in case $pd(S)=n$, $Ext_A^i(S,A)=0$ for $i=0,1,...,n-1$ and $Ext_A^n(S,A)$ being a simple $A$-left module. ...
Mare's user avatar
  • 26.5k
5 votes
1 answer
353 views

Existence of non-trivial reflexive modules

Recall that a module $M$ over a ring $R$ is reflexive in case the natural evaluation map $f_M:M \rightarrow M^{**}$ (where $M^{*}=Hom_R(M,R)$) is an isomorphism, where $f_M(m)=g$ with $g(h)=h(m)$, ...
Mare's user avatar
  • 26.5k
3 votes
1 answer
211 views

Coinduced modules in the BGG category $\mathcal O$ over complex semisimple Lie algebras

For a given finite-dimensional complex semisimple Lie algebera $\mathfrak g$, we fix Cartan $\mathfrak h$ and Borel subalgebras $\mathfrak b$, then we have the BGG category $\mathcal O$. As usual, we ...
GuNa's user avatar
  • 55
38 votes
0 answers
1k views

Groups whose complex irreducible representations are finite dimensional

By a complex irreducible representation of a group $G$, I mean a simple $\mathbb CG$-module. So my representations need not be unitary and we are working in the purely algebraic setting. It is easy ...
Benjamin Steinberg's user avatar
5 votes
2 answers
332 views

Questions on weakly symmetric algebras

A finite dimensional algebra $A$ over a field $K$ is called weakly symmetric in case $soc(P)=top(P)$ for every indecomposable projective module $P$ and it is called symmetric in case $D(A) \cong A$ as ...
Mare's user avatar
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2 votes
0 answers
74 views

Units in the (stable) center of a Frobenius algebra [duplicate]

Let $A$ be a Frobenius algebra with center $Z(A)$ and $I\subset Z(A)$ the ideal of elements in the image of some $A$-bimodule map $A\rightarrow A\otimes A\rightarrow A$, where the second map is ...
Fernando Muro's user avatar
2 votes
1 answer
203 views

$Ext_A^1(J,J)$ for the Jacobson radical $J$ of an algebra $A$

Let algebras be finite dimensional over a field $K$ and let $J$ denote the Jacobson radical (this is the intersection of all maximal right ideals) of an algebra. Being hereditary means that the ...
Mare's user avatar
  • 26.5k
4 votes
0 answers
218 views

Conjugacy class representatives for the automorphism group of a finite abelian group

Given a finite abelian group $A$, I'd like a list of conjugacy class representatives for its automorphism group ${\rm Aut}(A)$. In fact, it's not important that I have exactly one representative from ...
Matt Ollis's user avatar
7 votes
1 answer
239 views

Is being a Frobenius algebra a rare condition for local algebras?

Let $U_{r,l,q}$ be the set of finite dimensional local algebras $A$ over a finite field with $q$ elements such that $J/J^2$ is $r$-dimensional for a number $r \geq 2$ and such that $J^l=0$ for the ...
Mare's user avatar
  • 26.5k
5 votes
1 answer
192 views

Given a representation-infinite algebra, when is every AR component infinite?

Let $A$ be a finite dimensional algebra over an algebraically closed field $K$. The Auslander-Reiten quiver $\Gamma_A$ of $A$ is a means of presenting the category of finitely generated right $A$-...
Iteraf's user avatar
  • 482
5 votes
1 answer
271 views

Do all finite-dimensional division algebras appear as Wedderburn factors of rational group rings?

Suppose that $D$ is a division algebra that is finite-dimensional over $\Bbb Q$, does there exist a finite group $G$ such that one of the factors in the Wedderburn decomposition of $\Bbb Q[G]$ is a ...
Lukas Heger's user avatar
1 vote
0 answers
80 views

When is a stable endomorphism ring selfinjective?

Let $A$ be a local symmetric finite dimensional algebra and $M$ an $A$-module with at least two non-isomorphic indecomposable non-projective summands. In case $\Omega^1(M) \cong M$ in the stable ...
Mare's user avatar
  • 26.5k
2 votes
0 answers
84 views

Super global dimension

Let $R$ be a ring of finite global dimension. Define the small super global dimension as $sgl(R):= \sup \{ pd(X)+id(X) | X \in mod-R$ and indecomposable $\}$. Here $id(X)$ stands for the injective ...
Mare's user avatar
  • 26.5k
1 vote
0 answers
64 views

Questions on holonomic modules

An Auslander-Gorenstein ring is a noetherian ring R that has finite left and right selfinjective dimension and such that $fd(I_i) \leq i$ for all $i \geq 0$ for an injective coresolution of the ...
Mare's user avatar
  • 26.5k
3 votes
0 answers
169 views

Hochschild homology and Chern character quiver with potential

I am a beginner in quiver theory so this question might not be suitable for mathoverflow. Let $(Q,W)$ be a quiver with potential and let $\Gamma$ be the Ginzburg DG-algebra associated to $(Q,W)$. Is ...
Libli's user avatar
  • 7,300
3 votes
0 answers
54 views

Ext for simple modules in selfinjective algebras

Let $A$ be a finite dimensional symmetric algebra (given by a connected quiver and non-semisimple) and $S$ a simple $A$-module. (I am more interested in symmetric algebras, but selfinjective examples ...
Mare's user avatar
  • 26.5k
6 votes
3 answers
446 views

Is the category of symmetric bimodules over a commutative ring closed under extensions?

Let $A$ be a commutative ring, and consider the category of bimodules over $A$. An $A$-bimodule $M$ is called symmetric if $a\cdot m = m \cdot a$ for all $a \in A$, $m \in M$. Is the category of ...
Symmetric's user avatar
3 votes
0 answers
208 views

A new characterisation of hereditary algebras?

Let $A$ be a quiver algebra with global dimension at most two (or more generally finite global dimension) and $A^e=A^{op} \otimes_K A$ be its enveloping algebra. Guess:Is $A$ hereditary if and only ...
Mare's user avatar
  • 26.5k
1 vote
1 answer
140 views

Is the Cartan permanent odd for finite global dimension?

Define the Cartan permanent of a finite dimensional algebra as the permanent of the Cartan matrix. Is the Cartan permanent of a finite dimensional algebra with finite global dimension always an odd ...
Mare's user avatar
  • 26.5k
5 votes
1 answer
1k views

Periods in the trivial extension algebra of the incidence algebra of the divisor lattice

Definition of $C_L$ for people who like number theory: Let $m$ be a number with prime factorisation $m=p_1^{n_1} ... p_r^{n_r}$ with $n_i>0$. Define $I_m$ to be the incidence algebra of the ...
Mare's user avatar
  • 26.5k
9 votes
0 answers
259 views

Name for rings with $R \cong R^{\mathrm{op}}$

Is there a name for rings that are isomorphic to their opposite ring $R^{\mathrm{op}}$ in the literature? I'm especially interested for the class of Artin algebras.
Mare's user avatar
  • 26.5k
1 vote
0 answers
48 views

Is simreflexive left-right symmetric?

Call an Artin algebra (we can assume that it is basic) $A$ simreflexive in case every simple A-module is reflexive. Is A simreflexive iff the opposite algebra $A^{op}$ is simreflexive? Or equivalently ...
Mare's user avatar
  • 26.5k
0 votes
0 answers
66 views

Tameness of the trivial extension of a finite dimensional algebra

The trivial extension T(A) of a (finite dimensional) algebra A is representation-finite if and only if the algebra A is iterated tilted of Dynkin type. Questions: Is there a similar classification ...
Mare's user avatar
  • 26.5k
2 votes
0 answers
127 views

Multiplicative subgroups of $GL(V)$ which are almost additively closed

Edit: According to comments of YCor and Vincent, I revise the question.I appreciate their comments: Let $G$ be a group. We say that $G$ is a special group if it is isomorphic to a subgroup $H$ ...
Ali Taghavi's user avatar
6 votes
0 answers
79 views

Canonical forms for representations of tame algebras

Recently I have been studying the representation type of algebras (tame-wild dichotomy). A question that I feel is probably well known but that I cannot answer is the following: Can I define tame ...
J.J. Holton's user avatar
3 votes
0 answers
427 views

When is the stable category abelian

For which Artin algebras $A$ is the stable module (that is the module category modulo projectives) category of finitely generated modules abelian? If you like you may take rings that are not Artin ...
Mare's user avatar
  • 26.5k
4 votes
0 answers
228 views

Question on $n$-torsionless modules

Let $A$ be a finite dimensional algebra. Recall that a module $M$ is called $n$-torsionfree in case $Ext_A^i(D(A),\tau(M))=0$ for all $i=1,...,n$ when $\tau$ denotes the Auslander-Reiten translate. ...
Mare's user avatar
  • 26.5k
7 votes
1 answer
730 views

Where is my mistake in calculating duals?

I'm confused and probably have a thinking error. Exercise 6 on page 420 of Lam's Lectures on Modules and Rings says essentially: Let $R$ be a ring and $C$ a cyclic right $R$-module: $C=R/A$ with ...
Mare's user avatar
  • 26.5k
2 votes
0 answers
75 views

Double dual of the simple module in local algebras

Let $A$ be a local Artin algebra that is not selfinjective with simple module $S$. Questions: Can $S^{**}$ be indecomposable? $S^{**}$ be somehow generally be described (for example as a ...
Mare's user avatar
  • 26.5k
1 vote
1 answer
174 views

Reference for a result of Auslander about the global dimension

One of Auslanders famous theorems is that he proved that the global dimension of a semiprimary ring is equal to the maximum of the projective dimensions of the simple modules of the ring. This result ...
Mare's user avatar
  • 26.5k
6 votes
1 answer
290 views

(Non-)formality for ADE preprojective algebras

Given a quiver $Q$, I can associate to $Q$ a certain 2-Calabi-Yau (dg-)algebra $\Gamma_Q$ by a 2-dimensional version of the "Ginzburg dga" construction: i.e., start by doubling $Q$, and then impose ...
Ben G's user avatar
  • 423
5 votes
2 answers
226 views

Algebras with all simples reflexive

Let $A$ be a ring. Recall that a module $M$ is called reflexive in case the canonical evaluation map $f_M : M \rightarrow M^{**}$ is an isomorphism. Here $(-)^{*}$ denotes the functor $Hom_A(-,A)$. In ...
Mare's user avatar
  • 26.5k
2 votes
1 answer
98 views

Reflexive modules up to multiplicity

Call an indecomposable module $M$ over a ring $A$ (restrict to finite dimensional algebras if you like or if it helps) $n$-almost reflexive in case $M^{**} \cong nM$, when $(-)^{*}=Hom_A(-,A)$ and $nM$...
Mare's user avatar
  • 26.5k
3 votes
0 answers
169 views

Characterisation of reflexive modules for general rings

A module $M$ over a general ring A is called reflexive in case the canonical evaluation map $e_M: M \rightarrow M^{**}$ is an isomorphism, when $(-)^{*}:=Hom_A(-,A)$. Is $M$ reflexive iff $M \cong M^{*...
Mare's user avatar
  • 26.5k
4 votes
1 answer
615 views

Characterisation of reflexive modules

Let $A$ be a semiperfect noetherian ring. A module $M$ is called reflexive in case the canonical map $f_M: M^{**} \cong M$ is an isomorphism, when $(-)^{*}:=Hom_A(-,A)$. This is equivalent to say that ...
Mare's user avatar
  • 26.5k
3 votes
1 answer
319 views

Functions on a field representable by Hahn series?

It is well known (see here for example) that a function over $\mathbb{R}$ is representable by a power series iff its analytic continuation to $\mathbb{C}$ is holomorphic on some open subset of $\...
Alec Rhea's user avatar
  • 10.1k
1 vote
0 answers
155 views

Deduce Schur-Zassenhaus theorem from Wedderburn-Malcev theorem

Is it possible to derive Schur-Zassenhaus theorem from Wedderburn-Malcev theorem? For the existance part I have the following idea: Let $G$ be a finite Group and $N$ an abelian Hall $p$-subgroup. Let $...
Sven Wirsing's user avatar
5 votes
2 answers
360 views

Injective dimension of the Jacobson radical and global dimension

Given a finite dimensional algebra $A$ with Jacobson radical $J$. Is the global dimension of $A$ equal to the injective dimension of $J$? Together with Xiao-Wu Chen and Srikanth Iyengar we proved this ...
Mare's user avatar
  • 26.5k
1 vote
1 answer
149 views

Finding modules to check for finite global dimension

Given a finite dimensional algebra $A$ and a generator-cogenerator $M$ and let $B:=End_A(M)$. $B$ has finite global dimension iff every $A$-module has finite $add(M)$-resolution dimension, which is ...
Mare's user avatar
  • 26.5k
13 votes
0 answers
355 views

Analog of Haar element in an algebra

In a Hopf algebra $H $ (over some field $ k $), there is the notion of a Haar element $ h \in H$. This is an element of the algebra which has the property that if $ V $ is a representation of $ H $, ...
Joel Kamnitzer's user avatar

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