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Finitistic dimension conjecture for quadratic algebras

The finitistic dimension of a finite dimensional algebra is defined as the supremum of all projective dimensions of modules having finite projective dimension. The finitistic dimension conjecture says ...
Mare's user avatar
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4 votes
0 answers
88 views

Minimal injective coresolution in the stable Auslander algebra

Let $A$ be a finite dimensional (connected) quiver algebra. Let $T(A)$ denote the full subcategory of coherent functors from $mod-A$ to $Ab$ that vanish on projective objects. $T(A)$ is equivalent to ...
Mare's user avatar
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5 votes
0 answers
140 views

Open problems about Morita and derived invariants

Are there properties of rings of which one does not know whether they are Morita or derived invariances? For a recent such example for Morita invariance, see https://www.sciencedirect.com/science/...
Mare's user avatar
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3 votes
0 answers
48 views

Endomorphism ring of a generator-cogenerator over acyclic algebras

Let $A$ be an acyclic quiver algebra, $M$ a generator-cogenerator and $B=End_A(M)$. Questions: Does $B$ have finite global dimension? Does $B$ have finite global dimension in case $M=A \oplus D(A)$? ...
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4 votes
0 answers
58 views

Interpretation of stable Hom in Nakayama algebras

Let $A$ be a Nakayama algebra with Kupisch series $[c_0,c_1,...,c_{n-1}]$ and Jacobson radical $J$ (given by quiver and relations). As is well known every indecomposable $A$-module is of the form $e_i ...
Mare's user avatar
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9 votes
0 answers
123 views

Cartan determinant of stable categories

Let $A$ be a finite dimensional algebra with finitely many indecomposable non-projective modules $M_1, M_2,...,M_n$. Let $a_{i,j}:=\dim(\underline{Hom_A}(M_j,M_i))$ (the dimension of the stable Homs ...
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  • 26.5k
5 votes
0 answers
91 views

Bound on the sum of projective and injective dimension

Recall that a finite dimensional algebra is called piecewise hereditary in case it is derived equivalent to an abelian hereditary category. In proposition 1.2. of https://link.springer.com/article/10....
Mare's user avatar
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5 votes
1 answer
186 views

(Stable) Auslander algebras in a specific example

Let $k$ be a field and $Q$ be the quiver with two vertices 1 and 2 and three arrows: $a$ from 2 to 1, $b$ from 2 to 1 and $c$ from 2 to 2. Let $I_1=\langle ab-c^2,ba\rangle$ and $I_2=\langle ab-c^2,c^...
Mare's user avatar
  • 26.5k
2 votes
0 answers
60 views

$\Omega$-periodic modules in selfinjective algebras

Given a representation infinite (connected) selfinjective algebra $A$ with an indecomposable $\Omega$-periodic module $M$. Does $A$ then have infinitely many indecomposable $\Omega$-periodic ...
Mare's user avatar
  • 26.5k
2 votes
0 answers
65 views

Constructing stable equivalences for finite dimensional algebras

Given a finite dimensional (non-selfinjective) algebra $A$. Is there a method (for example using QPA) to construct algebras stable equivalent to $A$? Such a thing is easily possible for derived ...
Mare's user avatar
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4 votes
0 answers
85 views

Deciding whether two algebras are derived equivalent

Given two finite dimensional quiver algebras $A$ and $B$ (over a nice field in case that helps, for example a finite field). Question: Can an there be a finite algorithm that decides whether $A$ ...
Mare's user avatar
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4 votes
0 answers
43 views

Cartan determinants of minimal Auslander-Gorenstein algebras

Iyama and Solberg introduced minimal Auslander-Gorenstein algebras as algebras having finite dominant dimension ($\geq 2$) equal to the Goreinstein dimension in https://www.sciencedirect.com/science/...
Mare's user avatar
  • 26.5k
5 votes
0 answers
125 views

Stable equivalence and stable Auslander algebras

Let $A$ be a representation-finite finite dimensional quiver algebra and $M$ the basic direct sum of all indecomposable $A$-modules. Recall that the Auslander algebra of $A$ is $End_A(M)$ and the ...
Mare's user avatar
  • 26.5k
3 votes
0 answers
106 views

Bounds for the finitistic dimension

The finitistic dimension of an algebra is defined as the supremum of all projective dimensions of modules having finite projective dimension. For finite dimensional algebras $A$ with radical cube ...
Mare's user avatar
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4 votes
4 answers
596 views

Homology of solvable (nilpotent) Lie algebras

Let $\mathfrak{g}$ be a solvable Lie algebra over $\mathbb{C}$ and $\lambda\in(\mathfrak{g}/[\mathfrak{g},\mathfrak{g}])^*$ be a character of $\mathfrak{g}$. I'm interested in calculating homology for ...
Boris Bilich's user avatar
4 votes
0 answers
71 views

Koszul and quadratic algebras with Gorenstein dimension 2

In proposition 2.19. of http://inmabb.criba.edu.ar/revuma/pdf/v48n2/v48n2a05.pdf it was mentioned that a finite dimensional algebra of global dimension 2 is quadratic if and only if it is Koszul. ...
Mare's user avatar
  • 26.5k
3 votes
0 answers
61 views

Number of algebras stably equivalent to a given algebra

For $n \geq 2$ let $B_n$ be the algebra of upper triangular matrices over a field $K$. Recall that two algebras are said to be stably equivalent in case their module categories modulo projectives are ...
Mare's user avatar
  • 26.5k
3 votes
0 answers
96 views

When is the category of complexes of finite type?

For a ring $R$ define the category of complexes of length $n \geq 2$ as the category $C_n(R)$ with objects the complexes of the form $0 \rightarrow X_n \rightarrow \cdots X_1 \rightarrow 0$ with the ...
Mare's user avatar
  • 26.5k
3 votes
1 answer
149 views

Bounds for the number of edges in an Alperin diagram

If $A$ is an algebra over a field $k$ and $M$ is a finite-dimensional $A$-module, then Alperin showed in a paper [Diagrams for modules, JPAA, 1980] how to associate a diagram to $M$ with the vertices ...
David Stewart's user avatar
7 votes
1 answer
462 views

On a problem for determinants associated to Cartan matrices of certain algebras

This is a continuation of Classification of algebras of finite global dimension via determinants of certain 0-1-matrices but this time with a concrete conjecture and using the simplification suggested ...
Mare's user avatar
  • 26.5k
2 votes
0 answers
69 views

Do the values of the global dimension constitute an interval?

Let $Q$ be a fixed finite connected quiver and $k$ a fixed field. Set $Z_Q:= \{ gldim(kQ/I) < \infty | I $ an admissible ideal $\}$. Question: Is $Z_Q$ an intervall? This is true for example in ...
Mare's user avatar
  • 26.5k
11 votes
2 answers
558 views

Classification of algebras of finite global dimension via determinants of certain 0-1-matrices

I restrict to the elementary problem that is equivalent to give a classification when Morita-Nakayama algebras have finite global dimension (see the end of this post for some background). A Morita-...
Mare's user avatar
  • 26.5k
6 votes
2 answers
269 views

Derived invariance of the Cartan determinant

The Cartan matrix $C$ of a finite quiver algebra $A$ with points $e_i$ is defined as the matrix having entries $c_{i,j}=\dim(e_i A e_j)$. The Cartan determinant is defined as the determinant of the ...
Mare's user avatar
  • 26.5k
7 votes
1 answer
370 views

Gorenstein symmetric conjecture for arbitrary rings

The Gorenstein symmetric conjecture states that for Artin algebras $A$ one has the the regular module has finite injective dimension as a right module if and only if it has finite injective dimension ...
Mare's user avatar
  • 26.5k
4 votes
0 answers
66 views

Periodic modules in Frobenius algebras

Let $A$ be a finite dimensional Frobenius algebra and assume there exists an indecomposable periodic module $M$, that is $\Omega^n(M) \cong M$ for some $n$. Question: Does this imply that there is ...
Mare's user avatar
  • 26.5k
1 vote
0 answers
57 views

Modules with arbitrary large complexity

Let $A$ be a finite dimensional algebra with a module $M$ who has minimal injective coresolution $(I_i)$. Define the complexity $cx(M)$ as $cx(M):= \inf \{ t \geq 0 | \dim(I_i) \leq a i^{t-1}$ for all ...
Mare's user avatar
  • 26.5k
2 votes
0 answers
29 views

Complexity of the regular module

Let $A$ be a finite dimensional algebra with a module $M$ who has minimal injective coresolution $(I_i)$. Define the complexity $cx(M)$ as $cx(M):= \inf \{ t \geq 0 | \dim(I_i) \leq a i^{t-1}$ for all ...
Mare's user avatar
  • 26.5k
3 votes
0 answers
134 views

Proving that the exterior algebra is symmetric via the polynomial ring

Recall that a finite dimensional algebra $A$ over a field $K$ is called Frobenius in case $A \cong D(A)$ as right modules, and it is called symmetric in case $A \cong D(A)$ as bimodules (where $D=...
Mare's user avatar
  • 26.5k
3 votes
0 answers
156 views

Weak generators of the right-bounded derived category of a finite-dimensional algebra

The setup: Let $A$ be a finite-dimensional $k$-algebra over some field $k$. Let $\mathcal{B} = Hot^-(Proj \, A)$ denote the homotopy category of cochain complexes of (possibly infinitely generated) ...
Wayne's user avatar
  • 61
12 votes
1 answer
922 views

Does this algebra have finite global dimension ? (Human vs computer)

Usually computers can calculate the global dimension of a finite dimensional quiver algebra much faster than humans. But in this case a high end computer (calculating for 3 weeks) was not able to ...
Mare's user avatar
  • 26.5k
4 votes
1 answer
303 views

Algebras derived equivalent to quasi-hereditary algebras

Let an algebra always be finite dimensional over a field and connected. It is well known that a quasi-hereditary algebra with $n$ simple modules has global dimension at most $2n-2$. Questions: 1. ...
Mare's user avatar
  • 26.5k
4 votes
0 answers
84 views

Finitistic dimension via a bimodule

Let $A$ be a connected finite dimensional basic algebra. Question: Is there an indecomposable $A$-bimodule $W$ such that the finitistic dimension of $A$ is equal to the right projective dimension ...
Mare's user avatar
  • 26.5k
13 votes
1 answer
745 views

Combinatorial inequality for dominant dimension

In the following I present a conjecture on Nakayama algebras that I have for nearly 2 years now. Since I was not able to solve it and it can be stated purely combinatorically, I thought it might be ...
Mare's user avatar
  • 26.5k
3 votes
0 answers
67 views

Upper bound for embedding of submodules of projective modules

Assume we have a finite dimensional algebra $A$ with the following property: Every indecomposable submodule of a projective module embedds into $A^n$ for a fixed $n$. Is there a good method to ...
Mare's user avatar
  • 26.5k
4 votes
2 answers
453 views

Global dimension of the tensor algebra

Let $R$ be a semisimple ring with a non-zero $R$-bimodule V. Let $T_R(V):= \bigoplus\limits_{k=0}^{\infty}{V^{\otimes_k}}$ be the tensor algebra of $V$. Question 1: Is there a simple proof that $...
Mare's user avatar
  • 26.5k
4 votes
1 answer
463 views

Global dimension of a graded algebra

Let $A= \bigoplus\limits_{n=0}^{\infty}{A_n}$ be an $\mathbb{N}$-graded algebra with semisimple $A_0$. Question: Do we have that the global dimension of $A$ is equal to $\sup \{i \geq 0 | Ext_A^i(...
Mare's user avatar
  • 26.5k
4 votes
1 answer
683 views

Quadratic algebras and Koszul algebras

Let $A$ be a quadratic algebra and $B$ the Ext-algebra of $A$. In case $A$ is a Koszul algebra, we should have that the global dimension of $A$ plus one is equal to the Loewy length of $B$ (is there a ...
Mare's user avatar
  • 26.5k
2 votes
0 answers
83 views

Length 2 modules over finite dimensional algebras

Given a finite dimensional algebra $A$ over an infinite field and two simple modules $S,T$. Question 1: Is there a useful (homological/computational) crtierion to decide when there are infinitely ...
Mare's user avatar
  • 26.5k
3 votes
1 answer
188 views

Question on $\operatorname{Ext}$ in a local Frobenius algebra

Let $A$ be a finite dimensional local Frobenius algebra with simple module $k$ and an indecomposable non-projective module $M$ (that is also finite dimensional). Question: Is there an example of ...
Mare's user avatar
  • 26.5k
2 votes
0 answers
164 views

On a conjecture about tilting modules

There is the following conjecture on tilting modules (see also History of an open problem on partial tilting modules): Given a partial tilting module $T$ over a finite dimensional algebra $A$ (that is ...
Mare's user avatar
  • 26.5k
6 votes
1 answer
689 views

Tensor product of bimodules

Im not sure whether this question is appropriate for MO, but I do not have much experience with bimodules (or I forgot many things). Let $A$ be a finite dimensional (connected) algebra over a field $...
Mare's user avatar
  • 26.5k
8 votes
0 answers
140 views

$n$-fold tensor products of $D(A)$ for finite dimensional algebras

Let $A$ be a finite dimensional quiver algebra over a field $K$ and let $D(-):=Hom_K(-,K)$ denote the natural duality (assume algebras are connected). Define $\psi_A:=sup \{ n \geq 1 | D(A)^{\otimes ...
Mare's user avatar
  • 26.5k
1 vote
0 answers
141 views

Question on vanishing Hochschild cohomology

Recall that for an $K$-algebra $A$ with $A^e:=A^{op} \otimes_K A$ the Hochschild cohomology is defined as $HH^n(A,M):=Ext_{A^e}^n(A,M)$. Question: Is there a finite dimensional selfinjective ...
Mare's user avatar
  • 26.5k
1 vote
1 answer
127 views

Gorenstein projective modules of a certain triangular matrix algebra

Let $B$ be a finite dimensional selfinjective algebra over a field $k$ with a finite dimensional non-projective $B$-module $M$ and $$A=\pmatrix{k&M\\0&B}.$$ A module $N$ over an algebra $C$ ...
Mare's user avatar
  • 26.5k
6 votes
1 answer
420 views

Calculating the Ext-algebra with a computer

Given a finite dimensional quiver algebra $A$ over an arbitrary field and a module $M$ of finite injective dimension or finite projective dimension. Let $B$ be the Ext algebra of $M$, that is $B:=\...
Mare's user avatar
  • 26.5k
5 votes
0 answers
105 views

Derived invariant acyclic algebras

Call a connected quiver algebra $A=KQ/I$ (finite quiver Q and admissible ideal I) derived-invariant in case every quiver algebra derived equivalent to $A$ is even isomorphic to $A$. For example local ...
Mare's user avatar
  • 26.5k
3 votes
0 answers
71 views

$\Omega^2(S) \cong \tau(S)$ for simple modules

Let $A$ be an Artin algebra with $\Omega^2(S) \cong \tau(S)$ for each simple module $S$. Is $A$ a quasi-Frobenius (=selfinjective) algebra? Here $\tau$ denotes the Auslander-Reiten translate, which is ...
Mare's user avatar
  • 26.5k
2 votes
0 answers
55 views

$Ext_{A^e}^i(D(A),A)$ for finite dimensional algebras

Let $A$ be a finite dimensional non-semisimple algebra over a field $K$ with enveloping algebra $A^e=A^{op} \otimes_K A$. Let $D(A)=Hom_K(A,K)$. Question: Is there always a positive integer $i>...
Mare's user avatar
  • 26.5k
4 votes
1 answer
179 views

Reference for isomorphism $Ext_A^n(X,Y) \cong Ext_A^1(\Omega^{n-1}(X),Y)$

Let $A$ be a finite dimensional algebra and $X,Y$ indecomposable modules and $n \geq 2$. We know that $Ext_A^n(X,Y) \cong Ext_A^1(\Omega^{n-1}(X),Y)$. Now such an isomorphism should be given by ...
Mare's user avatar
  • 26.5k
9 votes
1 answer
593 views

Hochschild homology with coefficients in a certain bimodule

Let $A$ be a finite-dimensional $k$-algebra and $U$ and $V$ two finite-dimensional projective $A$-modules (maybe neither the finiteness nor projectivity has to play a role, but these requirements are ...
Lukas Woike's user avatar
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