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3 votes
1 answer
244 views

Left module which cannot be made into a bimodule?

Let $A$ be a noncommutative unital algebra, defined over $\mathbb{C}$ say. What is an example of a left $A$-module $M$ that does not admit a right $A$-module structure giving $M$ the structure of a ...
Fofi Konstantopoulou's user avatar
3 votes
2 answers
1k views

Dual of a projective module

Let $R$ be a noncommutative ring with unit, let $P$ be a projective left $R$-module, and denote $^{\vee}\!P := \,_R\mathrm{Hom}(P,R)$. One often sees it written that projectivity implies an ...
Fofi Konstantopoulou's user avatar
3 votes
0 answers
45 views

Magnitude of ADR algebras

Let $A$ be a connected quiver algebra with $n$ simple modules and Jacobson radical $J$ and Loewy length $n+1$ (that is $J^{n+1}=0$ and $n$ is minimal with this property). The ADR-algebra $B_A$ of $A$ ...
Mare's user avatar
  • 26.5k
1 vote
0 answers
30 views

Right approximations for special modules in Frobenius algebras

Let $A$ be a commutative Frobenius algebra (we can assume $A$ is also local) given by quiver and relations. Let $M_i=A/p_iA$ be a module where $p_i$ is a path in Q. Let $N:=A \oplus \bigoplus\limits_{...
Mare's user avatar
  • 26.5k
14 votes
1 answer
1k views

Factorization and vertex algebra cohomology

A chiral algebra on a smooth curve $X$, in the sense of Beilinson-Drinfeld, is a right $D_{X}$-module with a chiral bracket, which is a map $\mathcal{V}^{\boxtimes 2}(\infty\Delta)\rightarrow \Delta_{*...
user avatar
4 votes
1 answer
233 views

Right approximation in certain subcategories

Let $A$ be an Artin algebra and $C$ a subcategory of mod-$A$ that contains all projective modules and is closed under finite direct sums (but not necessarily under direct summands). Let $T:=add(C)$. ...
Mare's user avatar
  • 26.5k
4 votes
0 answers
73 views

Frobenius dimensions of Nakayama algebras

The Frobenius dimension $F(A)$ of an Artin algebra $A$ is given by the dimension of $Hom(D(A),A)$ (see the answer in On nearly Frobenius algebras ). Question 1: Is it true that $F(A) \geq gldim(A)$ ...
Mare's user avatar
  • 26.5k
4 votes
0 answers
192 views

Extended double 2-cocycle conditions: Mathematical structure behind?

Note: For experts, to save your time, you can just read the highlighted texts and Eqs directly. The ordinary group 2-cocycle condition: Let us remind the usual so-called homogeneous group 2-cocycle $...
wonderich's user avatar
  • 10.5k
6 votes
1 answer
339 views

Monoidal categories from the projective modules of a ring

Let $R$ be a not necessarily commutative ring, and denote by $_R\mathrm{lp}_R$ the category of $R$-bimodules, which are finitely generated projective as left modules, with morphism $R$-bimodule maps, ...
Max Schattman's user avatar
2 votes
1 answer
98 views

A weaker version of strongly graded algebras

Let $A = \oplus_{i \in \mathbb{Z}} A_i$ be a graded algebra. We say that it is strongly graded if $A_i.A_j = A_{i+j}$, for all $i,j \in \mathbb{Z}$. Can there be existing a graded algebra such that $$...
Fofi Konstantopoulou's user avatar
4 votes
1 answer
375 views

Invertible bimodules and projectivity

Let $A$ be a noncommutative algebra over a field, say $\mathbb{C}$ or $\mathbb{R}$, and let $L$ be a bimodule over $A$. If $L$ is invertible, that is, if the dual right $A$-module $L^*$ satisfies $$ L^...
Rodrigo Alfonso de la Paz's user avatar
4 votes
1 answer
122 views

Postprojective components of quiver algebras

Let $A=kQ/I$ be a quiver algebra with acyclic quiver $Q$. An indecomposable module $M$ is called postprojective in case $M \cong \tau^{-1}(P)$ for an indecomposble projective module $P$. A component ...
Mare's user avatar
  • 26.5k
10 votes
0 answers
236 views

Is being derived equivalent independent of the field?

Let $Q_1, Q_2$ be (connected) acyclic quivers and $I_1, I_2$ admissible ideals (in which the relations have only coefficients 1 or -1). Let $K$ and $F$ be two fields. Question 1: Is $KQ_1/I_1$ ...
Mare's user avatar
  • 26.5k
6 votes
1 answer
220 views

Derived invariant for Gorenstein algebras?

Let $A$ be a finite dimensional algebra with simple modules $S_i$ and projective indecomposable modules $P_l$ and global dimension $g< \infty$ (and $n$ is the number of simple modules). I noted ...
Mare's user avatar
  • 26.5k
5 votes
1 answer
268 views

Global dimension 2 Nakayama algebras , 321-avoiding permutations and Fibonacci combinatorics

A $n$-LNakayama algebra (for $n \geq 2$) is a list $[c_0,c_1,...,c_{n-1}]$ with $c_{n-1}=1$, $c_i \geq 2$ for $i \neq n-1$ and $c_i -1 \leq c_{i+1}$ for all $i$. They are in bijection with Dyck paths, ...
Mare's user avatar
  • 26.5k
3 votes
0 answers
176 views

Quiver algebras with finite global dimension

Given a fixed connected quiver $Q$. Are there only finitely many quiver algebra $KQ/I$ (I an admissible ideal) up to isomorphism which have finite representation type and finite global dimension?
Mare's user avatar
  • 26.5k
4 votes
0 answers
61 views

Characterisation of algebras with Euler trivial modules

Let $A$ be an algebra of finite global dimension. The Euler form on $A$ for an indecomposable module $M$ is defined as $\psi(M)=\sum\limits_{k=0}^{\infty}{(-1)^k dim( \operatorname{Ext}_A^k(M,M)) }$. ...
Mare's user avatar
  • 26.5k
6 votes
1 answer
368 views

Indecomposable objects in bounded derived category of $\mathbb C[x]/x^2$-mod

We know for any principal ideal domain, objects in the bounded derived category are all formal hence we can classify those objects with finitely generated cohomology using structure theorem for ...
Zhiyu's user avatar
  • 6,622
5 votes
0 answers
113 views

On algebras where all indecomposables have no selfextensions

Let $A$ be a finite dimensional algebra (we can assume it is a connected quiver algebra). Call $A$ extfree in case for every indecomposable $A$-module $M$ we have $\operatorname{Ext}_A^i(M,M)=0$ for ...
Mare's user avatar
  • 26.5k
6 votes
1 answer
205 views

When is the Jacobson radical reflexive?

Let algebras be Artin algebras. It is well known that a an algebra has global dimension at most one if and only if the Jacobson radical is projective. As reflexive is a natural generalisation of ...
Mare's user avatar
  • 26.5k
12 votes
0 answers
402 views

Which abelian categories have homological dimension 1?

In this MSRI lecture Geometry of Quiver Varieties I, Victor Ginzburg describes all abelian categories of homological dimension $1$ as being either a category of representations $\mathrm{Rep}_\mathbf{...
Mike Pierce's user avatar
  • 1,161
2 votes
0 answers
104 views

Tate cohomology for group algebras

Let $A=kG$ be a group algebra with a finite group $G$ and a field $k$. Let $T^i(M,N)= \underline{Hom_A}(\Omega^i(M),N)$ be the $i$-th Tate cohomology group. Note $T^i(M,N)= Ext_A^i(M,N)$ in case $i \...
Mare's user avatar
  • 26.5k
3 votes
0 answers
92 views

On NCR for finite dimensional algebras

Let $A$ be a finite dimensional algebra. A NCR of an algebra $A$ is a faithful module $M$ such that $End_A(M)$ has finite global dimension. Call a faithful module PNCR (=pseudo-NCR) in case $End_A(M)$ ...
Mare's user avatar
  • 26.5k
2 votes
1 answer
307 views

Gaps in the projective dimensions of simple modules

Let $A$ be a finite dimensional algebra with finite global dimension $g$ and $n$ simple modules. Let $d_1<d_2<...<d_r$ be the sequence of projective dimension of simple $A$-modules in ...
Mare's user avatar
  • 26.5k
1 vote
1 answer
132 views

Representation-finite implies planar for quiver algebras?

Let $A=KQ/I$ be a finite dimensional quiver algebra with an admissible ideal $I$. Is it true that in case $A$ is representation-finite, $Q$ has to be planar? In case it is true a possible approach ...
Mare's user avatar
  • 26.5k
1 vote
1 answer
190 views

Ext in Nakayama algebras

Let $A$ be a Nakayama algebra, that is an Artin algebra such that any indecomposable module has a unique composition series. The easiest examples of such algebras are $K[x]/(x^n)$. Question 1: In ...
Mare's user avatar
  • 26.5k
32 votes
3 answers
4k views

Replacing triangulated categories with something better

Gelfand and Manin in their 1988 book on homological algebra write that the non-functoriality of cones means that "something is going wrong in the axioms of a triangulated category. Unfortunately at ...
Hugh Thomas's user avatar
  • 6,292
4 votes
1 answer
233 views

Derived equivalences and Tachikawa conjecture

The first Tachikawa conjecture states that for a finite dimensional algebra $A$, $Ext_A^i(D(A),A)=0$ for all $i \geq 1$ implies that $A$ is selfinjective. Question: In case $A$ has the property that $...
Mare's user avatar
  • 26.5k
6 votes
0 answers
94 views

Injective dimension of the radical series of an algebra

Let $A$ be a (connected) finite dimensional algebra with Jacobson radical $J$. Question: Is the sequence $injdim(J^i)$ for $i=1,2,...,$ monotone decreasing? (one can ask the same question for $...
Mare's user avatar
  • 26.5k
14 votes
2 answers
514 views

Classification of shod Dyck paths

A sequence $[c_0,c_1,...,c_{n-1}]$ with $n \geq 2$ is called a Dyck path in case $c_{n-1}=1$, $c_i \geq 2$ for $i \neq n-1$ and $c_i-1 \leq c_{i+1}$ for each $i$. For example the Dyck paths for $n=4$ ...
Mare's user avatar
  • 26.5k
8 votes
1 answer
193 views

Maximal numbers of summands in middle terms of short exact sequences

Let $A$ be a finite dimensional algebra and $M$ and $N$ indecomposable $A$-modules. Denote by $\xi(M,N)$ the maximal number of indecomposable summands of a modules $X$ such that there is a non-split ...
Mare's user avatar
  • 26.5k
3 votes
1 answer
325 views

Question on $Ext^1$

Given a finite dimensional algebra $A$ with two indecomposable modules $M$ and $N$. Define $H(M,N)$ as the largest number of indecomposable summands of a module $X$ such that there exists a non-split ...
Mare's user avatar
  • 26.5k
3 votes
0 answers
53 views

Inequality for the magnitude of quiver algebras

A conjecture on the global dimension of quiver algebras of finite global dimension states that the global dimension is bounded by the vector space dimension of the algebra. The magnitude of a finite ...
Mare's user avatar
  • 26.5k
2 votes
1 answer
200 views

Projective dimensions of simple modules in acyclic quiver algebras

Given a quiver algebra $A=KQ/I$ with acyclic $Q$. Then $A$ has finite global dimension, lets say $g$. Question: Is there for any $0 \leq i \leq g$ a simple module with projective dimension equal to ...
Mare's user avatar
  • 26.5k
5 votes
0 answers
114 views

Extreme no loop conjecture for group algebras

Let $A=KG$ be a group algebra for a finite group $G$. Let $S$ be a simple $A$-module. The extreme no loop conjecture predicts that $Ext_A^1(S,S) \neq 0$ implies $Ext_A^i(S,S) \neq 0$ for infinitely ...
Mare's user avatar
  • 26.5k
2 votes
1 answer
97 views

When is $N^{*} \otimes_K M$ projective for a local Hopf algebra?

Given a finite dimensional local Hopf algebra $A$ over a field $K$ and two finite dimensional indecomposable modules $N$ and $M$. Is it known when the module $N^{*} \otimes_K M$ is projective? Can ...
Mare's user avatar
  • 26.5k
12 votes
0 answers
516 views

Does $\mathrm{Ext}^1(M,M) \neq 0$ imply $\mathrm{Ext}^2(M,M) \neq 0$?

$\DeclareMathOperator{\Ext}{\operatorname{Ext}}$The first question is about group algebras: Question 1: Let $A=kG$ be a group algebra (with $G$ finite) and let $M$ be an indecomposable $A$-module. ...
Mare's user avatar
  • 26.5k
4 votes
0 answers
69 views

Auslander-Solberg algebras from non-rigid modules

Let $A$ be a Nakayama algebra and $M$ be the direct sum of all indecomposable $A$-modules $N$ with $Ext_A^1(N,N) \neq 0$. The following is suggested by computer experiments with QPA: Question: Is ...
Mare's user avatar
  • 26.5k
2 votes
1 answer
169 views

Combinatorial problem on periodic dyck paths from homological algebra

edit: I added conjecture 2 that looks much more accessible. Here is the elementary combinatorial translation of the problem (read below for the homological background): Let $n \geq 2$. A Nakayama ...
Mare's user avatar
  • 26.5k
2 votes
0 answers
51 views

Selfinjective algebras with loops

Given a selfinjective finite dimensional algebra $A$ with an indecomposable module $M$ with $Ext_A^1(M,M) \neq 0$. Question: Is A derived equivalent to an algebra with a loop in the quiver in ...
Mare's user avatar
  • 26.5k
2 votes
0 answers
53 views

Strong no loop conjecture for uniserial modules

Let $A$ be a an Artin algebra. The strong no loop conjecture states that a simple $A$-module with $Ext_A^1(S,S) \neq 0$ has infinite projective dimension. This conjecture was recently proved for ...
Mare's user avatar
  • 26.5k
2 votes
0 answers
45 views

On monomial and $\Omega^d$-finite algebras

Let $Q$ be a finite quiver and $I$ a monomial admissible ideal of the path algebra $KQ$ for a field $K$. Then an algebra $A=KQ/I$ is called a monomial algebra. It is well known that monomial algebras ...
Mare's user avatar
  • 26.5k
1 vote
0 answers
55 views

$\mathrm{Ext}^1$-ordering on ${}^IW^{\Sigma_\mu}$

Let $\mathfrak{g}$ be a finite dimensional complex semisimple Lie algebra with Cartan subalgebra $\mathfrak{h}$. Let $W$ be the associated Weyl group and let $\Phi$ be its root system. We write $\Phi^+...
James Cheung's user avatar
  • 1,875
4 votes
1 answer
346 views

Verma module and vanishing of extension groups

Let $\mathfrak{g}$ be a finite dimensional complex semisimple Lie algebra with Cartan subalgebra $\mathfrak{h}$. Let $W$ be the associated Weyl group and let $\Phi$ be its root system. We write $\Phi^+...
James Cheung's user avatar
  • 1,875
4 votes
1 answer
149 views

Testing whether a module generates $K_0(\mbox{mod-}A)$

Given a representation-finite (connected) quiver algebra $A$ and a module $M$. Is there a good way to test whether the set $\{ [N] \mid N \in \mathrm{add}(M) \}$ generates $K_0(\mbox{mod-}A)$? Can ...
Mare's user avatar
  • 26.5k
2 votes
0 answers
69 views

Stable m-Calabi Yau property for Frobenius categories

Let $C$ be a Frobenius category. The stable category $\underline{C}$ is called $m$-Calabi Yau in case it is Hom-finite and there is a functorial duality $D \underline{Hom}(X,Y)=\underline{Hom}(Y,\...
Mare's user avatar
  • 26.5k
2 votes
0 answers
73 views

Equivalence from a tilting module

Let $A$ be a finite dimensional algebra. For a subcategory $C$ of $mod-A$ let $\overline{C}$ be the objects $X \in mod-A$ such that there exists an exact sequence $0 \rightarrow C_n \rightarrow ... \...
Mare's user avatar
  • 26.5k
4 votes
0 answers
82 views

On strongly simply connected quiver algebras

Let $A$ be a representation-finite quiver algebra. In this case $A$ is simply connected if and only if its first Hochschild cohomology vanishes by a result of Buchweitz and Liu. $A$ is called strongly ...
Mare's user avatar
  • 26.5k
2 votes
0 answers
56 views

Characterisation of representation-directed algebras

A representation-directed algebra $A$ over a field $K$ has the property that for every indecomposable module $M$ we have $\mathrm{End}_A(M) \cong K$ and $\mathrm{Ext}_A^i(M,M)=0$ for all $i>0$. ...
Mare's user avatar
  • 26.5k
16 votes
2 answers
694 views

How complicated can a finite double complex over a field be?

A finite complex over a field $k$ is pretty simple: it's the direct sum of its homology with a split-exact complex. How complicated can a finite double complex be? Does it make a difference if $k$ is ...
Tim Campion's user avatar
  • 63.9k

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