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3 votes
1 answer
234 views

Global choice of eigenvectors on an open surface

Let $(M^2,g)$ be a noncompact orientable Riemannian surface without boundary. Let $A \in \Gamma(\operatorname{Sym}(TM))$ be a section of the bundle of symmetric endomorphisms of $TM$, that is, for ...
Eduardo Longa's user avatar
2 votes
0 answers
35 views

Can one extend a Hermitian bundle from a compact manifold with boundary to its Riemannian double?

Let $M$ be a compact Riemannian manifold with boundary, and let $E \to M$ be a Hermitian vector bundle, endowed with a compatible connection. Let $\tilde M$ be a Riemannian double of $M$. Does $E$ ...
Alex M.'s user avatar
  • 5,407
0 votes
1 answer
108 views

Intersection Grassmanian planes

I am reading a paper that used Grassmanian planes properties. In particular, they studied the intersection of Grassmanian planes; they check the intersection Grassmanian of $n-k$-planes and ...
Adam's user avatar
  • 1,043
6 votes
0 answers
197 views

Regarding a proof in the surgery theorem by Gromov and Lawson

I have a question regarding a proof in the article The classification of simply connected manifolds of positive scalar curvature written by Gromov and Lawson. The precise reference is: Gromov, ...
user12390's user avatar
  • 386
1 vote
0 answers
225 views

Extending fibre metrics of submanifolds to Riemannian metrics

Let $M$ be a smooth manifold and $S\subseteq M$ a properly embedded smooth submanifold. Suppose that we have a fibre metric on $TM|_S$, i.e. a positive definite real inner-product on $T_pM$ for all $p\...
user115357's user avatar
5 votes
1 answer
1k views

Orthogonal complements in Hilbert bundles

It's a standard fact that for a finite-dimensional vector bundle with an inner product, the othogonal complement of any subbundle is itself a locally trivial vector bundle. What is known about the ...
Dan Ramras's user avatar
  • 8,803