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12 votes
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Two ways a manifold can have little symmetry

Let $M$ be a closed connected smooth oriented manifold. The following two properties - that $M$ can either enjoy or not - intuitively both mean that $M$ has very little symmetry: (a) Every self-map $...
Jens Reinhold's user avatar
9 votes
0 answers
336 views

Nash embedding for 3 manifolds

The Nash embedding theorem tells us that every smooth Riemannian m-manifold can be embedded in $R^n$ for, say, $n = m^2 + 5m + 3$ (edit: 14 is a better bound for compact 3 manifolds thanks @mme). What ...
Ian Gershon Teixeira's user avatar
2 votes
0 answers
205 views

Can a non-compact manifold become compact by cutting it?

I'm trying to understand a step in a proof, where one starts with a non-compact manifold $V$ containing a trapped (2-sided, closed) surface $\Sigma$ that's non-separating. In order to complete the ...
aceituna's user avatar
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