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12 votes
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Which abelian categories have homological dimension 1?

In this MSRI lecture Geometry of Quiver Varieties I, Victor Ginzburg describes all abelian categories of homological dimension $1$ as being either a category of representations $\mathrm{Rep}_\mathbf{...
Mike Pierce's user avatar
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11 votes
0 answers
818 views

How to compute Ext-groups for categories without enough injectives/projectives?

I am studying a category of representations of an infinite-dimensional Lie algebra, which is an abelian category. Unfortunately, the category does not have enough injectives/projectives. I would ...
Batominovski's user avatar
10 votes
0 answers
1k views

Complexes of representations with complementary central charges

This is another question asking for references. There is an important phenomenon of correspondence between (complexes of) representations of infinite-dimensional Lie algebras with the complementary ...
Leonid Positselski's user avatar
6 votes
0 answers
209 views

Classification of representation-finite algebras up to stable equivalence of Morita type

Assume $K$ is an algebraically closed field. I wanted to ask if there is a classification of the representation-finite $K$-algebras up to stable equivalence of Morita type (at least for some small ...
Mare's user avatar
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5 votes
0 answers
142 views

A practical way to check whether a module is periodic

A module $M$ over a finite dimensional selfinjective algebra $A$ over a field $K$ is called periodic if $M \cong \Omega^n(M)$ for some $n \geq 1$. We assume here that $M$ is simple and that A is a ...
Mare's user avatar
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5 votes
0 answers
76 views

Reference on two numbers associated to a module of finite homological dimension

Let $A$ be a finite dimensional algebra over a field $K$ with a module $M$ which has finite projective dimension and finite injective dimension. Let $n \geq 1$. Let $(P_i)$ be a minimal projective ...
Mare's user avatar
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5 votes
0 answers
132 views

On a reference for computing global spectrum of $A_n$-curve singularities, by H.Dao and E.Faber

This question is about chasing down a reference in a paper relating to non-commutative crepant resolutions and Cohen-Macaulay representation theory. Allow me to first give a minor introduction. Let $(...
user160167's user avatar
5 votes
0 answers
168 views

Higher analogue of the Auslander-Bridger transpose

Let $A$ be an Artin algebra and $M$ a module with $Ext^i(M,A)=0$ for $i=1,...,n-2$. Then in case $P_{n-1} \rightarrow ... \rightarrow P_0 \rightarrow M \rightarrow 0$ is the beginning of a minimal ...
Mare's user avatar
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5 votes
0 answers
140 views

Open problems about Morita and derived invariants

Are there properties of rings of which one does not know whether they are Morita or derived invariances? For a recent such example for Morita invariance, see https://www.sciencedirect.com/science/...
Mare's user avatar
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5 votes
0 answers
91 views

Bound on the sum of projective and injective dimension

Recall that a finite dimensional algebra is called piecewise hereditary in case it is derived equivalent to an abelian hereditary category. In proposition 1.2. of https://link.springer.com/article/10....
Mare's user avatar
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5 votes
0 answers
125 views

Stable equivalence and stable Auslander algebras

Let $A$ be a representation-finite finite dimensional quiver algebra and $M$ the basic direct sum of all indecomposable $A$-modules. Recall that the Auslander algebra of $A$ is $End_A(M)$ and the ...
Mare's user avatar
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5 votes
0 answers
303 views

Recovering an A-infinity structure on an Ext-algebra from a quiver presentation

Let $A=KQ/I$ be a basic finite dimensional algebra given by a quiver with relations. Let $S$ denote the direct sum of the corresponding simple modules. According to [Keller: A-infinity algebras in ...
Julian Kuelshammer's user avatar
4 votes
2 answers
771 views

Finitistic dimension conjecture for quadratic algebras

The finitistic dimension of a finite dimensional algebra is defined as the supremum of all projective dimensions of modules having finite projective dimension. The finitistic dimension conjecture says ...
Mare's user avatar
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3 votes
0 answers
48 views

Questions on piecewise hereditary algebras

Let $A$ be a finite dimensional quiver algebra over a field $k$ that is quasi-tilted and representation-finite (this implies that $A$ is a tilted algebra). Assume that the Coxeter polynomial of $A$ is ...
Mare's user avatar
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3 votes
0 answers
54 views

Classes of algebras where derived equivalence preserves the global dimension

Question: Are there known classes $X$ of finite dimensional algebras in the literature that have the property that in case $A, B \in X$ are derived equivalent, they share the same global dimension? ...
Mare's user avatar
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3 votes
0 answers
205 views

Finitistic dimension via tilting modules

is the following true (all algebras and modules are assumed to be finite dimensional): The finitistic dimension of an algebra is equal to the supremum of projective dimensions of tilting modules? It ...
Mare's user avatar
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2 votes
0 answers
138 views

Construction of a certain long exact sequence

Let $A$ be a noetherian ring (not necessarily commutative) or for simplicity even a finite dimensional algebra over a field. Let $X$ and $U$ be finitely generated $A$-modules and let $add(U)$ be the ...
Mare's user avatar
  • 26.5k
2 votes
0 answers
84 views

Representation finite Hopf algebras up to stable equivalence

It is well known that every representation-finite group algebra $KG$ is stable equivalent to a symmetric Nakayama algebra. Question: Is it true that every representation-finite Hopf algebra is stable ...
Mare's user avatar
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2 votes
0 answers
70 views

Rigid modules for hereditary algebras

Let $A=KQ$ be a path algebra of a connected quiver. (K algebraically closed if it helps) Question: Is there an explicit classification of all indecomposable $A$-modules $M$ that are rigid, that is $...
Mare's user avatar
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2 votes
0 answers
91 views

When does a stable endomorphism ring have injective dimension at most one?

tLet $A$ be a Frobenius algebra (we can assume that $A$ is given by quiver and relations) and let $M$ be a basic $A$-module without projective direct summands (we can assume we know the decomposition ...
Mare's user avatar
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2 votes
0 answers
61 views

Question on outer Ext-products

For group algebras $A=KG$ over a field $K$ with finite group $G$ there exists an outer product on Ext: $Ext_A^i(M,N) \otimes_K Ext_A^j(M',N') \rightarrow Ext_A^{i+j}(M \otimes_K M',N \otimes_K N')$. ...
Mare's user avatar
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1 vote
0 answers
124 views

Computing the induced homomorphisms of derived functors using acyclic resolutions

Let's suppose that $F\colon \mathcal A\to \mathcal B$ is a right exact additive functor between abelian categories such that $\mathcal A$ has enough projectives. Standard references shows that if $Q_\...
Benjamin Steinberg's user avatar
1 vote
0 answers
106 views

Uniqueness of indecomposable decomposition (Krull–Schmidt) for finitely generated modules over commutative Noetherian standard graded rings

Let $R_0=\mathbb C$ and $R=\bigoplus_{i\geq 0} R_i$ be a commutative Noetherian graded ring such that the grading is standard, i.e., $R=R_0[R_1]$. Let $M$ be a finitely generated $R$-module. Evidently,...
uno's user avatar
  • 412
1 vote
0 answers
20 views

Finding minimal copresentations of projectives in stable endomorphism rings

Let $A$ be a finite dimensional algebra (you can assume it is selfinjective in case this helps) and $M$ an $A$-module without projective summands. Let $B=\underline{End_A(M)}$, the stable endomorphism ...
Mare's user avatar
  • 26.5k
1 vote
0 answers
77 views

n-Gorenstein algebras and tilting modules

Let $\Lambda$ be an artin algebra over a commutative artinian ring $R$. $\Lambda$ is said to be $n$-Gorenstein, for some natural number $n$, provided it have finite self-injective dimension at most $n$...
Xiaosong Peng's user avatar
1 vote
0 answers
63 views

Reference request for formula on global dimension

Given a finite dimensional algebra $A$ over an algebraically closed field $K$. Let $A^e=A^{op} \otimes_K A$ be the enveloping algebra of $A$. Who noted first that the global dimension of $A$ is equal ...
Mare's user avatar
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