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Characterisation of a family of continuous martingales

I look for a full characterisation of the continuous martingales $X=(X_t)_{0\leq t\leq T}$ (defined on some filtered probability space as nice as possible) such that $$X_0=0\quad \mbox{ and } \quad\...
Fawen90's user avatar
  • 1,389
0 votes
0 answers
31 views

Looking for a citation for this simple generalization of the Markov bound to non-negative super-martingales

Does anybody know a reference for the following theorem? Theorem 1. Let $(X_t)_{t=0}^\infty$ be a non-negative supermartingale. Then, for any constant $c > 0$, the event $(\exists > t)\, X_t \...
Neal Young's user avatar
4 votes
1 answer
66 views

Expectation bounds on supremum of family of martingales

Suppose I fix a filtered probability space $(\Omega, \mathcal{F}, \mathbb{F}, P)$ and on it a Brownian motion $B$. Let $\tau_\alpha$ denote a set of stopping times which satisfies $\sup_\alpha \tau_\...
qp212223's user avatar
  • 143
0 votes
1 answer
57 views

Lower bounding an alternating series with signs from a martingale difference sequence

Let $\epsilon_n \in \{-1, 1\}$ be a martingale difference sequence, in the sense that $$M_n := \sum_{i = 0}^n \epsilon_i$$ is a martingale. We assume $\epsilon_0 = \pm 1$ with probability $\frac{1}{2}$...
Nate River's user avatar
  • 6,165
6 votes
1 answer
659 views

On the martingale betting scheme

For a fixed probability $0 < p < 1$, let $X^p$ be the martingale that goes up by $1$ with probability $p$, and goes down by $\frac{p}{q}$ with probability $q := 1-p$. Write $X$ for the ...
Nate River's user avatar
  • 6,165
1 vote
1 answer
60 views

Reverse Doob’s maximal inequality for bounded martingales

Consider the set of discrete or continuous time $L^\infty$-bounded martingales $X$ with $X_0 = 0$ almost surely. Here $L^\infty$-bounded means $\|X\|_{\infty} := \sup_t \mathbb \|X_t\|_{L^\infty(\...
Nate River's user avatar
  • 6,165
3 votes
1 answer
181 views

A nice terminal inequality for martingales

Let $X_t$ be a continuous time martingale taking with $\sup_t \mathbb E[X_t^-] < \infty$, and $X_0 = 0$ almost surely. Assume further that $X_1$ admits a probability density function. Is it true ...
Nate River's user avatar
  • 6,165
0 votes
1 answer
64 views

Sharpening Doob’s upcrossing inequality for Brownian motion

Note: This question is heavily related to a series of posts ([1], [2]) by user GJC20. Provided a martingale $X$ in continuous-time, Doob's upcrosssing inequality states: If $U(a,b)$ denotes the number ...
Nate River's user avatar
  • 6,165
0 votes
2 answers
60 views

Do continuous martingales satisfy this nice terminal inequality?

Let $X$ be a continuous, non negative martingale on $[0, 1]$ with $X_0 = x_0$ a.s. for some $x_0 \in \mathbb R$. Assume further that $X_1$ admits a probability density function. Is it true that the ...
Nate River's user avatar
  • 6,165
2 votes
0 answers
71 views

Assumptions Wald's second equation?

Let $(X_n)_{n\in \mathbb{N}}$ be an i.i.d. sequence of random variables and $N$ an $\mathbb{N}_0$ valued random variable. Let $X_1 \in \mathcal{L}^2$ and $N \in \mathcal{L}^1$. Let $S_n := \sum_{i=1}^...
psl2Z's user avatar
  • 261
1 vote
1 answer
185 views

Sum of $X_k$ with $\mathbb{P}(X_k=\pm 1) = 1/2\pm 1/(2\sqrt{k})$

Let $\{X_k\}$ be a sequence of mutually independent random variables with \begin{align} \mathbb{P}(X_k = 1) & = \frac{1}{2} + \frac{1}{2\sqrt{k}}, \\ \mathbb{P}(X_k = -1) & = \frac{1}{2} - \...
Nuno's user avatar
  • 269
3 votes
0 answers
101 views

Divergent/Unbounded random walks techniques

I want to prove the following biased random walk will be diverge. Suppose I have a random walk $S_n = X_1 + ... + X_n$, but $X_1,...,X_n$ are dependent variables. $X_1 \sim$ Bernoulli($\sigma(\theta_1)...
Chu Thắng's user avatar
9 votes
3 answers
448 views

All stationary martingales are constant?

Suppose $(X_{n})_{n\geq{1}}$ is a stationary process that is a martingale with respect to some filtration. Suppose also that $\mathbb{E}X_{0}^{2}<\infty$ so that $\mathbb{E}X_{n}^{2}<\infty$ for ...
David Pechersky's user avatar
2 votes
0 answers
61 views

Characterisation of Bessel process

Let $\delta \in (0, 2)$; $(X_t)_{t \ge 0}$ a nonnegative continuous Markov process. Suppose that For each $T \ge 0$, if we write $\tau \overset{\mathrm{def}}= \inf\{t \ge T : X_t = 0\}$, then $(X_{T +...
Focus's user avatar
  • 177
3 votes
0 answers
80 views

Seeking strong bounds on KL-divergence and martingales for a hypothesis-testing inequality

Let's say we have a finite set $\mathcal{O}$ of observations, and let $\mathcal{C}(\Delta\mathcal{O})$ denote the space of closed convex sets of probability distributions. We have two hypotheses which ...
Alex Appel's user avatar
1 vote
1 answer
129 views

A martingale puzzle about sum of expected squared bounds

I'm trying to get one of those "with $1-\delta$ probability, the following holds"-style bounds, and the following martingale problem looks solvable by some Freedman or Bernstein-style bound, ...
Alex Appel's user avatar
3 votes
1 answer
180 views

When does a local supermartingale become a proper supermartingale?

This is a cross-post of my question on MSE. Abstract: When a local supermartingale is bounded from below, is it a proper supermartingale? Question: In remark 4.2 (p.16) of the lecture notes by Martin ...
Hirofumi Shiba's user avatar
3 votes
1 answer
553 views

A concentration inequality derived from Freedman’s inequality

Freedman’s inequality is a well-known concentration inequality of martingale difference sequence: Let $(Z_t)_{t \leq T}$ be a real-valued martingale difference sequence adapted to filtration $\...
Mixi Andrew's user avatar
4 votes
0 answers
80 views

Does this filtration have a name?

In the context of Ethier&Kurtz Markov Processes: Characterization and Convergence (Chapter 4, equation (3.2)) as well as the two papers Martingale problems for conditional distributions of Markov ...
Mushu Nrek's user avatar
0 votes
0 answers
90 views

Martingale defined by an integral

Consider a probability space $(\Omega,\mathcal{F},P).$ Let $f \in C^{\infty}_{c}(\mathbb{R}^d,\mathbb{R}),p \geq 2.$ $(X_r^{y})_{(r,y) \in \mathbb{R}_+ \times \mathbb{R}^d}$ is a stochastic process ...
mathex's user avatar
  • 573
1 vote
0 answers
125 views

Can we construct close discrete martingales if their terminal marginal laws are close?

As no answer or comment to Can we construct close martingales if their terminal marginal laws are close? we consider a simplified version (discrete-time) as below: Let $M=(M_k)_{0\le k\le n}$ be a ...
Fawen90's user avatar
  • 1,389
6 votes
1 answer
396 views

Is a martingale conditioned to be large a submartingale?

Let $X$ be a continuous time martingale such that $X_\infty := \lim_{t \to \infty} X_t$ exists almost surely. Let $x \in \mathbb R$ be such that $\mathbb P(X_\infty \geq x) > 0$, and define the ...
Nate River's user avatar
  • 6,165
2 votes
1 answer
246 views

Can we construct close martingales if their terminal marginal laws are close?

Let $M=(M_t)_{0\le t\le 1}$ be a real-valued continuous martingale. Let $\mu := {\rm Law}(M_1)$ and $\varepsilon \in (0,1)$. For any $\nu$ satisfying $W_2(\mu,\nu)\le \varepsilon$, can we construct ...
Fawen90's user avatar
  • 1,389
10 votes
2 answers
828 views

On martingale convergence

Let $(X_t)_{t\ge0}$ be a martingale with continuous paths. It was previously shown here and here that then it is impossible that $X_t\to\infty$ almost surely as $t\to\infty$. Is it possible that there ...
Iosif Pinelis's user avatar
4 votes
2 answers
373 views

Another curious martingale

This is a natural follow up question to A curious martingale. Does there exist an almost surely continuous martingale that converges in probability to $+\infty$? Note: We say a process $X_t$ converges ...
Nate River's user avatar
  • 6,165
7 votes
2 answers
2k views

A curious martingale

Does there exist an almost surely continuous martingale $X$ with $X_t \to +\infty$ almost surely? Remark: Note that such a martingale exists in discrete time, or equivalently in continuous time if the ...
Nate River's user avatar
  • 6,165
2 votes
1 answer
74 views

Conditions for absorption

Let $X$ be a Markov chain with countable state space $S$ and transition kernel $P$, and let $h \colon S \to [0,1]$ be a sub-harmonic or super-harmonic function. Assume that for all $\varepsilon >0$ ...
user avatar
3 votes
0 answers
147 views

Request for article in Rev. Roumaine Math. Pures Appl. (1981)

I am looking for the following article: Al-Hussaini, A. N. A projective limit view of $L_1$-bounded martingales. Rev. Roumaine Math. Pures Appl.26 (1981), no.1, 51–54, but I can't find it anywhere. Do ...
mathex's user avatar
  • 573
2 votes
0 answers
121 views

Martingale regularization

Consider a submartingale $X,$ then for almost every $\omega \in \Omega,$ for every $v \in \mathbb{R},\lim_{u \in \mathbb{{Q},u \uparrow v}}X_u(\omega)$ exist in $\mathbb{R}.$ I was wondering if there ...
mathex's user avatar
  • 573
1 vote
1 answer
83 views

Integral of $M^\text{*} - M$ with respect to $M^\text{*}$ is zero for $M^\text{*}$ the running maximum of $M$ a continuous local martingale

Given $M$ a continuous local martingale, and $M^\text{*} = \sup_{0 \leq s \leq t} M_s$ its running maximum, we consider the finite variation integral $$ I_T:= \int_0^T (M^\text{*}_s - M_s) \, \text{d}...
George's user avatar
  • 113
1 vote
0 answers
156 views

is there a discrete version of Dambis Dubins Schwarz Theorem

Theorem (Dambis, Dubins-Schwarz). If $M$ is a $\left(\mathscr{F}_t, P\right)$-continuous martingale vanishing at 0 and such that $\langle M, M\rangle_{\infty}=\infty$ and if we set $$ T_t=\inf \left\{...
neveryield's user avatar
2 votes
0 answers
282 views

Identify two continuous martingales in law as time-changed Brownian motions

Let $W$ be a Brownian motion and $\alpha$ be a progressively measurable process taking values in $\mathbb R_+$. Set $\beta_t:=\max(\alpha_t, 1)$ for all $t\ge 0$. Define respectively $X$, $Y$ by $$X_t:...
Fawen90's user avatar
  • 1,389
1 vote
1 answer
464 views

A Lévy process is a semimartingale proof

I have to prove that a Lévy process is a semimartingale. In general we say that $X$ is a semimartingale if it is an adapted process such that, for each $t ≥ 0$, $$X (t) = X (0) + M(t) + C(t)$$ where $...
Joegin 's user avatar
3 votes
1 answer
352 views

First time random sum exceeds value

Suppose $X_n$ $n = 1, 2, \ldots$ are i.i.d random variables with $\mu := \mathbb{E}[X_n]$ > 0. (although they are not necessarily non-negative). Then if $S_n = \sum_{k=1}^n X_k$ and $\tau_a$ = $\...
Red5551's user avatar
  • 33
1 vote
0 answers
87 views

Normal approximation of martingale difference

Apologies in advance if the question is not precise (or silly), I am not a probabilist by profession. I have the following question: Let $(X_n)_{n \geq 1}$ be a martingale difference sequence. Assume ...
Kurisuto Asutora's user avatar
8 votes
1 answer
533 views

Concentration bounds for martingales with adaptive Gaussian steps

Consider the following martingale: $X_1 \sim \mathcal{N}(0, 1)$, and for any $n > 1$, $X_n \sim \mathcal{N}(X_{n-1}, X_{n-1}^2)$ (notice, this is a conditional distribution given $X_{n-1}$). I am ...
moshenfeld's user avatar
6 votes
1 answer
168 views

Weak convergence of random measures generated by non-negative martingales?

If I have a sequence of non-negative continuous martingales $(M_n(x))_{n\ge 1}$ on $x\in[0,1]$, i.e. for each fixed $n$, $M_n:[0,1]\to[0,\infty)$ is a continuous process, and for each fixed $x\in[0,1]$...
MikeG's user avatar
  • 715
1 vote
0 answers
182 views

Hardy's inequality proof using Doob's inequalities

Consider a probability space $([0,1],\mathcal{B}([0,1],\lambda),p>1$ and $f \in L^p(]0,\infty[).$ We want to prove Hardy's inequality using martingale theory and Doob's maximal inequalities. Let $\...
mathex's user avatar
  • 573
2 votes
1 answer
198 views

Enlargement of filtration

Let $M_t$ be a continuous time real valued martingale, and $\mathcal F_t$ its natural filtration. Suppose that $\mathcal F_t \setminus \mathcal F_s$ is nonempty for all $t > s$. Let $\mathcal G$ be ...
Nate River's user avatar
  • 6,165
2 votes
1 answer
182 views

Mean of log-normal variable when exponent is replaced by runnung maximum of Ito-integral

Let $W=\{W_t\}_{t\in[0;1]}$ be a real-valued Brownian motion, $\{F_t\}_{t\in [0;1]}$ the filtration generated by $W$, augmented with the nullsets. Let $\{\sigma_t\}_{t\in[0;1]}$ be a continuous and ...
Kolodez's user avatar
  • 335
1 vote
1 answer
139 views

Characterization of Brownian motion: processes with right-continuous paths

I am looking for a reference with a proof for the following fact: If a right-continuous martingale $(X_r)_{ r \geq 0}$ is such that $X_0=0,(X^2_r-r)_r,(X_r^3-3rX_r)_r,(X_r^4-6rX_r^2+3r^2)_r$ are ...
mathex's user avatar
  • 573
2 votes
1 answer
2k views

Alternate proof of Levy’s characterisation of Brownian motion

Levy’s characterisation theorem for Brownian motion states that for a local martingale $X$ with $X_0 = 0$, $X$ is a Brownian motion if and only if it has quadratic variation $\langle X, X \rangle_t = ...
Nate River's user avatar
  • 6,165
3 votes
1 answer
474 views

Harmonic function and Markov chain

Let $X=(X_k)_{k \in \mathbb{N}}$ be a Markov chain with countable countable state space $S$ and transition matrix $P.$ Let $\mathcal{T}$ be the tail $\sigma$-field of $X:\mathcal{T}=\bigcap_{k \in \...
john's user avatar
  • 53
5 votes
1 answer
350 views

Can an a.s. non constant continuous martingale be differentiable with nonzero probability?

Let $M$ be a continuous martingale such that almost surely, the sample paths of $M$ are not constant. Question: Is it true that $M$ is almost surely not differentiable?
Nate River's user avatar
  • 6,165
10 votes
1 answer
700 views

Martingales converging in probability but not a.s

It is known that a random series $$ \sum_{n\geq 1} X_n $$ whose terms $X_n$ are independent converges a.s. if and only if it converges in probability. Is it true that a martingale $(Y_n)$ converges a....
Liviu Nicolaescu's user avatar
1 vote
0 answers
240 views

Where to submit a new proof of the continuous martingale convergence theorem?

There were various proofs of the discrete martingale convergence theorem, but as far as I know there is only one proof of the continuous version of this theorem using the up-crossing lemma. I wrote a ...
Ghafari's user avatar
  • 11
2 votes
1 answer
300 views

Reverse martingale convergence theorem in Banach spaces

In section 1.5 of a course given by Gilles Pisier, the author is claiming that in the excerpt below $\operatorname E[\varphi_i\mid\mathcal A_{-n}]\to\operatorname E[\varphi_i\mid\mathcal A_{-\infty}]$ ...
0xbadf00d's user avatar
  • 167
2 votes
1 answer
274 views

Inequality for increments of $r$th absolute moments of martingales, $1<r<2$

If $Y_n=\sum_{i=1}^n X_i$ is a martingale, where $X_i$ is a martingale difference sequence, $\mathbb{E}[X_n\mid \mathcal{F}_{n-1}]=0$ for all $n$, we know that $$ \mathbb{E}\big[Y_n^2-Y_{n-1}^2\big]=\...
mattia's user avatar
  • 23
4 votes
1 answer
262 views

Bounded density for diffusions with diffusion coefficients bounded away from $0$

Consider a diffusion given by $$X_t=\int_0^t a(s,X_s)\,dW_s$$ for $t\ge 0$, where $W_\cdot$ is a standard Wiener process/Brownian motion and $a$ is a smooth enough positive function bounded away from $...
Iosif Pinelis's user avatar
5 votes
2 answers
311 views

A comparison of diffusions

Consider two diffusions given by $$X_j(t)=\int_0^t a_j(s,X_j(s))\,dW_s$$ for $j=1,2$ and $t\ge 0$, where $W_\cdot$ is a standard Wiener process/Brownian motion and the $a_j$'s are smooth enough ...
Iosif Pinelis's user avatar

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