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12 votes
1 answer
371 views

Is $X\times X$ homeomorphic to $X$ for a space of probability measures?

Let $\mathcal M_1(S)$ be the (compact, metrizable) space of probability Borel measures on the circle $S=\{z\in\mathbb C: |z|=1\}$ with its weak $*$ topology, so $\mu_n\to\mu$ if and only if $$ \int_S ...
Christian Remling's user avatar
2 votes
0 answers
156 views

About the 7.3.5. Corollary of the book "Measure Theory" by V.I. Bogachev

According to the 7.3.5. Corollary of the book "Measure Theory" by V.I. Bogachev we have the following result: Let $(X,\tau)$ be a completely regular space and let $\Gamma$ be a family of ...
rfloc's user avatar
  • 627
8 votes
1 answer
197 views

Topological property of the space of probability measures

Suppose that $\mathbb{P}$ is the metric space of Borel probability measures on the interval $[0,1]$ equipped with the topology of $w^*$ convergence. Consider also $\mathbb{P}_{ac}, \mathbb{P}_{s}$ the ...
an_ordinary_mathematician's user avatar
0 votes
0 answers
32 views

Hausdorff dimension: The dimension of boundary of a set [migrated]

I can't understand the following statement. If (perhaps not closed) set $S$ has dimension $n$, then the boundary could have any dimension from $0$ to $n$. (Could someone give me an example?) If S ...
TianS's user avatar
  • 29
3 votes
0 answers
75 views

Can we generalize the Kuratowski Extension Theorem to Souslin spaces?

The Kuratowski Extension Theorem says: Let $(X,\mathcal{A})$ be a measurable space, $Y$ be a polish space, $A\subseteq X$, and $f:A\to Y$ be a measurable map. Then there is a measurable function $F:X\...
rfloc's user avatar
  • 627
3 votes
0 answers
144 views

What is an example of a non-tight probability measure?

Billingsley (Convergence of Probability Measures, 1968) and van der Vaart and Wellner (Weak Convergence and Empirical Processes, 2023) discuss the concept of tight probability measures and use the ...
cgmil's user avatar
  • 277
3 votes
1 answer
176 views

Compactness of set of measurable functions between compact subspaces of real numbers

Let $X$ be a compact subset of $\mathbb{R}^n$ and $Y$ be a convex and compact subset of $\mathbb{R}^p$. Consider $\mathcal{F}$ the set of all measurable functions from $X$ to $Y$. Can I find ...
guest1's user avatar
  • 131
2 votes
1 answer
123 views

Signed measures on algebras (fields) and their boundedness properties

I asked this question here on math.StackEchange, but it might be too technical so I re-post it here. Let $X$ be a compact Hausdorff second countable topological space. Let $\mathcal{B}$ a countable ...
Ennio's user avatar
  • 23
7 votes
2 answers
446 views

Uncountable collections of distinct subsets of an interval (existence)

Throughout, $\mu$ is just the Lebesgue measure. Question: does there exist an uncountable family of distinct subsets of $[-1, 1]$, denoted by $(U_j)_{j \in [-1, 1]}$, with $\mu(U_j) > 0$ for each $...
Stepan Plyushkin's user avatar
2 votes
0 answers
71 views

Topological measure theory on spaces that are not completely regular

In the usual discourse regarding approaches to measure theory, it is often pointed out that the restriction of topological measure theory to locally compact Hausdorff spaces is insufficient. However, ...
Cameron Zwarich's user avatar
1 vote
0 answers
102 views

Homeomorphism to $[0,1]^n$ preserving equality of measure

Let $A\subseteq R^n$ be a subset which is homeomorphic to $\left[0,1\right]^n$. Does there exists a homeomorphic map $f:A\rightarrow \left[0,1\right]^n$ such that for any $X_1,X_2\subseteq\left[0,1\...
tom jerry's user avatar
  • 349
0 votes
0 answers
55 views

Any useful bases for the topology induced by the $t$-Wasserstein distance?

I am working on $\mathbb R ^d$ equipped with the usual Euclidean metric. I know of one nice base for $\mathcal W _t$, namely: $$\left\{ B_p (r) : r>0, p=\sum_{i=1} ^n \alpha_i \delta_{x_i},\text{ ...
J.R.'s user avatar
  • 291
6 votes
0 answers
195 views

Prokhorov's theorem for countably many random measures on a Polish space

I am looking for help to show the following lemma: Lemma Let $(\Omega,\mathcal A,\mathbb P)$ be a complete, standard Borel probability space and $\mathcal X$ a Polish space. Let $\mathcal P(\mathcal ...
Pierre-François Massiani's user avatar
0 votes
0 answers
98 views

Does weak $L^2$ approximation implies $L^2$ approximation under a condition similar to convexity?

(Cross posted from Math StackExchange: Does weak $L^2$ approximation implies $L^2$ approximation under a condition similar to convexity?) Assume $(\Omega, \mu)$ is a probability space. Consider a ...
David Gao's user avatar
  • 2,800
2 votes
1 answer
300 views

If $\mathcal{H}^{n-1}(E)=0$ then $\mathbb{R}^n\setminus E$ is connected

Let $E\subset \mathbb{R}^n$ be a (measurable) subset with $\mathcal{H}^{n-1}(E)=0$, where $\mathcal H^{n - 1}$ is the ($n - 1$)-dimensional Hausdorff measure. I want to know if $\mathbb{R}^n\setminus ...
No-one's user avatar
  • 1,149
1 vote
0 answers
72 views

Is $L^p_\text{loc} (Y)$ dense in $(L^0(Y), \hat \rho)$?

Below we use Bochner measurability and Bochner integral. Let $(Y, d)$ be a separable metric space, $\mathcal B$ Borel $\sigma$-algebra of $Y$, $\nu$ a $\sigma$-finite Borel measure on $Y$, $(Y, \...
Analyst's user avatar
  • 657
9 votes
1 answer
339 views

A topological characterisation of a.e. continuity

We say a measurable function $f: \mathbb R^n \to \mathbb R$ is essentially continuous if the inverse image of any open set $O$ differs from an open set by a set of null measure, in the sense that ...
Nate River's user avatar
  • 6,155
2 votes
1 answer
369 views

Relationship between Baire sigma algebra and Borel sigma algebra of an uncountable product

I've been trying to understand various questions to do with sigma algebras on uncountable product spaces. Let $T$ be an uncountable set and for each $t \in T$, let $\Omega_t$ be a topological space. ...
SBK's user avatar
  • 1,179
4 votes
1 answer
165 views

Is the set of clopen subsets Borel in the Effros Borel space?

Let $X$ be a Polish space and $\mathcal{F}(X)$ the set of closed subsets of $X$ endowed with the Effros Borel structure, generated by sets of the form $\{F\in \mathcal{F}(X):F\cap U\neq \emptyset\}$, ...
Iian Smythe's user avatar
  • 3,115
2 votes
0 answers
49 views

$\sigma$-compactness of probability measures under a refined topology

Denote Polish spaces $(X, \tau_x)$ and $(Y, \tau_y)$, where $X$ and $Y$ are closed subsets of $\mathbb{R}$. Consider a Borel measurable function $f: (X \times Y, \tau_x \times \tau_y) \rightarrow \...
Hans's user avatar
  • 195
4 votes
0 answers
119 views

Is the range of a probability-valued random variable with the variation topology (almost) separable?

Let $X$ and $Y$ be uncountable Polish spaces, $\Delta(Y)$ be the space of Borel probability measures on $Y$ endowed with the Borel $\sigma$-algebra induced by the variation distance, and let $g:X\to \...
Michael Greinecker's user avatar
2 votes
0 answers
47 views

The world of non-weak*-topologies on $\mathcal{P}(X)$

Let $X$ be a metrizable space and consider $\mathcal{P}(X)$, the set of all probability measures on $X$. Typically, the weak*-topology is considered on $\mathcal{P}(X)$, which is a very natural ...
alhal's user avatar
  • 429
3 votes
0 answers
145 views

Eigenvalues of random matrices are measurable functions

I have read that if a random matrix is hermitian then its eigenvalues are continuous, hence also measurable. If the random matrix is not hermitian, the eigenvalues are not continuous in some cases. ...
Curtis74's user avatar
2 votes
0 answers
226 views

Is the product of two outer regular Radon measures outer regular?

Everything is nice on second countable spaces: the product of two outer regular Radon measure is still an outer regular Radon measure. But what happens without the assumption of second countability? ...
Thomas Lehéricy's user avatar
4 votes
2 answers
261 views

Product of locally Borel sets locally Borel

Let $X$ be a locally compact Hausdorff space with a fixed Radon measure (= Borel measure that is finite on compact subsets, inner regular on open subsets and outer regular on Borel sets) $\mu$ . A ...
Andromeda's user avatar
  • 175
3 votes
1 answer
159 views

Closed graph correspondence which never contains the whole support

Let $I=[a,b]$ with $a<b\in\mathbb{R}$ and denote by $\mathcal{M}(I)$ the set of Borel probability measures on $I$ equipped with the topology induced by the weak convergence of measures. Does there ...
Julian's user avatar
  • 113
9 votes
2 answers
687 views

Analogue of open/closed maps for measurable spaces

$\newcommand{\A}{\mathcal{A}}\newcommand{\T}{\mathcal{T}}$The notions of continuous map of topological spaces and measurable function of measurable spaces are very similar: A map of topological ...
Emily's user avatar
  • 11.8k
2 votes
1 answer
192 views

Open sets in the space of signed measures equipped with the Kantorovich–Rubinshtein norm

Let $X$ be a compact metric space and $\mathcal{M}(X)$ be the space of variational-bounded, signed Borel measures equipped with the Kantorovich–Rubinshtein norm, cf. [Section 8.3, 1]: $$||\mu||_0:= \...
Julian's user avatar
  • 113
6 votes
1 answer
203 views

Can Theorem 1.40 in Rudin's Real and Complex Analysis be strengthened when the $\sigma$-algebra is Borel?

Let $(X, \mathcal F, \mu)$ be a $\sigma$-finite measure space and $(E, |\cdot|)$ a Banach space. Here we use the Bochner integral. Then we have Theorem 1.40 in Rudin's Real and Complex Analysis, i.e., ...
Akira's user avatar
  • 835
3 votes
0 answers
173 views

Any reference on Jensen inequality for measurable convex functions on a Hausdorff space?

I asked this question on math.stackexchange and I was suggested that asking it may be more appropriate. This is part of my research which tries to extend some of Choquet's theory to some non-compact ...
P. Quinton's user avatar
1 vote
0 answers
192 views

Is the domain space in Lusin's theorem required to be Hausdorff?

I'm reading a general version of Lusin's theorem, i.e., If $\mu$ is a finite Radon measure on $X$, and $Y$ is a second countable topological spaces, then for any Borel-measurable function $f:X\to Y$ ...
Akira's user avatar
  • 835
2 votes
1 answer
852 views

The Borel sigma-algebra of a product of two topological spaces

The following problem arose while trying to justify some "known results" in abstract harmonic analysis on noncommutative groups, for which I couldn't find explicit statements in the ...
Yemon Choi's user avatar
  • 25.8k
3 votes
1 answer
131 views

Does there exist $f:\Bbb{R}\to \Bbb{R}$ additive onto function such that $f(F) \subset \Bbb{R}$ has the property of Baire for every $F$?

Let $F\subset \Bbb{R}$ intersect every closed uncountable subsets of $\Bbb{R}$. Does there exist $f:\Bbb{R}\to \Bbb{R}$ additive onto function such that $f(F) \subset \Bbb{R}$ has the property of ...
SoG's user avatar
  • 307
6 votes
1 answer
191 views

Steinhaus number of a group

$\newcommand\Sn{\mathit{Sn}}$A subset $A$ of a group $X$ is called algebraic if $A=\{x\in X: a_0xa_1x\dotsm xa_n=1\}$ for some elements $a_0,a_1,\dotsc,a_n\in X$. Let $\mathcal A_X$ be the family of ...
Taras Banakh's user avatar
  • 41.8k
2 votes
1 answer
140 views

Is a Boolean algebra with an order continuous topology a measure algebra?

Assume that $B$ is a complete boolean algebra endowed with a Hausdorff topology, with respect to which all operations on $B$ are continuous, $0$ has a base of full sets (recall that $A\subset B$ is ...
erz's user avatar
  • 5,529
0 votes
1 answer
242 views

Condition for set of the type $\{(a,b)|a \in A, \ b = f(a)\}$ to have empty interior if $A$ has empty interior [closed]

Let us consider $$\mathcal X = \{(a,b)|a \in A, \ b = f(a)\}, $$ where $A \subset L^1(\mathbb R)$ has empty interior and $f:L^1 \to L^1$ is a bijective map. Does $\mathcal X$ also have empty interior? ...
Riku's user avatar
  • 839
1 vote
0 answers
155 views

Study of the class of functions satisfying null-IVP

$\mathcal{N}_u$ : Class of all uncountable Lebesgue-null set i.e all uncountable sets having Lebesgue outer measure $0$. Let $f:\Bbb{R}\to \Bbb{R}$ be a function with the following property : $\...
SoG's user avatar
  • 307
5 votes
1 answer
254 views

Boolean algebra of ambiguous Borel class

Suppose $X$, $Y$ are uncountable compact metric spaces and $\Delta^0_\xi(X)$, $\Delta^0_\xi(Y)$ ($2\le\xi\le\omega_1$) are the Boolean algebras of Borel sets of ambiguous class $\xi$. So for $\xi=2$ ...
Fred Dashiell's user avatar
5 votes
1 answer
253 views

Is the topology of weak+Hausdorff convergence Polish?

Let $X$ be a compact metric space, $P_X$ the set of Borel probability measures on $X$, and $K_X$ the set of non-empty closed subsets of $X$. I will define the "topology of weak+Hausdorff ...
Julian Newman's user avatar
8 votes
1 answer
489 views

The class of spaces where every Borel measure is atomic

I have been considering the following question: Let $X$ be a compact, metrizable space with the following property: every (regular) Borel probability measure on $X$ is atomic, i.e. for each $\mu\in\...
J G's user avatar
  • 93
0 votes
0 answers
98 views

Reference request: subspace-based generalisation of weak* convergence

Let $V$ be a normed space and $(V_j)_{j\in [0,1]}$ be a family of linear subspaces of $V$ with $V_1$ non-trivial and such that $V_1\subsetneq V_j\subseteq V_i$ whenever $i\leq j$. We write $W:=V'$ for ...
fsp-b's user avatar
  • 463
2 votes
1 answer
148 views

Borel $\sigma$-algebras on paths of bounded variation

Let $(C, \|\cdot\|)$ be the Banach space of continuous paths $x: [0,1]\rightarrow\mathbb{R}^d$ starting at zero with sup-norm $\|\cdot\|$. Let further $B\subset C$ be the subspace of $0$-started ...
fsp-b's user avatar
  • 463
2 votes
0 answers
75 views

Dual space induced by a finer topology

Let $\|\cdot\|_1$ and $\|\cdot\|_2$ be two seminorms on a space $E$ such that $\|\cdot\|_2\geq\|\cdot\|_1$. Let further $E_i:=(E,\|\cdot\|_i)$ and $$C_b(E_i):=\{f : E\rightarrow\mathbb{R}\mid f \ \...
fsp-b's user avatar
  • 463
3 votes
0 answers
153 views

Is it possible to reconstruct the universally measurable sets in X from the $C^*$-algebra $C(X)^{**}$?

This continues my question of two months ago. Let $X$ be a compact Hausdorff topological space. We consider the $C^*$-algebra $C(X)$ of continuous functions on $X$, its dual space $C(X)^{*}=M(X)$ of ...
Sergei Akbarov's user avatar
7 votes
1 answer
280 views

Extending a finite Baire measure to a regular Borel measure

Let $X$ be a Hausdorff compact space, and let $\mathrm {Ba}$, $\mathrm {Bo}$ be its Baire, respectively, Borel, $\sigma$-algebras. Let $\mu:\mathrm {Ba}\to[0,+\infty)$ be a finite Baire measure: it is ...
Pietro Majer's user avatar
  • 60.5k
1 vote
1 answer
183 views

Topological analog of the Lusin-N property

$A\subset \Bbb{R}$ is meager if $A$ can be expressed as a countable union of nowhere dense sets. Let $f:[a, b]\to \Bbb{R}$ is absolutely continuous, i.e., for every $\epsilon>0$, there exists $\...
SoG's user avatar
  • 307
1 vote
3 answers
345 views

Under what general conditions is the set $S := \left\{\int_{X}v(x)\pi(x)\,\mathrm{d}P(x) \mid \pi: X \to A\right\}$ closed?

Let $X$ be a compact subset of $\mathbb R^n$ and let $A$ be a compact subset of $\mathbb R^k$. Let $P$ be a probability distribution on $X$ and $v$ be a $P$-measurable function from $X$ to $\mathbb R^{...
dohmatob's user avatar
  • 6,853
3 votes
0 answers
232 views

Is it possible to reconstruct the compact space $X$ from the space of measures $M(X)$?

Let $X$ be a compact Hausdorff topological space and $C(X)$ the Banach algebra of continuous functions $u:X\to\mathbb C$ (with the usual $\sup$-norm). It is well-known that the structure of Banach ...
Sergei Akbarov's user avatar
2 votes
1 answer
161 views

Existence of a Borel measurable function

Let $X$ be a compact metric space and $Y\subset X$ be a compact set. Assume that $f_1, f_2: Y \to \mathbb{P}\mathbb{R}^2$ are continuous functions. Let $N \subset \mathbb{P}\mathbb{R}^2$ be a ...
David's user avatar
  • 133
4 votes
1 answer
202 views

Generalized limits in Boolean algebras

Let $\mathbb{B}$ be an infinite $\sigma$-complete Boolean algebra. By $\mathbb{B}^\omega$ we denote the countable product of $\mathbb{B}$ with the coordinate-wise operations. Let us call a ...
Damian Sobota's user avatar

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