Skip to main content

All Questions

Filter by
Sorted by
Tagged with
35 votes
2 answers
9k views

tr(ab) = tr(ba)?

It is well known that given two Hilbert-Schmidt operators $a$ and $b$ on a Hilbert space $H$, their product is trace class and $tr(ab)=tr(ba)$. A similar result holds for $a$ bounded and $b$ trace ...
André Henriques's user avatar