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Questions tagged [noncommutative-algebra]

Non-commutative rings and algebras, non-associative algebras. Can be used in combination with ra.rings-and-algebras

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The monoid of stably-free modules over integral group rings

Fix a torsion-free group G, let $M_G$ be the monoid of stably-free $\mathbb{Z}G$-modules under operation $\oplus$, the direct sum of modules. In studying objects related to Wall’s D2 problem on CW-...
William Thomas's user avatar
2 votes
0 answers
144 views

Zero divisors in the extra-special group algebra $\mathbb{R}[2^{1+6}_+]$

Can you characterize the unit-group of the real group-algebra of the extraspecial plus-type 2-group of order 128? (That is $\mathbb{R}[2_+^{1+6}]$ using Conway's notation.) (Please choose any irrep ...
Eric Downes's user avatar
9 votes
2 answers
2k views

A ring for which the category of left and right modules are distinct

What is an example of a ring $R$ for which the abelian category of left $R$-modules is not isomorphic to the category of right $R$-modules?
Tim Montegue's user avatar
1 vote
1 answer
182 views

A question about surjective maps between quadratic algebras

Let $V$ be a finite-dimensional vector space and $$ U \subseteq W \subseteq V \otimes V $$ be a proper inclusion of vector subspaces. Then take the tensor algebra $$ T(V) = \bigoplus_{i=1}^{\infty} V^{...
Pierre Dubois's user avatar
9 votes
1 answer
889 views

Combinatorics for the action of Virasoro / Kac–Schwarz operators: partition polynomials of free probability theory

In the background sections below, I establish the relations among characterizations of the action of Virasoro / Kac–Schwarz operators of 2D gravity models presented in terms of Laurent series by ...
Tom Copeland's user avatar
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1 vote
1 answer
165 views

Polynomial identities satisfied by the Weyl algebra in prime characteristic

The rank $n$ Weyl $A_n(\mathsf{k})$ algebra over a field $\mathsf{k}$ of zero characteristic does not satisfies any polinomial identity. If it were a PI-algebra, Kaplansky theorem would apply (since ...
jg1896's user avatar
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2 votes
1 answer
267 views

Existence of finite dimensional representation of an algebra

Let $m>1$ be an integer and let $A$ be the algebra generated by the elements $\{u^i_j,v^i_j,\bar{u}^i_j, \bar{v}^i_j| 1\leq i,j\leq m\}$ quotient over the relations \begin{eqnarray} u^i_j v^k_l&...
Zhiyuan Wang's user avatar
40 votes
9 answers
10k views

Simplest examples of rings that are not isomorphic to their opposites

What are the simplest examples of rings that are not isomorphic to their opposite rings? Is there a science to constructing them? The only simple example known to me: In Jacobson's Basic Algebra (...
Amritanshu Prasad's user avatar
7 votes
1 answer
457 views

Are perfect complexes the same as compact objects in D(R) for noncommutative rings?

The Stacks Project proves Thomason's insight that compact objects of the derived category $\simeq$ bounded complexes of finitely generated projective modules in Section 15.78, but the running ...
theblue7's user avatar
64 votes
4 answers
8k views

What is the current status of the Kaplansky zero-divisor conjecture for group rings?

Let $K$ be a field and $G$ a group. The so called zero-divisor conjecture for group rings asserts that the group ring $K[G]$ is a domain if and only if $G$ is a torsion-free group. A couple of good ...
Johan Öinert's user avatar
2 votes
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71 views

Classification of polynomials leading to finite dimensional admissible algebras

Let $K \langle x , y \rangle $ ($K$ a field, we can assume it has only two elements if it helps) be the non-commutative polynomial ring in 2 variables. Question 1: For which non-commutative ...
Mare's user avatar
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5 votes
2 answers
321 views

Cubical vs. simplicial Hochschild cohomology

Simplicial Hochschild cohomology. $\newcommand{\Hom}{\mathrm{Hom}}\newcommand{\B}{\mathrm{B}}\newcommand{\Obj}{\mathrm{Obj}}\newcommand{\HH}{\mathrm{HH}}\newcommand{\Mod}{\mathsf{Mod}}$One way to ...
Emily's user avatar
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1 vote
2 answers
333 views

Condition for equality of modules generated by columns of matrices

Let $R$ be a commutative ring with unit. Let $M_A$ denote the submodule of $R^m$ generated by columns of a matrix $A$ with entries in $R$. Suppose we are given two matrices $A,B \in R^{m \times k}$. I ...
Rahul Sarkar's user avatar
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111 views

Correct notion of "connected" for dga of bundle-valued forms

Consider a vector bundle $E$ over a manifold $M$ with flat connection, $\nabla$. From this data I can form the associative/unital differential graded algebra $\mathcal{A} = \left(\Omega^{\bullet}(M, ...
cheyne's user avatar
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Extension of work by Novelli and Thibon on noncommutative symmetric functions and Lagrange inversion

(Edit May 12, 2023: I just put up a brief summary of some of my notes on the partition polynomials described below in my WordPress mini-arXiv at "As Above, So Below". It contains multinomial ...
Tom Copeland's user avatar
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21 votes
1 answer
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Is there any non-commutative ring such that every element other than the identity is a zero divisor?

A (unital) ring $R$ with the property that every element other than the identity $1_R$ is a (two-sided) zero divisor, seems to be commonly called a "$0$-ring" or "$\mathcal O$-ring"...
Salvo Tringali's user avatar
4 votes
0 answers
80 views

Indecomposable injectives over Weyl algebras

Let $A=A_n(\mathbb{C})$ be the $n$-th Weyl algebra over the complex field. Then $A$ is a left Noetherian noncommutative ring. Is there a complete classification of indecomposable injective $A$-modules?...
Doug Liu's user avatar
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3 votes
1 answer
308 views

Projective dimension of group ring

Assume that $G$ is a group and $R$ is a p.i.d. What can we say about the projective dimension of $R[G]$? For example can we say that this dimension is at most $1$ for reductive groups? (I think if $...
ali's user avatar
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4 votes
0 answers
105 views

Convolution algebra of a simplicial set

Consider a simplicial set $X^\bullet$ with face maps $d_i$ (assume the set is finite in each degree so there are no measure issues). Then given two functions $f,g:X^1\to \mathbb{C}$ one can form their ...
Josh Lackman's user avatar
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5 votes
1 answer
400 views

Injective modules

Let $A$ be a finite dimensional $k$-algebra and let $I$ be an injective module。My question is whether $I$ is a direct sum of finite-dimensional injective modules。
Sun YongLiang's user avatar
3 votes
1 answer
377 views

Graded global dimension of a graded algebra

Let $k$ be an algebraically closed field of characteristic $0$. Let $A := k \langle x,x^{-1},y \rangle /(xy-qyx, x^{d_1}-ay^{d_2})$, where deg$(x)>0$, deg$(y)>0$, $q,a \in k^*$ and $d_1\text{deg}...
YkMz's user avatar
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7 votes
1 answer
179 views

Symmetry of unique generator property

In this article: Canfell, M. J. "Completion of Diagrams by Automorphisms and Bass′ First Stable Range Condition." Journal of algebra 176.2 (1995): 480-503. the author defines a ring $R$ to ...
rschwieb's user avatar
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1 vote
0 answers
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Inner product on Standard form of von Neumann algebra

Let $(M, H, H_+,J)$ be a standard form of a von Neumann algebra $M$ acting on a complex Hilbert space $H$ endowed with a self-dual cone $H_+$. Is it true that $$\langle x,yz\rangle=\langle zx,y\rangle$...
Guest's user avatar
  • 131
22 votes
5 answers
4k views

Motivation for the Preprojective Algebra

Let $Q=(Q_0,Q_1)$ be a quiver and $k$ a field. We construct a new quiver $\bar{Q}$ in the following way. Let the vertices of $\bar{Q}$ be the same as the vertices of $Q$, and let the arrows of $\bar{Q}...
Sondre's user avatar
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0 answers
108 views

Does the center of any finitely generated associative algebra over a field have finite type?

Consider the monoid algebra $R:=K\langle x_1,\dots,x_n\rangle$ generated by $n$ letters $x_1,\dots,x_n$ for $n>1$ over field $K$. Equivalently, $R$ is the tensor algebra $T(V)$ on the $n$-...
GiS's user avatar
  • 331
7 votes
1 answer
284 views

Does the choice of the algebraically closed field of characteristic $p$ have influence on the module category?

Let $G$ be a finite group and $p$ be a prime number dividing $|G|$. Let $k$ be the algebraic closure of $\mathbb{F}_p$. Let $K$ be another algebraically closed field of characteristic $p$ which is not ...
LSt's user avatar
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3 votes
1 answer
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When are simple holonomic D-modules of the form $\mathcal{D}/\mathcal{D}L$?

Let $\mathcal{D}=\mathcal{D}_X$ be the sheaf of rings of differential operators on a smooth algebraic curve $X$. Since $\dim X=1$, the D-modules of the form $\mathcal{D}/\mathcal{D}L$ are necessarily ...
Gabriel's user avatar
  • 721
6 votes
2 answers
449 views

Survey of recent developments of the Gelfand-Kirillov dimension

It is almost two decades since the now classical books by McConnell and Robinson's [ Noncommutative Noetherian rings. With the cooperation of L. W. Small. Revised edition. Graduate Studies in ...
jg1896's user avatar
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11 votes
1 answer
520 views

Problems concerning subspaces of $M_{n}(\mathbb{Q}) $

Let $M_{n}(\mathbb{Q}) $ denote the $n$ times $n$ matrices over the rational number field. $N$ be a subspace of $M_{n}(\mathbb{Q}) $.Then if all the non-zero matrices in $N$ are invertible, what is ...
Sky's user avatar
  • 923
4 votes
2 answers
586 views

Brauer group of $\mathbb{Z}_{(p)}$

This may be a well known result but I could not find it in the standard references. What is the Brauer group of the local ring $\mathbb{Z}_{(p)}$ (the ring of integers localized at $p$)?
user123's user avatar
  • 81
4 votes
0 answers
178 views

Finitistic dimension conjecture — why artin algebras?

As I understand it, the finitistic dimension conjecture says that if a ring $A$ is finitely generated over a commutative artinian ring $K$, then the finitistic dimension of $A$ is finite. My question ...
Finitistic dimension's user avatar
2 votes
1 answer
181 views

Relation(s) between units and nilpotent elements in graded noncommutative rings

In Commutative Algebra we have the following standard facts which I am going to state in a slightly different form than usually found in textbooks. Namely, let $A$ be a commutative unital ring of ...
M.G.'s user avatar
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5 votes
1 answer
330 views

About a recent paper of Rickard on finitistic dimension

Apologizes if this is a basic question, but I am new to the area of finite dimensional algebras. I am reading the paper "Unbounded derived categories and the finitistic dimension conjecture" ...
Reading finitisitic's user avatar
7 votes
1 answer
281 views

Question concerning the coefficients of block idempotents

Let $G$ be a finite group. Let $p$ be a prime number such that $p \mid |G|$. Let Irr$(G)$ denote the set of ordinary irreducible characters of $G$. For $\chi\in$ Irr$(G)$ define $e_{\chi} := \frac{\...
Bernhard Boehmler's user avatar
5 votes
1 answer
300 views

Quasi-coherent cohomology in non-commutative algebraic geometry

In non-commutative algebraic geometry, the motto so to speak is to replace the study of a scheme $X$ with the study of the category $D_{qcoh}(X)$ of quasi-coherent sheaves and study the properties ...
curious math guy's user avatar
1 vote
0 answers
69 views

Structure of tame concealed algebra of Euclidean type

I wanted to know some references where people have studied the representation theory of tame concealed algebra of Euclidean type. What do we know about the structure of their module category? What ...
It'sMe's user avatar
  • 839
11 votes
3 answers
909 views

Does Morita theory hint higher modules for noncommutative ring?

Two possibly noncommutative rings are called Morita equivalent if their left-module categories are equivalent. In the commutative case, Morita equivalence is nothing more than ring isomorphism. ...
Student's user avatar
  • 5,230
1 vote
0 answers
35 views

Number of right divisors of a central skew polynomial

Let $\mathbb{F}$ be a finite field of $p$ elements, $\sigma \in \operatorname{Aut}(F)$ of order $m$, $\mathbb{F}^\sigma$ be the fixed field of $\sigma$, and $\mathbb{F}[x,\sigma]$ be a skew polynomial ...
a196884's user avatar
  • 323
8 votes
2 answers
2k views

Reason to apply the Koszul sign rule everywhere in graded contexts

The Koszul sign rule is a sign rule that arises from graded-commutative algebras. For instance, let $\bigwedge(x_1,\dots, x_n)$ be the free graded-commutative algebra generated by $n$ elements of ...
Javi's user avatar
  • 499
4 votes
0 answers
106 views

Regular coherence of tensor algebras

Under what conditions on a bimodule $M$ over a noetherian commutative ring $R$ is the tensor algebra $T=T_R(M)$ regular coherent? A theorem of Gersten says this is true for a free bimodule $M$. If $M$ ...
Willie C's user avatar
3 votes
1 answer
300 views

RIng that is flat over a subring as a right module but not as a left module

What is an example of a ring $R$ and a subring $S \subseteq R$ such that $R$ is flat as a right module but not flat as a left module. The following question is my motivation: Faithful flatness for ...
Alain Rochefort's user avatar
2 votes
1 answer
287 views

On the definition of the Cherednik algebra of a variety with a finite group action

Let $X$ be a connected complex smooth affine variety, acted on by a finite group $G$. We define a reflection hypersurface $(Y,g)$ as a smooth codimension one subvariety $Y\subset X$ which is fixed by $...
FPV's user avatar
  • 541
8 votes
0 answers
354 views

Rough paths, unparametrized path space, and Kontsevich's moduli space of stable maps

Let $X$ be a manifold. Modulo reparametrization, the path space of $X$ is a groupoid $\Pi_X$. In Kapranov's "Free Lie Algebroids and the Space of Paths", Kapranov constructs an associated ...
John Rached's user avatar
2 votes
0 answers
172 views

Simple modules of quantum planes

Let $k$ be an algebraically closed field. Let $R := k\langle x,y \rangle/(yx-qxy) (q \in k^*)$. We often call $R$ a quantum plane. If $q$ is a primitive $n$-th root, then for any $(\zeta, \xi) \in k^* ...
YkMz's user avatar
  • 889
5 votes
1 answer
175 views

Finding non-inner derivations of simple $\mathbb Q$-algebras

What's a good example of a simple algebra over a field of characteristic $0$ which has a non-inner derivation but also has the invariant basis number property (IBN)? I'm under the impression that when ...
rschwieb's user avatar
  • 1,507
2 votes
1 answer
246 views

The combinatorics of $(f \partial)^n$ in the noncommutative setting?

This is a noncommutative version of these three previous questions: differential operator power coefficients Сlosed formula for $(g\partial)^n$ A Leibniz-like formula for $(f(x) \frac{d}{dx})^n f(x)$? ...
M.G.'s user avatar
  • 7,127
45 votes
8 answers
6k views

What makes a theorem *a* "nullstellensatz."

I know what the (Hilbert) Nullstellensatz says. A MathSciNet search on "nullstellensatz" turns up nearly 200 papers, with only a minority offering either new proofs or new applications of the classic ...
5 votes
1 answer
266 views

Rings s.t. each element has a power lying in the center (and their completely prime ideals)

Let $R$ be a ring (throughout, all rings are associative and unital). We say $R$ satisfies condition (C) if, for every $a \in R$, there exists an integer $n \ge 1$ (depending on $a$) such that $a^n$ ...
Salvo Tringali's user avatar
1 vote
0 answers
87 views

Abelianization of the group of invertible elements in a finite local ring

Let $R$ be a finite local $\mathbb{F}_q$-algebra. Assume that $R\cong R^*$ as left $R$-modules. Are there any known results about the abelianization $(R^{\times})_{\mathrm{ab}}$? (We can factor $R$ be ...
Ehud Meir's user avatar
  • 5,039
0 votes
3 answers
1k views

non-associative but commutative algebra [closed]

Is it possible(or may be easier) to give an example of non associative algebra but commutative? At first sight, it seems possible to prove associativity from commutativity but later realised it may no ...
Sunny's user avatar
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