All Questions
4 questions
13
votes
4
answers
2k
views
Why does (Ribbon) Graph (co)Homology Compute (co)Homology of MCG?
The title says it all. I am looking for an explanation or reference for why the homology of the ribbon graph complex computes the cohomology of the mapping class groups of surfaces.
I've seen ...
4
votes
1
answer
195
views
Stable cohomology of mapping class group with coefficients in $H^{\otimes n}$
Let $\text{Mod}_g$ be the mapping class group of a closed oriented genus-$g$ surface $\Sigma_g$ and let $H = H_1(\Sigma_g;\mathbb{Q})$. Fix some $r \geq 0$. It is known that the cohomology group $H^...
4
votes
1
answer
805
views
Homology dimension of the mapping class group of a surface with boundary
There is a result on the dimension bound for ${M_{g,n}}/S_n$, (the moduli space for Riemann surfaces of genus $g$ with $n$ marked points) that is
$H_{i}({M_{g,n}}/S_n)=0$, for $i\ge 6g-7+2n$ except $(...
2
votes
1
answer
1k
views
Question related to the moduli space of Riemann surfaces and a fibration
If $M_{g}$ is the moduli space of Riemann surface of genus $g$, $M^1_{g}$ is the moduli space of Riemann surface of genus $g$ with one boundary, how can we show that the natural map:
$M^1_{g} \...