Questions tagged [lo.logic]

first-order and higher-order logic, model theory, set theory, proof theory, computability theory, formal languages, definability, interplay of syntax and semantics, constructive logic, intuitionism, philosophical logic, modal logic, completeness, Gödel incompleteness, decidability, undecidability, theories of truth, truth revision, consistency.

Filter by
Sorted by
Tagged with
3 votes
0 answers
43 views

How exactly are realizability and the Curry-Howard correspondence related?

Consider, on the one hand: the Curry-Howard correspondence between, on the one hand, types and terms (programs) in various flavors of typed $\lambda$-calculus, and on the other, propositions and ...
Gro-Tsen's user avatar
  • 28.3k
-1 votes
1 answer
65 views

How to prove that increasing the number of constant symbols of a first-order logic by the number of formulas keeps the number of formulas the same [closed]

Let $S$ be a set of theory symbols for a first-order logic, and let $C$ be a set of constant symbols in $S$ such that $|C| = |L(S)|$, where $L(S)$ is the set of all formulas generated by $S$ in the ...
Andrew's user avatar
  • 3
2 votes
0 answers
46 views

Can the set of parafinite congruences be descriptive-set-theoretically complicated?

Fix an algebra $\mathfrak{A}$ with underlying set $\mathbb{N}$ and finite language $\Sigma$. The set of congruences on $\mathfrak{A}$ is a closed subset $C_\mathfrak{A}$ of $2^\mathbb{N}$ (with the ...
Noah Schweber's user avatar
0 votes
1 answer
107 views

Congruences that aren't "finite from above," take 2: semigroups

This is a hopefully less trivial version of this question. Briefly, say that a congruence is parafinite if it is the largest congruence contained in some equivalence relation with finitely many ...
Noah Schweber's user avatar
4 votes
3 answers
396 views

Congruences that aren't "finite from above"

Let $\mathfrak{A}=(A;...)$ be an algebra in the sense of universal algebra. Say that a congruence $\sim$ on $\mathfrak{A}$ is parafinite iff there is an equivalence relation $E\subseteq A^2$ with ...
Noah Schweber's user avatar
0 votes
0 answers
101 views

Is "$\gamma$ is admissible" necessary in lemma V.5.10, Constructibility, Devlin?

This lemma is an early step of the proof of Jensen's covering lemma. I feel that in this lemma, "$\gamma$ is admissible" is not required. $\gamma$ being a limit ordinal is enough. In the ...
Reflecting_Ordinal's user avatar
9 votes
1 answer
460 views

Con(PA) via non-well-foundedness?

Lumsdaine made the following interesting comment: if Con(PA) fails in a non-standard model, it means it contains a “proof of non-standard length” of a contradiction from PA. With a little work, one ...
Mikhail Katz's user avatar
  • 14.8k
6 votes
0 answers
82 views

Locally presentable and accessible categories without the axiom of choice?

Is there a good reference for the study of locally presentable and accessible categories without the axiom of choice? For instance, it seems one will need to understand: What is a good notion of $\...
Tim Campion's user avatar
  • 58.6k
1 vote
0 answers
266 views

What's the definition of a mouse in Mitchell's handbook article "the covering lemma"?

In the book "handbook of set theory", in the chapter "the covering lemma", definition 3.24, Mitchell defines what is mouse. However he did not give any definition of $\mathcal{U}_\...
Reflecting_Ordinal's user avatar
9 votes
2 answers
2k views

Is GCH useful in proving theorems?

By GCH I mean the Generalized Continuum Hypothesis. Let me give some context before presenting my question. When the axiom of choice was introduced by Zermelo in his 1904 proof of Well-Ordering ...
jg1896's user avatar
  • 2,445
1 vote
0 answers
13 views

Reference request for dinatural transformations arising from free Cartesian closed categories

Let $g_n$ be a discrete graph with $n$ nodes and $\operatorname{F}$ the free functor of the adjunction between the category of graphs and the category of Cartesian closed categories and functors, as ...
Johan Thiborg-Ericson's user avatar
6 votes
1 answer
174 views

Is the Rado graph the unique countable graph that has all finite graphs as induced subgraphs?

I understand that since the Rado graph is the Fraïsse limit of the class of finite graphs, it is the unique homogeneous graph with this property. Is there another graph not isomorphic to the Rado ...
Vilhelm Agdur's user avatar
5 votes
0 answers
116 views

Elementary equivalence for rings

Let $\mathcal{L}$ be a first-order language, and $M$ and $N$ be two $\mathcal{L}$-structures. We say that $M$ and $N$ are elementarily equivalent (write $M \approx N$) if they satisfy the same first-...
jg1896's user avatar
  • 2,445
6 votes
2 answers
522 views

Is "the purely probabilistic version of Freiling's axiom of symmetry" disprovable in ZFC?

I'm trying to pinpoint the "intuitive argument" for Freiling's Axiom of Symmetry. It's meant to be a "probabilistic" argument, so thinking about what seems to me to be the ...
Julian Newman's user avatar
2 votes
1 answer
115 views

Posets of equational theories of "bad quotients"

This is a follow-up to an older question of mine: Suppose $\mathfrak{A}=(A;...)$ is an algebra (in the sense of universal algebra) and $E$ is an equivalence relation - not necessarily a congruence - ...
Noah Schweber's user avatar
1 vote
1 answer
210 views

Hahn-Banach theorem and ultrafilter lemma

I'm unable to understand a remark in "Two application of the method of construction by ultrapowers to analysis" by Luxemburg, which uses the ultrafilter lemma to prove the Hahn-Banach ...
oggius's user avatar
  • 75
5 votes
0 answers
249 views

An imaginary disaster scenario - second order arithmetic is inconsistent

I think my question is a natural follow up of What would be some major consequences of the inconsistency of ZFC? Regarding the later question, I agree with the commentaries that probably an ...
jg1896's user avatar
  • 2,445
6 votes
1 answer
276 views

Proving finiteness in Reverse Mathematics

In (second-order) Reverse Mathematics, a (code for an) open set $U\subset \mathbb{R}$ is given by two sequences of rationals $(a_n)_{n \in \mathbb{N}}, (b_n)_{n \in \mathbb{N}}$. The idea is that $U$ ...
Sam Sanders's user avatar
  • 3,657
-4 votes
0 answers
75 views

Is the following combinatorial identity correct? $\sum_{k=1}^{n}k \cdot 2^k = n \cdot 2^n$ [closed]

During my studies in mathematical logic, I learned a new concept called a truth table. I saw as an example that for $3$ atoms, in the context of a binary connector, there are $8$ different cases for ...
Bulldog On Steak's user avatar
3 votes
1 answer
106 views

Classes of algebras axiomatizable by special formulas; and free objects

Let $\mathcal{L}$ be a first-order language without relation symbols, and let $\mathcal{K}$ be a class of $\mathcal{L}$-algebras. $\mathcal{K}$ is axiomatizable if there is a set $T$ of first-order ...
jg1896's user avatar
  • 2,445
3 votes
1 answer
176 views

Is Morse-Kelley set theory with Class Choice bi-interpretable with itself after removing Extensionality for classes?

Let $\sf MKCC$ stand for Morse-Kelley set theory with Class Choice. And let this theory be precisely $\sf MK$ with a binary primitive symbol $\prec$ added to its language, and the following axioms ...
Zuhair Al-Johar's user avatar
11 votes
5 answers
1k views

In what sense does the sentence $\operatorname{con}(\mathsf{PA})$ "say" that $\mathsf{PA}$ is consistent?

It seems common amongst logicians to think of "truth" as being relative to a particular structure. Consider, for instance, the first-order theory of groups. The sentence $\forall x\forall y(...
Joe's user avatar
  • 119
1 vote
1 answer
72 views

Sizes of linearly ordered subalgebras of powers

On the grounds that I'm currently teaching a linear algebra class and I enjoy making my students furious, let a linear algebra be an algebra $\mathcal{A}$ in the sense of universal algebra equipped ...
Noah Schweber's user avatar
22 votes
4 answers
3k views

A Löwenheim–Skolem–Tarski-like property

I am interested in the following Löwenheim–Skolem–Tarski-like property. Given a cardinal $\kappa$, what (if any) is a property $\phi(x)$ such that if $\phi(\kappa)$ holds, then we can prove the ...
Nai-Chung Hou's user avatar
8 votes
1 answer
268 views

Two notions of generalized quotient/substructure

Given a language $\Sigma$ and a $\Sigma$-algebra (in the sense of universal algebra) $\mathcal{A}=(A;\dotsc)$ and a function $f:A\rightarrow A$, let $\mathcal{A}_f$ be the $\Sigma$-algebra whose ...
Noah Schweber's user avatar
13 votes
1 answer
1k views

Are Berkeley cardinals easier to refute in ZFC than Reinhardt cardinals?

Kunen showed that Reinhardt cardinals are inconsistent in ZFC. But his proof is a bit technical for a non-set-theorist to follow. Berkeley cardinals are stronger than Reinhardt cardinals. You can ...
Tim Campion's user avatar
  • 58.6k
17 votes
3 answers
2k views

Why is an internal proof of consistency satisfactory for some systems?

I've only a shallow understanding of the relevant theory, but I don't understand how any internal proof of consistency is in any way satisfactory (even for systems that are so weak Gödel's ...
student25's user avatar
  • 171
4 votes
2 answers
260 views

Hyperarithmetically least elements in $\Pi^1_1$ sets

My question is: Do we have a hyperarithmetically $\le_H$-least real in any $\Pi^1_1$ set? That is Question. Suppose that $A$ is a non-empty $\Pi^1_1$ set. Then can we find a real $a\in A$ such that $...
Hanul Jeon's user avatar
  • 2,412
7 votes
0 answers
158 views

Strengthening Determinacy in constructive set theory?

Recall how games work. Let $X$ be a set (the "game space") and $\alpha$ an ordinal (the "game clock"). Alice and Bob take turns naming elements of $X$. We write them down in order ...
Tim Campion's user avatar
  • 58.6k
3 votes
2 answers
297 views

Are there $2^{\aleph_0}$ pairwise non-isomorphic countable groups containing every finite group?

Let us call a group $(G,\cdot)$ finitarily complete if $G$ is countable, and every finite group is isomorphic to a subgroup of $(G,\cdot)$. Is there a collection of $2^{\aleph_0}$ pairwise non-...
Dominic van der Zypen's user avatar
11 votes
0 answers
277 views

Can Friedman's property fail at or above a supercompact cardinal?

If $\kappa>\omega_1$ is a regular cardinal, $FP_\kappa$ is the assertion that every stationary subset of $\kappa$ consisting of ordinals of countable cofinality has a closed subset of order type $\...
Ben Goodman's user avatar
2 votes
0 answers
58 views

Relation of top and bottom types given multiple universes

This is something that I haven't seen mentioned in any literature. In a type theory (extensional, intuitionistic, Martin Lof variant), given two ordered Tarski Universes such that $U_i < U_{i+1}$, ...
Daniel Smith's user avatar
3 votes
0 answers
117 views

Can well-ordering of the universe due to global choice survive extensive failure of Extensionality?

That axiom of global choice leads to the well-ordering of the universe given the other axioms of Zermelo set theory is a famous result. Now, if we weaken the power set axiom to the axiom stating that ...
Zuhair Al-Johar's user avatar
4 votes
1 answer
117 views

$\aleph_0$-uniform non-bipartite linear hypergraph

A hypergraph $H= (V,E)$ is said to be bipartite if there is $S\subseteq V$ such that for all $e\in E$ with $|e|>1$ we have $$S\cap e\neq \emptyset\neq (e\setminus S).$$ A hypergraph is said to be ...
Dominic van der Zypen's user avatar
5 votes
0 answers
161 views

Complexity implications on computability

Are there any known links between complexity theory and computability theory by which I mean non-trivial theorems of the form: If NP $\neq$ co-NP then there is no strong minimal pair of r.e. sets or ...
Peter Gerdes's user avatar
  • 2,531
2 votes
1 answer
561 views

"Potency set" for power set?

Cross-posted at HSM. Has the term "potency set" been used in English language mathematics for power set, and, if so, what are good references? It is relevant that for historical reasons, &...
Frode Alfson Bjørdal's user avatar
3 votes
1 answer
105 views

Oscillation functions and similar constructs

For given $f$ from reals to reals, the associated oscillation function is defined as follows: $$\textstyle osc_f(x):= \lim_{n\rightarrow \infty} [\sup_{y \in B(x, \frac{1}{2^n}) } f(y)-\inf_{z \in B(x,...
Sam Sanders's user avatar
  • 3,657
14 votes
1 answer
471 views

Extensions of $PA+\neg Con(PA)$ with large consistency strength

There is a large hierarchy of theories strengthening $PA$ eg $PA+Con(PA)$, $PA+Con(PA+Con(PA))$,..., second-order arithmetic and $ZFC$, ordered by consistency strength. Is there an extension of $PA+\...
Tom Bouley's user avatar
8 votes
0 answers
167 views

The approximate mean value theorem / Rolle's theorem in pure constructive mathematics

In the replies of this very similar question, there is a fascinating answer that is beautiful in its simplicity. In particular, it seems to use perhaps the most minimal assumptions one can possibly ...
SpectreDNZ's user avatar
12 votes
2 answers
378 views

Trading Choice for Comprehension (or Replacement)

This question is basically a request for clarification about a remark made by Sam Sanders in a comment to another question: IIUC what he's saying, there are statements that can be proved either with a ...
Gro-Tsen's user avatar
  • 28.3k
2 votes
1 answer
149 views

Does allowing Ur-elements in $\sf ZF^*GC$ break bi-interpretability with $\sf ZF^*GC$?

Is $(\sf ZF^*GC - Extensionality)$ bi-interpretable with $\sf ZF^*GC$? Where $\sf ZF^*GC$ is $\sf ZF - Replacement + Separation + Collection + Global \ Choice$
Zuhair Al-Johar's user avatar
8 votes
1 answer
322 views

"Compactness length" of Baire space

Intuitively, my question is: how many times do we have to mod out by an closed equivalence relation with all classes compact in order to collapse Baire space $\omega^\omega$ to a singleton? In more ...
Noah Schweber's user avatar
6 votes
1 answer
397 views

A strange product forcing

Given two forcing notions $\mathbb{P}_0,\mathbb{P}_1$, we know that the product $\mathbb{P_0}\times\mathbb{P_1}$ will produce the following diagram of models ordered by inclusion: where $M$ is the ...
Lorenzo's user avatar
  • 1,980
2 votes
1 answer
162 views

What's the benefit of adding a well-ordering over all classes to $\textsf{MK}$?

Working in $\textsf{ZF} + \text {there is a strongly inaccessible cardinal}$. Let $\kappa$ be the first strongly inaccessible cardinal, and let $\lvert V_\kappa\rvert= \kappa$, then $(V_{\kappa+1}, \...
Zuhair Al-Johar's user avatar
9 votes
1 answer
326 views

Natural set-theoretic principles implying the Ground Axiom

The Ground Axiom states that the set-theoretic universe is not a set-forcing extension of an inner model. By Reitz, it is first-order expressible and easy to force over any given ZFC model with class-...
Monroe Eskew's user avatar
  • 17.8k
7 votes
0 answers
171 views

Does the Affine Pappus Axiom imply the Affine Desargues Axiom in affine planes?

I am interested in the affine version of the well-known Hessenberg's Theorem (saying that Pappian projective planes are Desarguesian). First I introduce all necessary definitions. Definition L. A ...
Taras Banakh's user avatar
  • 40.1k
2 votes
0 answers
113 views

Can this theory of classes of ordinals interpret ZFC?

The following theory is a theory of classes of ordinals. Language: Bi-sorted FOL with identity. First sort in lower case ranging over ordinals. Second sort in upper case ranging over classes of ...
Zuhair Al-Johar's user avatar
7 votes
5 answers
2k views

Standard models of N and R: An Alice/Bob approach

This is a question about a comment in a recent publication by Roman Kossak. Kossak wrote: "Nonstandardness in set theory has a different nature. In arithmetic, there is one intended object of ...
Mikhail Katz's user avatar
  • 14.8k
6 votes
0 answers
187 views

Reference for Understanding Shelah's Proof of Vaught's Conjecture for $\omega$-stable Theories

I'm looking for a source to help me better understand Shelah's proof of Vaught's Conjecture for $\omega$-stable Theories (https://shelah.logic.at/files/95409/158.pdf). An obvious candidate is Makkai's ...
Tesla Daybreak's user avatar
3 votes
1 answer
291 views

Second order theory of a real-closed field

It is well known that the first-order theory of any real-closed field is complete, and consequently not capable of interpreting the majority of modern mathematics. Is this still true for the second-...
Alec Rhea's user avatar
  • 8,878

1
2 3 4 5
100