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3 votes
2 answers
392 views

Monotonicity of matrix conjugation

Let $A$ and $B$ be positive-definite matrices such that $A \le B.$ By matrix monotonicity of the root, this also implies that $A^{\alpha} \le B^{\alpha}$ for $\alpha \in [0,1].$ I am now curious under ...
António Borges Santos's user avatar
1 vote
1 answer
241 views

Monotonicity of eigenvalues II

In a previous question here, I asked the question below for block matrices and received an answer showing the question is true if $\mathcal B$ is hermitian and false, in general if $\mathcal B$ is non-...
Sascha's user avatar
  • 536
6 votes
1 answer
601 views

Monotonicity of eigenvalues

We consider block matrices $$\mathcal A = \begin{pmatrix} 0 & A\\A^* & 0 \end{pmatrix}$$ and $$\mathcal B = \begin{pmatrix} 0 & B\\C & 0 \end{pmatrix}.$$ Then we define the new matrix $...
Sascha's user avatar
  • 536
1 vote
1 answer
195 views

Eigenvalues of operator

In the question here the author asks for the eigenvalues of an operator $$A = \begin{pmatrix} x & -\partial_x \\ \partial_x & -x \end{pmatrix}.$$ Here I would like to ask if one can extend ...
Kung Yao's user avatar
  • 192
7 votes
1 answer
204 views

Are $\log(\sigma(A(z))$ subharmonic functions?

Let $A$ be a matrix-valued entire function. It is then well-known that $\log \Vert A(z)\Vert$ is subharmonic. In particular, the operator norm is just the largest singular value of $A$. Is it ...
Pritam Bemis's user avatar
6 votes
0 answers
107 views

Eigenvalues of splitting scheme

In numerical analysis it is common to approximate a solution to a PDE $$u'(t) = (A+B) u(t), \quad u(0)=u_0$$ which is just given by $e^{t(A+B)}u_0$ by the splitting $e^{tB/2} e^{tA} e^{tB/2}u_0.$ Here,...
Sascha's user avatar
  • 536
3 votes
1 answer
115 views

Approximation of vectors using self-adjoint operators

Let $T$ be an unbounded self-adjoint operator. Does there exist, for any $\varphi$ normalized in the Hilbert space, a constant $k(\varphi)>0$ and a sequence of normalized $(\varphi_n)$ such that $$...
Landauer's user avatar
  • 173
1 vote
1 answer
2k views

Positive matrix and diagonally dominant

There is a well-known criterion to check whether a matrix is positive definite which asks to check that a matrix $A$ is a) hermitian b) has only positive diagonal entries and c) is diagonally ...
Xin Wang's user avatar
  • 183
2 votes
3 answers
216 views

Equivalence of operators

let $T$ and $S$ be positive definite (thus self-adjoint) operators on a Hilbert space. I am wondering whether we have equivalence of operators $$ c(T+S) \le \sqrt{T^2+S^2} \le C(T+S)$$ for some ...
van Dyke's user avatar
4 votes
2 answers
871 views

Decay of eigenfunctions for Laplacian

Consider the discrete second derivative with Dirichlet boundary conditions on $\mathbb C^n$. Its eigendecomposition is fully known: see wikipedia It seems like the largest eigenvalue $\lambda_1$ is ...
Yannis Pimalis's user avatar
3 votes
0 answers
163 views

Perturbation theory compact operator

Let $K$ be a compact self-adjoint operator on a Hilbert space $H$ such that for some normalized $x \in H$ and $\lambda \in \mathbb C:$ $\Vert Kx-\lambda x \Vert \le \varepsilon.$ It is well-known ...
user avatar
8 votes
2 answers
323 views

Matrix rescaling increases lowest eigenvalue?

Consider the set $\mathbf{N}:=\left\{1,2,....,N \right\}$ and let $$\mathbf M:=\left\{ M_i; M_i \subset \mathbf N \text{ such that } \left\lvert M_i \right\rvert=2 \text{ or }\left\lvert M_i \right\...
André's user avatar
  • 225
5 votes
1 answer
1k views

The spectrum of the discrete Laplacian

Consider a connected (we define connected components by defining the set of vertices where every vertex has one neighbour) sublattice $V$ of the square lattice $V \subset\mathbb{Z}^2.$ On this we ...
Dr. House's user avatar
2 votes
2 answers
446 views

Entrywise modulus matrix and the largest eigenvector

Disclaimer. This is a cross-post from math.SE where I asked a variant of this question two days ago which has been positively received but not has not received any answers. Let $A$ be a complex ...
Julian's user avatar
  • 623