Skip to main content

All Questions

Filter by
Sorted by
Tagged with
3 votes
0 answers
64 views

Metrically homogeneous spaces as inverse limits

Let $(X,d)$ be a locally compact, separable, connected and $\sigma$-compact metric space such that the group of isometries $G$ acts transitively on $X$. The question is the following: Is $X$ ...
user44172's user avatar
  • 541
2 votes
2 answers
423 views

Lie (and topological) group extensions of $\mathbb{R}^2$ by $\mathbb{R}$

What are all the non-split Lie (and topological) group extensions $0 \to \mathbb{R} \to G \to \mathbb{R}^2 \to 0$? Here, $\mathbb{R}$ and $\mathbb{R}^2$ are regarded as Lie (and topological) groups ...
jap's user avatar
  • 125
2 votes
1 answer
282 views

Does every locally compact group G contain a maximal open subgroup P which is a pro-Lie group?

EDIT 1: All topological groups in this question are assumed to be second countable. In particular, this forces every group to be metrizable and every Lie group to have at most countably many ...
Cosine's user avatar
  • 609
2 votes
1 answer
101 views

Compact Lie groups as quotients of torsion-free compact metrizable groups

The question: (1) Is every compact Lie group $G$ isomorphic (as a topological group) to some quotient $H/N$ where $H$ is a torsion-free compact metrizable group? Or equivalently: (2) Is every compact ...
chj's user avatar
  • 157
2 votes
1 answer
216 views

How to prove that Chevalley groups over $\mathbb R$ have no compact factors

I am trying to see why the Chevalley groups (not limited to the adjoint group) over $\mathbb R$ are without compact factors in order to use the Borel density theorem. I've been told in another thread ...
Ami's user avatar
  • 332
2 votes
1 answer
182 views

Gelfand-Naimark and Peter-Weyl for the unitary group

Consider the compact Lie groups $U(l)$ (the unitary group) and $U(1) \times SU(l)$ for some natural number $l$. Both the groups have the same Lie algebra $\frak{gl}_l$. Which means that they both have ...
Jake Wetlock's user avatar
  • 1,144
2 votes
1 answer
82 views

Structure of extensions arising in Lie approximation of connected groups

My imperfect understanding is that, by the work of various authors (Gleason, Yamabe, Montgomery, Zippin ...), the following result is known: Let $G$ be a connected, locally compact, Hausdorff group, ...
Yemon Choi's user avatar
  • 25.8k
2 votes
1 answer
263 views

Profinite extension of a Lie group

Let $H,G,K$ be three topological groups, we say that $G$ is an extension of $K$ by $H$ if the following short sequence $$0\rightarrow H\rightarrow G\rightarrow K\rightarrow 0$$ is exact. (If $H$ is a ...
Lie groups's user avatar
2 votes
1 answer
571 views

On homeomorphic compact connected topological groups

I wish to thank Professor Claudio Gorodski for his very helpful answers to my question on the webcite: If compact connected Lie groups are homeomorphic as topological space, are they isomorphic as Lie ...
sife's user avatar
  • 491
2 votes
0 answers
85 views

Coherent states on compact abelian state spaces and complexification

First, to establish notation, let $T^*(M)$ denote the cotangent bundle of a manifold $M$. Let $\widehat{(-)}:= \hom_{\sf LCAbGrp}(-,\mathbb{T}):{\sf LCAbGrp}^{\sf op}\simeq {\sf LCAbGrp}$ denote the ...
Cole Comfort's user avatar
2 votes
0 answers
86 views

Homomorphisms from circle to $GL(k,\mathbb{R})$ [duplicate]

Example 3 at the website tricki proves that every measurable homomorphism of groups from the circle to the non-zero complex numbers is continuous. Is there any analogous (true) statement for ...
David Epstein's user avatar
2 votes
0 answers
91 views

Fixed point set with non-empty interior

Let $G$ be an infinite compact separable Hausdorff metric group, and $H\subset G$ a closed subgroup, such that the left $G$-action on $G/H$ is effective (i.e., $H$ doesn't contain a non-trivial closed ...
Bedovlat's user avatar
  • 1,959
2 votes
0 answers
80 views

Are the roots of an infinitely divisible probability infinitely divisible themselves?

Let $\mu$ be an infinitely divisible probability on a topological group $G$. If $\nu ^{* n} = \mu$ for some $n$, is $\nu$ an infinitely divisible probability too? A sufficient criterion would be to ...
Alex M.'s user avatar
  • 5,407
2 votes
0 answers
321 views

Surjective homomorphisms of non-connected Lie groups

Let $\psi\colon B\to C$ be a homomorphism of real Lie groups, where the group $C$ is connected. Let $B^0$ denote the identity component of $B$, and we set $\pi_0(B)=B/B^0$, then $\pi_0(B)$ is a ...
Mikhail Borovoi's user avatar
2 votes
0 answers
82 views

Uniquely divisible neighborhoods of identity in topological groups

Let $G$ be a (finite dimensional real) Lie group, and let $A\subset G$ be an open neighborhood of identity. If $A=\operatorname{Exp}(\mathcal{A})$ is the injective range of the exponential map from a ...
Bedovlat's user avatar
  • 1,959
2 votes
0 answers
62 views

Codistal subgroups of locally compact groups

Let $G$ be a topological group and let $H$ be a closed subgroup of $G$. Say $H$ is codistal in $G$ if the translation action of $G$ on the coset space $G/H$ is distal (meaning that no non-diagonal ...
Colin Reid's user avatar
  • 4,728
1 vote
2 answers
481 views

Cross section for closed Lie subgroup in a Lie group

Let $G$ be a Lie group and $H$ a closed Lie subgroup. Is there an explicit way to construct a local cross section of $H$ in $G$ so that $\pi: G\to G/H$ is a fiber bundle?
ruhi's user avatar
  • 23
1 vote
1 answer
111 views

Is every compact quasisimple group a Lie group?

Let $ G $ be a compact topological group which is quasisimple in the sense that $$ [G,G]=G $$ and $$ G/Z(G) $$ is simple as an abstract group. Must $ G $ be a Lie group? This is a follow-up question ...
Ian Gershon Teixeira's user avatar
1 vote
1 answer
338 views

distance between unitary and anti-unitary matrices

This question is related to the previous post, "A question about unitary and anti-unitary matrices". Following the suggestion of Lspice, I am posting it as a separate question, as it might ...
jacaboul's user avatar
  • 327
1 vote
0 answers
43 views

Continuous surjection from $X(D_n)$ onto $\operatorname{Homeo}_0(D_n)$

Let $n>1$ and let $\mathfrak{X}(D_n)$ denote the set of continuous vector fields on the closed disc $D_n\subseteq \mathbb{R}^n$. Let $\operatorname{Homeo}_0(D_n)$ be the set of homeomorphism of ...
ABIM's user avatar
  • 5,405
1 vote
0 answers
164 views

Continuous vs $L^2$ homomorphisms from circle to non-zero complex numbers

Let $T:S^1\to C^\ast$ be a group theoretic homomorphism from the circle to the non-zero complex numbers. Presumably it is true that if $T$ is $L^2$, then it is continuous. Is there a simple proof, or ...
David Epstein's user avatar
1 vote
0 answers
140 views

Describing compact Lie groups in purely topological terms

Compact Lie groups are a very special type of compact group, namely those which admit a differentiable structure. Is it possible to describe compact Lie groups in purely topological terms, that is, ...
Max Schattman's user avatar
1 vote
0 answers
121 views

A section over an orbit space

Let $G$ be a compact second countable Hausdorff group, and let $X=G/H$ be a homogeneous space with $H\subset G$ a closed subgroup. Let further $K\subset G$ be another closed subgroup. Questions: ...
Bedovlat's user avatar
  • 1,959
1 vote
0 answers
128 views

The group of polynomial homeomorphism of the plane

Let $G$ be the set of all homeomorphisms $f$ of $\mathbb{R}^2$ such that both $f$ and $f^{-1}$ are polynomial maps. We equip $G$ with the compact open topology and the obvious group ...
Ali Taghavi's user avatar
0 votes
1 answer
434 views

Reference request: Any connected Lie group has a countable base for its topology

I am looking for a reference for the assertion in the title. This assertion is proved in a comment of user nfdc23 to this question. Has any proof of this assertion been published?
Mikhail Borovoi's user avatar
0 votes
0 answers
98 views

An application of the Gleason-Montgomery-Zippin Theorem

In the book How groups grow by Avinoam Mann, the author cites the following theorem attributed to Gleason-Montgomery-Zippin. Theorem 6.4 (Gleason–Montgomery–Zippin: solution of Hilbert’s Fifth ...
Canno's user avatar
  • 1
0 votes
1 answer
83 views

Is the union of 1-dimensional pro-tori in a finite dimensional pro-torus dense?

Is the union of 1-dimensional compact connected abelian subgroups in a finite dimensional compact connected abelian group dense?
Mehmet Onat's user avatar
  • 1,367
0 votes
0 answers
267 views

Definition of reducible lattice

I am reading Raghunathan's book on discrete subgroups of Lie groups. In particular I am stuck on Corollary 5.19 which gives several equivalent conditions for a lattice in a semisimple Lie group to be ...
user551642's user avatar
-3 votes
4 answers
5k views

What is the situation with Hilbert's Fifth Problem?

The common knowledge in this regard seems to be that Hilbert's Fifth Problem was completely solved by Gleason, Montgomery, and Zippin. However, such wisdom was contested by Peter Olver: Olver, Peter ...
Elemer E Rosinger's user avatar

1
2