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19 votes
1 answer
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Fubini without CH

In Real and Complex Analysis, Rudin gives an example (due to Sierpinski) of a function $f:[0,1]^2\to[0,1]$ separately Lebesgue-measurable in each argument, such that $$ \int_0^1 dx\int_0^1f(x,y)\,dy \...
Aryeh Kontorovich's user avatar
7 votes
1 answer
381 views

Consistency of a strong Fubini type theorem for measure zero sets

Is the following statement (†) consistent with ZFC? If $E \subseteq [0,1]^2$ is such that $E_x := \{y\in[0,1] : (x,y)\in E\}$ has measure zero for almost all $x$, then $E^y := \{x\in[0,1] : (x,y)\in ...
Gro-Tsen's user avatar
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