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0 votes
2 answers
99 views

Is there an uncountable extension of the Ramsey set $[\omega]^2$?

We say that a family ${\cal A}\subseteq {\cal P}(\omega)$ is Ramsey if for every map $c:{\cal A}\to\{0,1\}$ there is an infinite set $X\subseteq \omega$ with the following properties: ${\cal A}\cap {\...
Dominic van der Zypen's user avatar
8 votes
1 answer
255 views

Maximal Ramsey families

We say that a family $\mathcal R\subseteq \mathcal P(\omega)$ is Ramsey if $\bigcup \mathcal R = \omega$, and for every map $f:\mathcal R \to \{0,1\}$ there is an infinite set $X\subseteq \omega$ ...
Dominic van der Zypen's user avatar
-3 votes
1 answer
73 views

Non-Ramsey function $f:[\omega]^{<\omega}\to\{0,1\}$ [closed]

Let $\newcommand{\o}{\omega}\o$ be the set of non-negative integers, and for any set $X$, let $\newcommand{\oo}{[\o]^{<\o}}X^{<\o}$ denote the collection of all finite subsets of $X$. What is an ...
Dominic van der Zypen's user avatar
1 vote
0 answers
95 views

A two-colouring of a complete graph over the set of incompressible strings

A two-coloring is done over the (infinite) set all incompressible strings (in some chosen alphabet); such that, an edge between two strings is blue if and only if, the strings are of equal lengths and ...
ARi's user avatar
  • 851
1 vote
0 answers
99 views

Group graphs and Ramsey theory. Sub-question 1

Question: Find/compute relations between the classical Ramsey numbers and their variations (described below) -- exact or asymptotic. A graph is a set $\ X\ $ together with a (coloring) function $\ c:\...
Wlod AA's user avatar
  • 4,776
6 votes
1 answer
284 views

Does every bijective graph endomorphism restrict to a full-cardinality isomorphism?

Given a graph $G$, and a bijective endomorphism $f$ (that is, a graph homeomorphism $f : G \to G$ that establishes a bijection on the vertices), it is true that $f$ is an automorphism whenever $|G|$ ...
Alex Meiburg's user avatar
  • 1,203
8 votes
1 answer
360 views

A combinatorial property of uncountable groups, II

Problem 1. Is it true that each uncountable group $G$ contains two subsets $A,B\subset G$ such that 1) for any $x,y\in G$ the intersection $xA\cap yB$ is finite and 2) for any function $\...
Taras Banakh's user avatar
  • 41.8k
20 votes
1 answer
1k views

On Erdös–Kakutani like Equivalents of the Failure of Continuum Hypothesis

Among all mysterious equivalents of the Continuum Hypothesis and its negation, there is an algebraic combinatorial equivalent of $\neg \mathit{CH}$ in Erdös and Kakutani - On non-denumerable graphs (...
Morteza Azad's user avatar