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Questions tagged [independence-results]

This tag is for questions about proving that some statement is independent from a theory, meaning it is neither provable nor refutable from that theory. Common examples are the continuum hypothesis from the axioms of ZFC, and the axiom of choice from the axioms of ZF.

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297 votes
34 answers
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What are some reasonable-sounding statements that are independent of ZFC?

Every now and then, somebody will tell me about a question. When I start thinking about it, they say, "actually, it's undecidable in ZFC." For example, suppose $A$ is an abelian group such ...
54 votes
1 answer
3k views

In the two-person Killing the Hydra game, what is the winning strategy?

My question is which player has a winning strategy in the two-player version of the Killing the Hydra game? In their amazing paper, Kirby, Laurie; Paris, Jeff, Accessible independence results for ...
Joel David Hamkins's user avatar
51 votes
4 answers
7k views

How undecidable is the spectral gap?

Nature just published a paper by Cubitt, Perez-Garcia and Wolf titled Undecidability of the Spectral Gap, there is an extended version on arxiv which is 146 pages long. Here is from the abstract:"Many ...
Conifold's user avatar
  • 1,731
44 votes
3 answers
5k views

"Simpler" statements equivalent to Con(PA) or Con(ZFC)?

Given any reasonable formal system F (e.g., Peano Arithmetic or ZFC), we all know that one can construct a Turing machine that runs forever iff F is consistent, by enumerating the theorems of F and ...
Scott Aaronson's user avatar
33 votes
1 answer
2k views

Is it still an open problem whether $\mathbb{R}^\omega$ is normal in the box topology?

On page 205 of his Topology textbook, James Munkres made an interesting remark: It is not known whether $\mathbb{R}^\omega$ is normal in the box topology. Mary-Ellen Rudin has shown that the answer ...
Keshav Srinivasan's user avatar
32 votes
1 answer
2k views

Should axiomatic set theory be translated into graph theory?

Recently I saw the abstract of a paper by Nash-Williams: ``Should axiomatic set theory be translated into graph theory?''. The abstract, taken from Mathscinet says the following: The author ...
Mohammad Golshani's user avatar
32 votes
1 answer
2k views

Bidi: A new cardinal characteristic of the continuum?

This question assumes familiarity with combinatorial cardinal characteristics of the continuum. Identify an infinite set $a\subseteq\mathbb{N}$ with its increasing enumeration. Thus, for each natural ...
Boaz Tsaban's user avatar
  • 3,104
22 votes
3 answers
2k views

Nice algebraic statements independent from ZF + V=L (constructibility)

Background and motivation I've always been fascinated about algebraic statements independent from ZFC set theory. One such fascinating example comes from considering $\rm{Ext}^1_\mathbb{Z}(A,\mathbb{Z}...
user avatar
18 votes
3 answers
3k views

What's the earliest result (outside of logic) that cannot be proven constructively?

Although mathematicians usually do not work in constructive mathematics per se, their results often are constructively valid (even if the original proof isn't). An obvious counter-example is the law ...
Christopher King's user avatar
18 votes
3 answers
1k views

Spectra of elements of a Banach algebra and the role played by the Hahn-Banach Theorem.

This problem was posed on Math StackExchange some time ago, but it did not garner any solutions there. I think that it is interesting enough to be posed here on Math Overflow, so here it goes. Let $ \...
Leonard's user avatar
  • 816
16 votes
1 answer
2k views

A contradiction in the Set Theory of von Neumann–Bernays–Gödel?

Thinking on the theory NBG (of von Neumann–Bernays–Gödel) I arrived at the conclusion that it is contradictory using an argument resembling Russell's Paradox. I am sure that I made a mistake in my ...
Taras Banakh's user avatar
  • 41.8k
16 votes
1 answer
1k views

Kaplansky's conjecture and Martin's axiom

Recall Kaplansky's conjecture which states that every algebra homomorphism from the Banach algebra C(X) (where X is a compact Hausdorff topological space) into any other Banach algebra, is ...
Mohammad Golshani's user avatar
15 votes
4 answers
2k views

Is every p-point ultrafilter Ramsey?

A non-principal ultrafilter $\mathcal{U}$ on $\omega$ is a p-point (or weakly selective) iff for every partition $\omega = \bigsqcup _{n < \omega} Z_n$ into null sets, i.e each $Z_n \not \in \...
Amit Kumar Gupta's user avatar
14 votes
3 answers
2k views

Is the Axiom of Union independent of the rest of ZF?

Short version: Is the axiom of union independent of the rest of axioms of ZF? NO) Tourlakis (2003) says in p. 177 that the axiom of union can be derived from the rest of ZF if an appropriate version ...
0rvidal's user avatar
  • 243
13 votes
0 answers
325 views

$\mathsf{AC}_\mathsf{WO}+\mathsf{AC}^\mathsf{WO}\Rightarrow \mathsf{AC}$?

Let $\mathsf{AC}_\mathsf{WO}$: Every well-orderable family of non-empty sets has a choice function. $\mathsf{AC}^\mathsf{WO}$: Every family of non-empty well-orderable sets has a choice function. My ...
Lorenzo's user avatar
  • 2,286
11 votes
5 answers
3k views

Minimal subset of axioms for ZFC

Hello all, one may look for "minimal system of axioms" for ZFC (or any other theory) in the following (unusual) sense : say that a subset S of ZFC is "sufficient" if there is an explicit procedure ...
Ewan Delanoy's user avatar
  • 3,595
11 votes
6 answers
1k views

When can a function defined on $[a, b] \cup [b, c]$ be constructively extended to a function defined on $[a, c]$?

Let $a, b, c \in \mathbb R$ such that $a \le b \le c$. Let $S$ be some set and $f : [a, b] \cup [b, c] \to S$ be a function. When can we find a function $g : [a, c] \to S$ that meets the following ...
Christopher King's user avatar
11 votes
3 answers
994 views

Why can we assume a ctm of ZFC exists in forcing

Following Kunen's book, it makes clear that countable transitive models (ctm) exist only for a finite list of axioms of ZFC. So, why can we assume a ctm of the whole ZFC axioms exists and use it as ...
Guest's user avatar
  • 111
11 votes
1 answer
628 views

A new cardinal characteristic (related to partitions)?

In this post I will discuss some cardinal characteristic of the continuum, related to partitions of $\omega$ and would like to know if it is equal to some known cardinal characteristic. By a partition ...
Taras Banakh's user avatar
  • 41.8k
11 votes
1 answer
704 views

Is $\mathfrak j_{2:1}=\mathfrak{j}_{2:2}$ in ZFC?

A function $f:\omega\to\omega$ is called $\bullet$ 2-to-1 if $|f^{-1}(y)|\le 2$ for any $y\in\omega$; $\bullet$ almost injective if the set $\{y\in \omega:|f^{-1}(y)|>1\}$ is finite. Let us ...
Taras Banakh's user avatar
  • 41.8k
11 votes
0 answers
256 views

Existence of a strong antichain

Call an antichain (set of pairwise incomparable elements) $A$ of a poset $P$ strong if for every $p,q \in P$ with $p \leq q$ there exists an $a\in A$ which is comparable with both $p$ and $q$. ...
Attila Joó's user avatar
10 votes
3 answers
2k views

Reference Request: Independence of the ultrafilter lemma from ZF

I'm looking for references for the following facts concerning the ultrafilter lemma (~ "there exist non-principal ultrafilters"): The ultrafilter lemma is independent of ZF. ZF + the ultrafilter ...
Greg Graviton's user avatar
10 votes
2 answers
3k views

Independence of the countable axiom of choice

How does one proove that the Countable axiom of choice is not provable in ZF?Is there any brief proof?Does the Independence of the countable axiom of choice implies the independence of the axiom of ...
Ilias kaperonis's user avatar
9 votes
2 answers
1k views

Given a cardinal k, what's the biggest dense linear order with a dense subset of size k?

It's not hard to show that for any cardinal $\kappa$, there is no dense linear order without endpoints (DLO) of size greater than $2^{\kappa}$ that has a dense subset of size $\kappa$. But one can ...
Amit Kumar Gupta's user avatar
9 votes
1 answer
482 views

Relationship between AC, WO, and Zorn's lemma in ZF-Powerset

In regular ZF, AC, WO, and Zorn's Lemma are equivalent, but every proof I know (of the implication AC -> WO and AC -> Zorn) uses the axiom of choice on the powerset of X (where X is the Set which is ...
Hannes Jakob's user avatar
  • 1,799
9 votes
2 answers
1k views

Relationship between fragments of the axiom of choice and the dependent choice principles

The dependent choice principle ${\rm DC}_\kappa$ states that if $S$ is a nonempty set and $R$ is a binary relation such that for every $s\in S^{\lt\kappa}$, there is $x\in S$ with $sRx$, then there ...
Victoria Gitman's user avatar
9 votes
1 answer
489 views

Intuition behind Pincus' "injectively bounded statements"

In David Pincus, Zermelo-Fraenkel Consistency Results by Fraenkel-Mostowski Methods, The Journal of Symbolic Logic, Vol. 37, No. 4 (Dec., 1972), pp. 721-743 Pincus introduces the notion of ...
David Roberts's user avatar
  • 35.4k
8 votes
3 answers
745 views

Natural statements independent from true $\Pi^0_2$ sentences

I am looking for sentences in the language of first order arithmetic ($0,1,+,\cdot,\leq$) which are independent from $\Pi^0_2$ consequences of true arithmetic $\Pi^0_2\text{-}\mathsf{Th}(\mathbb{N})$. ...
Kaveh's user avatar
  • 5,502
8 votes
1 answer
323 views

A surjection from square onto power: Is limit Hartogs/Lindenbaum number necessary?

I am considering the construction in [Peng—Shen—Wu] in which the authors show the consistency of a set $X$ such that there is a surjection from $X^2$ onto the power set of $X$ (henceforth $\mathscr{P}(...
Calliope Ryan-Smith's user avatar
8 votes
1 answer
490 views

Natural $\Pi_1$ sentence independent of PA

Order invariant graphs and finite incompleteness by Harvey Friedman gives an example of a combinatorial/non-metamathematical $\Pi_1$ sentence that is independent of ZFC. Is there a simpler example of ...
user76284's user avatar
  • 2,203
8 votes
0 answers
238 views

Metrically Ramsey ultrafilters

On Thuesday I was in Kyiv and discussed with Igor Protasov the system of MathOverflow and its power in answering mathematical problems. After this discussion Igor Protasov suggested to ask on MO the ...
Taras Banakh's user avatar
  • 41.8k
7 votes
6 answers
2k views

Formal proof of Con(ZFC) => Con(ZFC + not CH) in ZFC

Is it possible to prove $Con(ZFC) \rightarrow Con(ZFC + \neg CH)$ purely within ZFC? To prove this (using forcing) one seems to need a countable transitive model of ZFC. The texts I am reading avoid ...
Tobias Neukom's user avatar
7 votes
1 answer
457 views

The existence of definable subsets of finite sets in NBG

This question is motivated by my preceding MO-question on (in)consistency of NBG theory of classes. Let $\varphi(x,Y,C)$ be a formula of NBG with free parameters $x,Y,C$ and all quantifiers running ...
Taras Banakh's user avatar
  • 41.8k
7 votes
2 answers
844 views

Statements forced by one condition of a poset, but not the whole thing

In order to get the relative consistency of some statement, it suffices to find a notion of forcing, and a condition $p$ in that forcing, such that $p$ forces the desired statement. It seems to be ...
Amit Kumar Gupta's user avatar
7 votes
3 answers
439 views

Dedekind-"finiteness" for arbitrary limit cardinals

In $\mathbf{ZF}$, it is possible for a set $A$ to be infinite but not to admit a countable set. In other words, for any $\alpha\in\omega$, there is an injection from $\alpha$ into $A$, but there is no ...
Hannes Jakob's user avatar
  • 1,799
7 votes
1 answer
425 views

On Consistency of an Existence

Let $\omega \leq \kappa <2^{\omega}$ , $\omega \leq\lambda \leq \kappa$ and $D(\kappa, \lambda)$ be the statement: For all $ \mathfrak{B} \subseteq \mathbf{P}(\omega)$ with $|\mathfrak{B}|=\kappa$...
Rahman. M's user avatar
  • 2,381
7 votes
0 answers
177 views

Asymptotically discrete ultrafilters

Definition 1. A ultrafilter $\mathcal U$ on $\omega$ is called discrete (resp. nowhere dense) if for any injective map $f:\omega\to \mathbb R$ there is a set $U\in\mathcal U$ whose image $f(U)$ is a ...
Taras Banakh's user avatar
  • 41.8k
6 votes
3 answers
1k views

Is there an "undecided" assertion of which a proof that it's not undecidable is known?

Just a curiosity: Is there an assertion of which a proof (formalizable, say, in ZFC) is not known but a proof that it's not undecidable (in ZFC) is known? Edit: after the comments, I think the ...
Qfwfq's user avatar
  • 23.3k
6 votes
1 answer
603 views

A strong form of the Axiom Schema of Replacement

Let us consider the following stronger version of the Axiom Schema of Replacement (let us call it the Axiom Schema of Replacement for Definable Relations): Let $\varphi$ be any formula in the language ...
Taras Banakh's user avatar
  • 41.8k
6 votes
1 answer
626 views

Can $H_{\omega_1}$ and $H_{\omega_2}$ be in bi-interpretation synonymy?

This question concerns the possibility of the bi-interpretation synonymy of the structure $\langle H_{\omega_1},\in\rangle$, consisting of the hereditarily countable sets, and the structure $\langle ...
Joel David Hamkins's user avatar
6 votes
1 answer
273 views

$\omega_2$-sequence of Suslin trees

Is it possible to have an $\omega_2$-length sequence of ($\omega_1$-)Suslin trees such that if one builds the product of finitely many trees in that sequence, one ends up with a Suslin tree again? ...
Stefan Hoffelner's user avatar
6 votes
0 answers
375 views

How bad a proper forcing of size $\aleph_1$ can be?

This question concerns proper forcings of size $\aleph_1$. In the context of $\rm ZFC+\neg CH$, I couldn't find any counter example to the following property. Suppose $\mathbb P$ is a proper forcing ...
Rahman. M's user avatar
  • 2,381
5 votes
1 answer
325 views

Is Axiom of Choice equivalent to its version for families of sets, indexed by ordinals? [duplicate]

Is Axiom of Choice equivalent to the following statement? Axiom of Ordinal Choice: For any ordinal $\lambda$ and any indexed family of sets $(X_\alpha)_{\alpha\in\lambda}$ there exists a function $...
Taras Banakh's user avatar
  • 41.8k
5 votes
1 answer
401 views

Variants of reflection principle

This question concerns two definitions of the reflection principle. One of them known to be a consequence of the other one. I would like to understand if the reverse is true. Let us state the first ...
Rahman. M's user avatar
  • 2,381
5 votes
1 answer
197 views

The cardinal characteristic $\mathfrak r_{(X,f)}$ of a dynamical system

I am interested in a "dynamical" modification of the cardinals $\mathfrak r$ and $\mathfrak r_\sigma$, well-known in the theory of cardinal characteristics of the continuum. For a compact ...
Taras Banakh's user avatar
  • 41.8k
5 votes
1 answer
207 views

Examples of independent $\Sigma_4^1$ statements

As in the title, I'm looking for examples of $\Sigma^1_4$ (preferably complete) sentences which are independent from ZFC in both ways, namely given a model $V$ we can extend it to $V'$ where such a ...
Jarek Swaczyna's user avatar
5 votes
1 answer
524 views

A topologically transitive dynamical system without dense orbits

By a dynamical system I understand a pair $(K,G)$ consisting a compact Hausdorff space and a subgroup $G$ of the homeomorphism group of $K$. We say that a dynamical system $(K,G)$ $\bullet$ is ...
Taras Banakh's user avatar
  • 41.8k
5 votes
1 answer
512 views

Smallest size of a non-measurable set of reals

The question is pretty much the title. I'm wondering if anything is known about the smallest size $\kappa$ of a non-measurable subset of the real numbers (regarding the Lebesgue measure). Since we ...
Hannes Jakob's user avatar
  • 1,799
5 votes
0 answers
212 views

Questions about very fat sets

If $\kappa$ is a regular uncountable cardinal, we call a set $S\subseteq\kappa$ fat if for every $\alpha<\kappa$ and every club $C\subseteq\kappa$, there is a closed subset of $S\cap C$ of ...
Hannes Jakob's user avatar
  • 1,799
5 votes
0 answers
175 views

Selecting an almost disjoint family in a given family of sets

A family $\mathcal A$ of infinite subsets of $\omega$ is called almost disjoint if for any distinct sets $A,B\in\mathcal A$ the intersection $A\cap B$ is finite. Let $\mathfrak a'$ be the largest ...
Taras Banakh's user avatar
  • 41.8k