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Are maps between cohomology of homogeneous vector bundles morphisms of representations?

Let $X = G/P$ a rational homogeneous variety, e.g. a grassmannian. Consider a short exact sequence $$ 0 \longrightarrow E_1 \longrightarrow E_2 \longrightarrow E_3 \longrightarrow 0$$ where $E_i$ are ...
AleK3's user avatar
  • 41
9 votes
3 answers
790 views

A manifold whose tangent space is a sum of line bundles and higher rank vector bundles

I am looking for an example of the following situation. Let $M$ be a connected (if possible compact) manifold such that its tangent bundle $T(M)$ admits a vector bundle decomposition $$ T(M) = A \...
Bobby-John Wilson's user avatar
2 votes
0 answers
125 views

The double quotient of SU(N) by its diagonal maximal torus

$\DeclareMathOperator\SU{SU}$The special unitary group $\SU(N)$ contains $T^{N-1}$ as a maximal torus, which we take to be the diagonal subgroup of $\SU(N)$. Can we describe the double quotient space $...
Yilmaz Caddesi's user avatar
7 votes
1 answer
178 views

Homogeneous metric connections on 3-dimensional Lie groups

Let $G$ be a 3-dimensional unimodular Lie group equipped with a left-invariant metric $q$. Call $P_{SO}$ its oriented orthonormal frame bundle. Considering the moduli space of connections $\mathscr{B}$...
Matteo Bruno's user avatar
6 votes
0 answers
345 views

Why can't a Lie group act transitively on a finite volume hyperbolic manifold?

In the comments on the MathSE question "Is Seifert-Weber space homogeneous for a Lie group?", it is claimed that if $ M $ is a manifold which admits a finite volume hyperbolic metric (...
Ian Gershon Teixeira's user avatar
4 votes
0 answers
226 views

Is the total space of a $ U_1 $ principal bundle over a compact homogeneous space always itself homogeneous?

Let $ U_1 \to E \to B $ be a $ U_1 $ principal bundle. Suppose that $ B $ is homogenous (admits a transitive action by a Lie group) and compact. Then must it be the case that $ E $, the total space of ...
Ian Gershon Teixeira's user avatar
3 votes
0 answers
80 views

Can a semisimple orbit always be identified with a cotangent bundle?

Let $H$ be a semisimple element of the Lie algebra $\mathfrak{g}$ of a semisimple Lie group $G$, and let $M:=\mathrm{Ad}_G(H)\subset\mathfrak{g}$ be the corresponding adjoint orbit. If we choose a ...
Giovanni Moreno's user avatar
3 votes
1 answer
119 views

Existence of a bounded measurable subset of $\text{SL}(d,\mathbb R)$ that is Borel isomorphic to $\text{SL}(d,\mathbb R)/\text{SL}(d,\mathbb Z)$?

$\text{SL}(d,\mathbb R)/\text{SL}(d,\mathbb Z)$ has two interesting properties: on one hand it is non-compact, but on the other hand it admits a unique $\text{SL}(d,\mathbb R)$-invariant finite ...
user506835's user avatar
5 votes
0 answers
146 views

Is every linear Lie group of bounded geometry?

$\newcommand\norm[1]{\lVert#1\rVert}$Given any point $p$ of a smooth Riemannian manifold $M$ there exists $r\in (0,\infty]$ such that the Riemannian exponential is a diffeomorphism in the geodesic ...
Marco's user avatar
  • 293
5 votes
1 answer
261 views

Non-integrable almost complex structure for complex projective $3$-space

It is well known that complex projective three space $\mathbb{C}\mathbf{P}^3$ is a complex manifold. However it also possess a non-integrable almost-complex structure (as discussed in this article for ...
Didier de Montblazon's user avatar
3 votes
0 answers
50 views

Are there invariants of configurations of points in space obtainable via the moduli space of solutions of the Berry-Robbins problem?

Let $C_n(\mathbb{R}^3)$ denote the configuration space of $n$ distinct points in Euclidean $3$-space and let $U(n)/T^n$ denote the flag manifold associated to the unitary group $U(n)$, i.e. the ...
Malkoun's user avatar
  • 5,215
7 votes
1 answer
280 views

Non-homogeneous line bundles over a homogeneous space

Let $G$ be a compact Lie group and $G/K$ a connected homogeneous space. A homogeneous vector bundle over $G/K$ is a vector bundle is one that is isomorphic to a vector bundle of the form $$ G \times_{\...
László Szabados's user avatar
4 votes
0 answers
101 views

Modern reference for a theorem by Bott on the Dolbeault cohomology of compact homogeneous manifolds

I am looking for a modern, maybe shorter or even easier, reference for Theorem II of Homogeneous vector bundles (R. Bott, Annals of mathematics, 1957). This is a theorem where the Dolbeault cohomology ...
Max Reinhold Jahnke's user avatar
3 votes
1 answer
203 views

Free $S^1$-action on compact homogeneous spaces

Let $M = G/K$ be a compact homogeneous space, i.e. $G$ a connected compact Lie group, and $K$ a closed subgroup inside $G$ that contains no nontrivial normal subgroup of $G$. If $r(G) > r(K)$ (...
abracadabra12345's user avatar
5 votes
1 answer
203 views

Can all hermitian symmetric spaces be realised as coadjoint orbits?

Here is what I know. Assume $M\cong G/K$ is an irreducible hermitian symmetric space. Denote the Lie-algebra of $K$ by $\mathfrak{t}$. Proposition 1.2. chapter 3 in Wienhard - Bounded cohomology and ...
SophieS's user avatar
  • 61
1 vote
0 answers
132 views

About the classification of simply connected homogeneous 3-manifolds

I've read somewhere (but cannot locate the source) that the following classification holds: simply connected homogeneous 3-manifolds are either isometric to $S^2 \times \mathbb{R}$ or to a metric Lie ...
Paul Cusson's user avatar
  • 1,763
3 votes
0 answers
111 views

Almost two-point homogeneous spaces

I define a NICE space to be a connected Riemannian manifold $M$ such that for any two distinct points $p,q\in M$, there exists an isometry $R_{p,q}$ exchanging these two points (that is such that $R_{...
Andrea Aveni's user avatar
1 vote
0 answers
196 views

Homogeneous metrics on compact Lie groups

Given a differentiable manifold $M$, a Riemannian metric $g$ on $M$ is called homogeneous if its isometry group acts transitively on $M$. In that case, given any group $G$ acting transtitively on $(M,...
emiliocba's user avatar
  • 2,446
3 votes
1 answer
273 views

Classification of "homogeneous" submanifolds of ℝⁿ

I define a subset $M$ of $\mathbb R^n$ to be a "homogeneous Euclidean manifold" if: it is a closed connected smooth submanifold of $\mathbb R^n$, for every $p, q$ in $M$, there is a ...
Andrea Aveni's user avatar
2 votes
0 answers
35 views

Properties of the orbit $Abx_0$ when $b$ is upper or lower triangular but not diagonal

Let $G=\text{SL}(d,\mathbb R)$ and $\Gamma = \text{SL}(d,\mathbb Z)$. The homogeneous space is identified with the space of unimodular lattices, denoted $X_d$. Let $A$ denote the subgroup of $G$ ...
No One's user avatar
  • 1,565
5 votes
1 answer
134 views

Homogeneous representations of compact manifolds

There is a classification of effective transitive groups actions on the sphere by compact connected Lie groups, compare Besse "Einstein manifolds" 7.13 Examples. Are there similar results ...
Julian Seipel's user avatar
3 votes
2 answers
120 views

The closure of the orbit of an irrational grid contains the fiber

Let $G=\text{SL}(d,\mathbb R)$ and $\Gamma = \text{SL}(d,\mathbb Z)$. The homogeneous space is identified with the space of unimodular lattices, denoted $X_d$. Let $Y_d$ denote the space of unimodular ...
No One's user avatar
  • 1,565
2 votes
2 answers
213 views

Riemannian homogeneous equivalent to linear group orbit

Let $ M $ be a smooth manifold. Recall that a manifold $ M $ is smooth homogeneous if there exists a Lie group acting transitively on $ M $. Recall that a manifold $ M $ is Riemannian homogeneous if ...
Ian Gershon Teixeira's user avatar
17 votes
3 answers
2k views

Examples of the Thurston geometries with transitive Lie group action

Here are some examples of compact homogeneous 3 manifolds for different Thurston geometries: (1) Spherical: $\mathbb{S}^3 \cong \mathrm{SU}_2$ modulo any finite subgroup (2) Euclidean: 3 torus $\...
Ian Gershon Teixeira's user avatar
4 votes
2 answers
332 views

Does the maximal compact subgroup always act transitively on a compact homogeneous space?

Let $ G $ be a Lie group, $ H $ a closed subgroup, and $ G/H $ compact. Under what conditions do we have that $$ G/H \cong K/(K\cap H) $$ where $ K $ is a maximal compact subgroup of $ G $? Obviously ...
Ian Gershon Teixeira's user avatar
2 votes
0 answers
95 views

Local decomposition of semisimple Lie groups at the identity into the product of centralizer, unstable and stable horospherical subgroups

First let us look at an example. Let $G=\text{SL}(d,\mathbb R)$ and $A$ be its subgroup consisting of diagonal matrices with positive entries. Let $a\in A$ be an element. We define the stable ...
No One's user avatar
  • 1,565
2 votes
0 answers
557 views

What is the precise definition of connect semisimple Lie groups "without compact factors" in the literature?

I frequently see in the literature (of homogeneous dynamics, in particular) of the notion "semisimple Lie groups without compact factors" without seeing its precise definition. I have three (...
No One's user avatar
  • 1,565
2 votes
0 answers
82 views

Transitive Lie group actions with uniformly bounded derivatives

Let $\phi:G\times M\rightarrow M$ be a smooth and transitive action of a real Lie group $G$ on a smooth real manifold $M$. Both $G$ and $M$ are assumed to be finite-dimensional but neither are assumed ...
Jochen Trumpf's user avatar
8 votes
0 answers
228 views

What can we say about the homogeneous spaces $E_8/E_7$ and $E_7/E_6$?

For the three exceptional compact Lie groups $E_8, E_7, E_6$ we have the inclusions $$ E_6 \subseteq E_7 \subseteq E_8. $$ What can we say about the the homogeneous spaces $$ E_8/E_7, ~~~~ E_7/E_6? $$ ...
Alain Rochefort's user avatar
6 votes
2 answers
448 views

Homogeneous symplectic manifolds

I have often heard/read a statement (see, e.g., this MathOverflow question) equivalent to the following: Let $G$ be a connected Lie group and $(M,\omega)$ a connected and simply-connected symplectic ...
José Figueroa-O'Farrill's user avatar
0 votes
1 answer
254 views

$SU(k)/SO(k)$ as a manifold, for each positive integer $k$ [closed]

The quotient space $SU(k)/SO(k)$ is also a homogeneous space constructed out of the Lie groups (special unitary $SU(k)$ and special orthogonal $SO(k)$). Because the $SO(k)$ may not be a normal ...
Марина Marina S's user avatar
8 votes
1 answer
298 views

How special are homogeneous spaces?

Let $M$ be a smooth finite dimensional manifold, how restrictive is it to require $M$ to admit a smooth action by a finite dimensional Lie group $G$? Related questions/approaches: Of course we need $\...
GFR's user avatar
  • 639
4 votes
1 answer
324 views

The Hausdorff codimension of singular matrices vs. the Hausdorff codimension of points with divergent trajectories

Let $G:=SL(m+n,\mathbb R)$ and $\Gamma :=SL(m+n,\mathbb Z)$ and $X:=G/\Gamma$. (1) Let $M$ denote the set of all $m \times n$ matrices with real entries. A matrix $A \in M$ is called $\textit{singular}...
No One's user avatar
  • 1,565
7 votes
3 answers
577 views

Ergodicity of the action of $\operatorname{SL}(n,\mathbb R)$ on $\operatorname{SL}(n,\mathbb R)/\operatorname{SL}(n,\mathbb Z)$

$\DeclareMathOperator\SL{SL}$Let $G\mathrel{:=}\SL(n,\mathbb R)$ and $\Gamma\mathrel{:=}\SL(n,\mathbb Z)$. Consider the action of $G$ on $(G/\Gamma,\mu)$ by left translation, where $\mu$ is the Borel ...
No One's user avatar
  • 1,565
8 votes
1 answer
610 views

Are invariant forms on homogeneous spaces necessarily closed?

Take a compact homogeneous space $G/K$, and a left $G$-invariant differential $k$-form $\omega \in \Omega^k(G/K)$. Will $\omega$ necessarily be closed? Might it even be harmonic when $G/K$ is endowed ...
Quin Appleby's user avatar
11 votes
0 answers
336 views

The existence of a fiber sequence involving $\mathrm{Spin}(9)$ and $\mathrm{SU}(2)$

$\newcommand{\SU}{\mathrm{SU}} \newcommand{\Spin}{\mathrm{Spin}}$There is a fiber sequence $G_2\to \Spin(9) \to \Spin(9)/G_2$, and $G_2$ contains $\SU(3)$ as a subgroup. Is there a space (possibly a ...
skd's user avatar
  • 5,760
1 vote
0 answers
517 views

Horizontal lift of fundamental vector field

Suppose $\theta\colon G\times M\to M$ is a transitive smooth left action of a compact Lie group $G$ on a manifold $M$ and $\pi\colon G\to M\cong G/K$ the corresponding smooth submersion for some ...
Sven Pistre's user avatar
3 votes
0 answers
105 views

p-adic analogue of classification of irreducible Riemannian symmetric spaces?

For Riemannian symmetric spaces, we have a nice result that the simply-connected ones are products of irreducible symmetric spaces, of which we have a list of ten infinite families and some ...
Roger Van Peski's user avatar
3 votes
1 answer
152 views

Model geometry uniqueness

Let $ M $ be a compact connected manifold with $$ M \cong \Gamma \backslash G /H $$ where $G $ is a Lie group, $ H $ a compact subgroup, $\Gamma $ a discrete subgroup, and $ G/H $ is connected and ...
Ian Gershon Teixeira's user avatar
3 votes
2 answers
2k views

Is a manifold paracompact? Should it be?

We will say that a Hausdorff topological space $X$ is a smooth manifold if there is an open cover $(U_{\alpha})$ of $X$ and a corresponding collection of homeomorphisms $\varphi_{\alpha} : U_{\alpha} \...
AmorFati's user avatar
  • 1,379
4 votes
3 answers
862 views

Is every homogeneous space Riemannian homogeneous?

A manifold $M$ together with a transitive $G$-action is always diffeomorphic a quotient $G/H$ for $H < G$ Lie groups. On the other hand, there might be a proper subgroup of $G$ that also acts ...
Lezkus's user avatar
  • 177
9 votes
0 answers
203 views

Octonionic Stiefel manifolds

The Stiefel manifolds are presented in this Wikipedia article over the division algebras $\mathbb{R,C,H}$. In fact, they are presented as homogeneous spaces, respectively for the $A,B,C$,and $D$ ...
Fofi Konstantopoulou's user avatar
4 votes
1 answer
252 views

Flag manifolds as homogeneous Kahler manifolds

In this question it is asked if every flag manifold can be given the structure of a Kähler manifold. In the first answer it is written Flag manifolds exhaust all compact homogeneous Kähler ...
Fofi Konstantopoulou's user avatar
2 votes
1 answer
148 views

Coinvariant representative of homogeneous space cohomology

Given a compact homogeneous space $M = K/L$, consider its de Rham complex $(\Omega^*,d)$. Will every cohomology class $[\omega] \in ker(d)/im(d)$ contain a representative $\nu$ which is invariant with ...
Fofi Konstantopoulou's user avatar
1 vote
1 answer
408 views

De Rham cohomology of homogeneous spaces

Take a homogeneous space $K/L$, where $K$ and $L$ are compact lie groups. Denoting by $\Omega^*(K/L)$ its de Rham complex, which is a homogeneous vector bundle over $K/L$, and hence has a ...
Fofi Konstantopoulou's user avatar
7 votes
0 answers
123 views

Infinitesimal description of homogeneous supermanifolds

Lie's third theorem says that if $\mathfrak{g}$ is a real, finite-dimensional Lie algebra, then there is a unique (up to isomorphism) simply-connected Lie group $G$ whose tangent Lie algebra is ...
José Figueroa-O'Farrill's user avatar
2 votes
1 answer
51 views

Descending central extensions to homogeneous spaces

Let $G$ be a Lie group (finite dimensional or Banach), and let $H$ be a Lie subgroup (in the Banach case we assume that $H$ is a submanifold which is also a Lie group). Let $\text{U}(1) \rightarrow \...
Peter's user avatar
  • 556
5 votes
2 answers
1k views

Malcev's paper "On a class of homogeneous spaces" in English

I am struggling to find the English translation of Malcev's paper "On a class of homogenous spaces" providing foundational material for nil-manifolds. To be precise this paper: Malcev, A. I. On a ...
Tom1990's user avatar
  • 51
5 votes
1 answer
549 views

Volume of balls in homogeneous manifolds

Let $X=G/H$ be a homogeneous manifold, where $G$ and $H$ are connected Lie groups and assume there is given a $G$-invariant Riemannian metric on $X$. Let $B(R)$ be the closed ball of radius $R>0$ ...
user avatar
3 votes
0 answers
72 views

Homogeneous space for intersection of subgroups

Suppose we have a Lie group $G$ and two subgroups $P_1$ and $P_2$. We can then study the homogeneous spaces $M_1=G/P_1$ and $M_2=G/P_2$, and bundles on these spaces associated to representations of $...
Peter Kravchuk's user avatar