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Questions tagged [hamiltonian-graphs]

A Hamiltonian graph (directed or undirected) is a graph that contains a Hamiltonian cycle, that is, a cycle that visits every vertex exactly once.

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Infinitely many counterexamples to Nash-Williams's conjecture about hamiltonicity?

Question from 2013 gives one counterexample to Nash-Williams's conjecture about hamiltonicity of dense digraphs. Later, we found tens of counterexamples on more than 30 vertices and believe there are ...
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Two more counterexamples to a conjecture from 1975 about hamiltonicity of digraphs

Question from 2013 gives one counterexample to Nash-Williams's conjecture 1975 about hamiltonicity of dense digraphs. In the linked answer, @LouisD "reverse engineered" the counterexample ...
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"Gray code" for building teams

Motivation. In a team of $n$ people, we had the task to build subteams of a fixed size $k<n$ such that every day, $1$ person of the subteam is replaced by another person in the team, but not in the ...
Dominic van der Zypen's user avatar
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Is this case of Barnette's Conjecture known?

Context: Barnette's Conjecture is that every bipartite cubic polyhedral graph is Hamiltonian. I have been interested by this problem for a long time, and I recently came up with a result. From my ...
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Is Hamiltonian cycle fixed parameter tractable with parameter clique cover?

Let $G$ be connected simple graph. Clique cover of graph $G$ is partition of the vertices of $G$ into $k$ disjoint cliques $D'_i$. Given $G$ and $k$-clique cover, can we solve Hamiltonian cycle in ...
joro's user avatar
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Does 2-connectivity imply Hamiltoniancy for subgraphs of the rook graph

We say the rook graph, $R_n$, is the cartesian product of $K_n \times K_n$. Let $S$ be the set of graphs that are an induced subgraph of $R_n$ for some $n$. Does there exist some constant $c$ such ...
Zach Hunter's user avatar
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Extending perfect matchings into Hamiltonian cycles

Let $G$ be a simple cubic graph which has a Hamiltonian circuit $C$. In general, it is not possible to find a second Hamiltonian circuit which contains all the chords of $C$. For example, the Wagner ...
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The number of Hamiltonian circuits on a convex polytope embedded in $\mathbb{R}^N$

Recently I wondered whether there might be a natural topological complexity measure for convex polytopes embedded in $\mathbb{R}^N$. After some reflection it occurred to me that the number of distinct ...
Aidan Rocke's user avatar
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6 votes
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Normal colorings of bridgeless cubic graphs

Definition (informal) A normal edge-5-coloring of a bridgeless cubic graph $G$ is a proper 5 coloring of the edges of the graph, so that for each edge $e\in E(G)$, either $e$ and the four edges ...
EGME's user avatar
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Arranging all permutations on $\{1,\ldots,n\}$ such that there are no common points

If $n>0$ is an integer, let $[n]=\{1,\ldots,n\}$. Let $S_n$ denote the set of all permutations (bijections) $\pi:[n]\to[n]$. For which positive integers $n$ is there a bijection $\Phi:[n!]\to S_n$ ...
Dominic van der Zypen's user avatar
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Edge colorability and Hamiltonicity of certain classes of cubic graphs (MO graphs)

Let $G$ be a simple cubic graph (that is, 3-regular). A dominating circuit of $G$ is a circuit $C$ such that each edge of $G$ has an endvertex in $C$. The circuit $C$ is chordless if no edge which is ...
EGME's user avatar
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Which are good algorithms for finding Hamiltonian path (not necessarily a circle) up to now?

I am not expertise in graph theory. So have to ask this question here. The term "good" means that the algorithms should be efficient for general undirected simple connected graphs with a higher ...
Licheng Wang's user avatar
14 votes
1 answer
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Are all cubic graphs almost Hamiltonian?

Call a graph $G$ $n$-almost-Hamiltonian if there is a closed walk in $G$ that visits every vertex of $G$ exactly $n$-times. So a Hamiltonian graph is $n$-almost-Hamiltonian for all $n$. Are all ...
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Is there a permutation $\pi\in S_n$ with $\sum\limits_{0<k<n}\frac1{\pi(k)^2-\pi(k+1)^2}=0$ for each $n>7$?

Let $S_n$ be the symmetric group of all permutations of $\{1,\ldots,n\}$. QUESTION: Is it true that for each $n=8,9,\ldots$ we have $$\sum_{0<k<n}\frac1{\pi(k)^2-\pi(k+1)^2}=0\tag{$*$}$$ for ...
Zhi-Wei Sun's user avatar
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12 votes
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Quantitatively characterizing the failure of the converse of Dirac's theorem

First, I am an undergraduate so I apologize if this is trivial and certainly understand if it is closed immediately. I am currently in a combinatorics and graph theory class and recently we have ...
1729's user avatar
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6 votes
1 answer
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What is the complexity of counting Hamiltonian cycles of a graph?

Since deciding whether a graph contains a Hamiltonian cycle is $NP$-complete, the counting problem which counts the number of such cycles of a graph is $NP$-hard. Is it also $PP$-hard in the sense ...
T. D. Nguyen's user avatar
7 votes
1 answer
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Grinberg's uniquely hamiltonian 3-connected graphs (Russian paper)

Many years ago, Grinberg found some uniquely-hamiltonian $3$-connected graphs, and published his results in a paper that has been cited several times as follows. E. Grinberg, Three-connected graphs ...
Gordon Royle's user avatar
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Halin Graphs with Highest Number of Hamilton Cycles

Halin graphs contain a Hamilton cycle and have the interesting property, that, also in the case of arbitrary real edge weights, it is possible to report one of the shortest contained Hamilton cycles ...
Manfred Weis's user avatar
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Reference request: Bipartite symmetric graphs are hamiltonian

Does anyone know whether bipartite symmetric graphs are hamiltonian? I'm not sure whether anyone have proved it before, but a nonhamiltonian symmetric bipartite graph would lead to a counterexample to ...
LeechLattice's user avatar
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6 votes
1 answer
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Why is the number of Hamiltonian Cycles of n-octahedron equivalent to the number of Perfect Matching in specific family of Graphs?

In OEIS A003436, it is written that the number of inequivalent labeled Hamilton Cycles of an n-dimesnional Octahedron is the same as the number of Perfect Matchings in a the complement of the Cycle ...
Mario Krenn's user avatar
9 votes
1 answer
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Are bipartite Moore graphs Hamiltonian?

This is motivated by a computer-generated conjecture that bipartite distance-regular graphs are hamiltonian. I decided to check the case of Moore graphs first. The cycles and complete bipartite graphs ...
LeechLattice's user avatar
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4 votes
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Maximal non-hamiltonian graphs - spanned by a theta graph?

At the moment I am interested in maximal non-hamiltonian graphs, so that is a (simple, undirected) graph that does not itself have a hamilton cycle, but if you add an edge between any two distinct non-...
Gordon Royle's user avatar
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3 votes
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Hamiltonian cycle polytope for the hypercube graph

Let $Q_n$ denote the $n$ dimensional hypercube graph (i.e., graph formed from the vertices and edges of an n-dimensional hypercube). Denote the set of edges and vertices of $Q_n$ by $E_n$ and $V_n$ ...
Ozzy's user avatar
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1 vote
0 answers
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Properties of graphs with Hankel-like adjacency matrix

I am having undirected graphs with adjacency matrices which have a regular Hankel-like form, e.g., $$A=\begin{pmatrix}0 & 0 & 1 & 0 & 0 & 0 & 0 & 1 & (6\times 0 \text{ ...
pisoir's user avatar
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2 answers
321 views

Hamiltonicity and minimal degree in bipartite graphs

Given an integer $k>1$, is there a connected bipartite graph $\Gamma = (A, B, E)$ where $A\cap B = \emptyset$ and $E \subseteq \big\{\{a, b\}:a\in A, b\in B\big\}$ such that $|A| = |B|$, $\text{...
Dominic van der Zypen's user avatar
1 vote
3 answers
883 views

Hamiltonian paths in bipartite graphs with 2 sets of "almost" same cardinality

Suppose we have two finite disjoint sets $A, B \neq \emptyset$ such that $|A|$ and $|B|$ differ by at most $1$, and let $\Gamma = (A\cup B, E)$ where $E\subseteq \big\{\{a,b\}: a\in A, b\in B\big\}$ ...
Dominic van der Zypen's user avatar
9 votes
2 answers
2k views

"Gray code" of all permutations

Informally asking, can we step through all permutations of the set $\{1,\ldots,n\}$ by just using transpositions? More formally: For any $n\in\mathbb{N}$ let $[n] = \{1,\ldots,n\}$ and let $S_n$ be ...
Dominic van der Zypen's user avatar
14 votes
1 answer
783 views

What was Smith's proof of Smith's theorem on Hamilton cycles in cubic graphs?

In a short 1946 paper "On Hamiltonian Circuits", Tutte proved the famous result that an edge in a cubic graph lies in an even number of Hamilton circuits. He attributed the result to his friend CAB ...
Gordon Royle's user avatar
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4 votes
3 answers
506 views

Does every finite bridgeless cubic planar simple undirected graph admit a 2-factorization with at most two components each of which has even order?

Consider simple bridgeless cubic planar graphs. Does each such graph admit a 2-factorization with $\leq 2$ components each of which has even order? If not, does anyone know of an counterexample? ...
Jimmy Dillies's user avatar
3 votes
2 answers
123 views

Number Associated with Straight-line Drawings of Hamiltonian Graphs

Is there anything known about the maximum number of simple-polygonal Hamilton cycles that a straight-line drawing of a Hamiltonian graph can have? Put differently, if the vertices of a Hamilton ...
Manfred Weis's user avatar
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3 votes
1 answer
234 views

Counting cycle vertex covers on hypercube

Let $Q_n$ be the $n$-dimensional hypercube graph. How many vertex cycle covers exist on $Q_n$? (Presumably the best we can hope for are upper and lower bounds.) To be clear, a single "vertex cycle ...
Bill Bradley's user avatar
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9 votes
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Heuristic arguments regarding Sheehan's conjecture?

Sheehan conjectured that there are no 4-regular graphs that are uniquely hamiltonian (i.e. have exactly one hamilton cycle). Evidence that might be loosely seen to be in favour of this conjecture is: ...
Gordon Royle's user avatar
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8 votes
0 answers
123 views

Is there a non-bipartite hamiltonian cubic graph on $n$ vertices with no $(n-1)$-cycle?

Is there a cubic (3-regular) graph $G$ on $n$ vertices such that: $G$ is hamiltonian $G$ has no $(n-1)$-cycles $G$ is not bipartite My computer tells me that there are none on up to $24$ vertices.
Gordon Royle's user avatar
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6 votes
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Minimum number of hamilton cycles in a 4-connected planar triangulation?

I am currently interested in hamilton cycles (i.e. a cycle through every vertex) in planar triangulations (i.e. planar graphs with every face a triangle). There are non-hamiltonian planar ...
Gordon Royle's user avatar
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1 vote
1 answer
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Graph gadget related to uniquely hamiltionian regular graphs (question #2)

Related to uniquely hamiltionian graphs. For natural numbers $a,b$ define $(a,b)$ gadget $G$: $G$ is finite simple graph. Two vertices $u,v$ are of degree $b$ and the rest of the vertices are of ...
joro's user avatar
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5 votes
0 answers
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Graph gadget related to uniquely hamiltionian regular graphs

A graph is uniquely hamiltonian if it has exactly one hamiltonian cycle. According to a conjecture there are no $r$-regular uniquely hamiltonian graphs for $r > 2$ and of special interest is the ...
joro's user avatar
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6 votes
0 answers
76 views

Cage graphs and even cycles

Let $G$ be a $(\nu,g)$-cage graph of degree $\nu$ with girth $g$ and $n=n(\nu,g)$ vertices. Based on the known examples, I am wondering if the following can be proved/disproved: Is it true that ...
Wolfgang's user avatar
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15 votes
2 answers
2k views

What is the smallest uniquely hamiltonian graph with minimum degree at least 3?

I would like to know more about uniquely hamiltonian graphs with minimum vertex degree at least 3, and in particular what is the smallest one. (Recall that a graph is hamiltonian if it has a cycle ...
Gordon Royle's user avatar
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6 votes
0 answers
108 views

Localizing Bondy's metaconjecture on hamiltonicity

Definitions: Let $G$ be a graph on $n$ vertices. $G$ is Hamiltonian provided $G$ has a cycle of length $n$. $G$ is pancyclic provided $G$ has a cycle of length $\ell$ for every $3 \leq \ell \leq n$. ...
D. Ror.'s user avatar
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0 votes
1 answer
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degG(x) + degG(y) >= n, show that the graph is hamiltonian [closed]

I'm trying to show that a connected graph which has order >=3, and having the following inequality is Hamiltonian: ...
KevinZ's user avatar
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11 votes
1 answer
328 views

How many edges can be added to two circles before the graph becomes Hamiltonian?

Start with two $n$-circles $(v_1\cdots v_n)$ and $(w_1\cdots w_n)$ of vertice sets $V$ and $W$, where $n\ge 5$. Add a number of vertex-disjoint edges between $V$ and $W$ (thus no chords) in a way ...
Wolfgang's user avatar
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3 votes
1 answer
266 views

What is the densest bipartite graph with unique Hamiltonian cycle?

In a prior post regarding perfect matching, it was stated that the densest graph with a unique perfect matching cannot have more than $n^2$ edges, if graph has $2n$ vertices. Analogously, what is the ...
Turbo's user avatar
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10 votes
1 answer
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What is the complexity of finding a third Hamilton Cycle in cubic graph?

According to Smith Theorem: if a cubic graph has a hamilton circuit then it must have a second one. SMITH : Given a Hamilton circuit in a 3-regular graph, find a second Hamilton circuit. It is known ...
user avatar
2 votes
1 answer
606 views

Simple decomposition of $K_{2n}-I$ into hamiltonian cycles

http://mathworld.wolfram.com/HamiltonDecomposition.html In the 1890s, Walecki showed that complete graphs K_n admit a Hamilton decomposition for odd n, and decompositions into Hamiltonian cycles ...
Mohemnist's user avatar
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7 votes
1 answer
736 views

Refinement of Dirac's theorem on Hamiltonian graphs

Dirac's theorem states that if degree of each vertex of a graph $G=(V,E)$ is not less than $|V|/2$, then it has Hamiltonian cycle. It is less known, but still known and not so hard to prove (though I ...
Fedor Petrov's user avatar
4 votes
2 answers
349 views

Can we find 3 disjoint directed Hamiltonian cycles in the cube?

Let $D$ be the digraph on $2^d$ vertices with $d2^d$ edges that we obtain by directing each edge of the $d$-dimensional hypercube in both directions. Can we partition the edges of $D$ into $d$ ...
domotorp's user avatar
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5 votes
0 answers
295 views

A digraph related to permutations

A finite sequence of distinct real numbers of length $n$ determines a linear order of $\{1,\ldots,n\}$, by mapping position to rank; call this the permutation of the sequence. Consider the following ...
David Feldman's user avatar
5 votes
1 answer
1k views

How many hamiltonian cycles can be removed from a complete directed graph before it becomes disconnected?

The question started from a problem brought home by a friend's 5th grader: "How many ways can you seat 5 people around a round table so that the people sitting to the left of any person is different ...
Michael's user avatar
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3 votes
1 answer
117 views

Hamiltonicity of random graphs with high girth

We say that $G\sim G_{n,f}$ (for $f=f(n)$) if $G$ is chosen uniformly at random from all graphs on $n$ vertices with girth $g(G)\ge f(n)$. Is there any threshold function $F(n)$ such that when $f\ll F$...
Bach's user avatar
  • 221
19 votes
1 answer
1k views

Knight's tours in higher dimensions

I wonder if Knight's Tours have been explored in higher dimensions, using the following definition of a knight move. In dimension $d=2$, the knight moves left/right and forward/back one step and two ...
Joseph O'Rourke's user avatar