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Questions tagged [gt.geometric-topology]

Topology of cell complexes and manifolds, classification of manifolds (e.g. smoothing, surgery), low dimensional topology (e.g. knot theory, invariants of 4-manifolds), embedding theory, combinatorial and PL topology, geometric group theory, infinite dimensional topology (e.g. Hilbert cube manifolds, theory of retracts).

188 questions from the last 365 days
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Cell structure on the function space $\operatorname{Hom}(X,Y)$

By the Theorem of Milnor in his paper "On spaces having the homotopy type of a CW-complex", the function space $\operatorname{Hom}(X,Y)$ (with the compact-open topology) is homotopy ...
May's user avatar
  • 140
7 votes
1 answer
210 views

Preserving non-conjugacy of loxodromic isometries in a Dehn filling

Suppose that $g$ and $h$ are non-conjugate loxodromic isometries in a cusped hyperbolic $3$-manifold $M$ of finite volume. Fix a cusp $T$ of $M$. Can I choose a hyperbolic Dehn filling of $M$ along $...
Emily Hamilton's user avatar
-1 votes
0 answers
114 views

Stability of flow map

$\DeclareMathOperator\Diff{Diff}$Setting: Let $(M,g)$ be a compact and connected $C^{\infty}$-Riemannian manifold. Let $d_g$ denote the induced shorted path metric and equip $C^{\infty}(M)$ with the ...
ABIM's user avatar
  • 5,405
12 votes
1 answer
557 views
+200

Fundamental group of the complement of a codimension two submanifold

Let $M$ denote an arbitrary smooth, closed, connected, n-dimensional manifold for $n\geq 4$. For every such $M$, does there exist a closed (not necessarily connected!) codimension two submanifold $S \...
ThorbenK's user avatar
  • 1,174
3 votes
1 answer
157 views

Geometry and topology of Fuchsian character varieties

Consider the hyperbolic space, $\mathbb H^2$. A Fuchsian group is a discrete subgroup of $\text{PSL}(2,\mathbb R)$. We can generate tessellations, especially $\{p,q\} \;\text{tesellations}$ of $\...
user82261's user avatar
  • 357
3 votes
1 answer
269 views

$\mathrm{SL}(2,\mathbb{Z})$ finitely generated by using the Schwarz-Milnor lemma

Recently, I have been studying the modular group $G=\mathrm{SL}(2,\mathbb{Z})$, and I am trying to prove $G$ is finitely generated by using the Schwarz-Milnor lemma in geometric group theory.I am ...
T ghosh's user avatar
  • 111
7 votes
1 answer
177 views

Ergodicity of action of finite index subgroups in the boundary

Let $\Gamma < \operatorname{PSL}_2(\mathbb{R})= \text{Isom}^+(\mathbb{H^2})$ be a discrete subgroup. Suppose $\Gamma$ acts ergodically on the boundary of the hyperbolic plane $\partial{\mathbb{H}^2}...
shurtados's user avatar
  • 1,101
4 votes
1 answer
153 views

Kirby diagram of the complement of a subhandlebody of a smooth closed 4-manifold

Let $X$ be a smooth closed connected 4-manifold. It admits a handlebody structure, having a unique 0- and a unique 4-handle. We can express the handlebody structure as a Kirby diagram (https://en....
blancket's user avatar
  • 213
10 votes
1 answer
659 views

Are there any tests for knowing whether a topological space admits a CW structure?

We know that for n $\ge$ 5, a manifold admits a piecewise linear structure if and only if its Kirby-Siebenmann class vanish and Galewski and Stern showed the existence of a similar invariant to test ...
Tyrannosaurus's user avatar
3 votes
1 answer
132 views

Is a simply connected locally 2-connected complex a union of spheres and planes?

Let $X$ be a (potentially infinite) 2-dimensional simplicial complex. Then each link at a vertex $x\in X$ is a graph. Question. If $X$ is simply connected and each link is 2-connected (in the sense ...
M. Winter's user avatar
  • 13.6k
1 vote
0 answers
69 views

"Bad" valid edge contractions

In this paper, an edge contraction of a simplicial complex $\Gamma$ is defined as the operation of removing the neighborhood $N_e\Gamma$ of the edge $e=\{0,1\}$ and identifying $N_0\partial N_e\Gamma$ ...
Leo's user avatar
  • 11
2 votes
1 answer
380 views

Is it always possible to connect the endpoints of a smooth injective path, so the resulting path is smooth, closed and simple?

Motivation The motivation for this question arises from the following problem: Is there a closed, simple, and infinitely differentiable path on the (complex) plane such that every straight line has a ...
Gabriel Franceschi Libardi's user avatar
12 votes
1 answer
323 views

Does every mapping class group embed into some $\mathrm{Out}(F_n)$?

The title is pretty much the whole question. Let $S_g$ be a closed, oriented surface of genus $g$. Does there exist $n$ such that the mapping class group $\mathrm{Mod}(S_g)$ embeds as a subgroup of $\...
Matt Zaremsky's user avatar
3 votes
0 answers
119 views

Signature vs commensurability

If a closed oriented $4n$-dimensional manifold $M$ has an orientation-reversing homeomorphism, then the signature $\sigma(M)$ of the intersection form vanishes. More generally, $\sigma(M) = 0$ if $M$ ...
asd's user avatar
  • 41
3 votes
0 answers
115 views

Extending triangulations on surfaces

Suppose that $M$ is a surface (i.e., connected topological 2-manifold, I am willing to assume compact, but possibly with boundary), $K$ a finite simplicial complex, and $f$ an embedding of $K$ into $M$...
Iian Smythe's user avatar
  • 3,115
16 votes
2 answers
602 views

$\mathrm{GL}_n(\mathbb{Z}_2)=\mathrm{Out}(F_n)/\langle\langle \epsilon_1,\dots,\epsilon_n\rangle\rangle$

In a paper I found the following result: $$\mathrm{GL}_n(\mathbb{Z}_2)=\mathrm{Out}(F_n)/\langle\langle \epsilon_1,\dots,\epsilon_n\rangle\rangle$$ However, they got the result as a corollary of a ...
Marcos's user avatar
  • 911
4 votes
0 answers
177 views

Basis of topology on space of properly embedded smooth manifolds

In A Short Exposition of the Madsen-Weiss Theorem, Hatcher discusses (starting at p.6) a basis for a topology on the space $\mathcal{C}^n$, the space of all smooth oriented $d$-dimensional ...
jasnee's user avatar
  • 141
5 votes
1 answer
378 views

Why is this Brieskorn manifold a rational homology sphere?

In Némethi's book "Normal surface singularities", Example 5.1.17, there is a formula to find the Seifert invariants of a Brieskorn complete intersection $\Sigma(a_1,...,a_n)$. I am ...
user13121312's user avatar
1 vote
1 answer
91 views

When is a 2-bridge knot hyperbolic?

It is known that 2-bridge knots in $S^3$ can be classified by the Schubert form. My question is: which 2-bridge knots are hyperbolic? (Do we have a complete classification for hyperbolicity in 2-...
YC Su's user avatar
  • 605
25 votes
2 answers
2k views

Is there a continuous partition of space into circles?

Question 1. Is there a continuous partition of space $\mathbb{R}^3$ into circles? I strongly suspect not. It is well-known by diverse arguments that space can be partitioned into circles. There is an ...
Joel David Hamkins's user avatar
4 votes
1 answer
236 views

If a lattice can be embedded into $\mathbb Q^n,\langle-1\rangle^n$, then can it be embedded into $\mathbb Z^n,\langle -1 \rangle^n$?

Given a graph with negative integers on each vertex $\Gamma$ there is a corresponding intersection lattice denoted $Q_\Gamma$, a free $\mathbb Z$ module generated by the vertices, endowed with a ...
Márton Beke's user avatar
8 votes
1 answer
224 views

Can increasing the winding number of a 2-cell make a CW complex embeddable?

Let $X$ be a 2-dimensional CW complex and let $c\subset X$ be a 2-cell attached along a simple closed loop $\gamma$ in the 1-skeleton $X^{(1)}$. For a natural number $n\ge 2$ consider the operation of ...
M. Winter's user avatar
  • 13.6k
25 votes
1 answer
581 views

Does every oriented $3$-dimensional submanifold of $\mathbb{R}^6$ bound an oriented $4$-dimensional submanifold?

In my recent research, I encountered the following problem about embeddings. Let $M^3$ be a closed compact oriented smooth $3$-dimensional submanifold of $\mathbb{R}^6$. Does there exist a compact ...
Zhenhua Liu's user avatar
3 votes
2 answers
189 views

Necessary condition for invertible knot concordance from both ends

It is clear that if $K_1$ and $K_2$ are two concordant knots by a concordance that only present ambient isotopic phenomena (no saddles, maxima, or minima) they are invertible concordant from both ends....
jamp's user avatar
  • 31
-2 votes
1 answer
141 views

Existence of orientable finite volume complete cusp hyperbolic 3-manifolds $\mathbb{H}^3 / \Gamma$, where $\Gamma$ has no parabolic generators?

Let $K$ be a hyperbolic knot, i.e., $S^3 - K$ is an orientable finite volume cusp hyperbolic 3 manifold. Let $M=S^3 - K$ then $M= \mathbb{H}^3/\Gamma$, where $\Gamma$ (Kleinian group) is discret ...
T ghosh's user avatar
  • 111
0 votes
0 answers
128 views

The smallest dihedral angle of convex polyhedrons

Given a set of points $\{x_{k}\}_{k=0}^{m} \subset \mathbb{R}^n$, is it always possible to find a constant $c=c(m,n)>0$, depending only on the dimension $n$ and the number $m$, such that, after ...
sorrymaker's user avatar
3 votes
0 answers
51 views

Asymptotic dimension of graph families representing each finite group

Frucht's theorem says every finite group is isomorphic to the automorphism group of a simple graph $G$ (with no loops, multiple edges or directed edges). There has been interest in finding classes of ...
Agelos's user avatar
  • 1,926
4 votes
1 answer
172 views

Is every Cantor set $C\subseteq\mathbb R^{\infty}$ the limit set of a Fuchsian group?

Is every Cantor set $C\subseteq\mathbb R^{\infty}$ the limit set of a Fuchsian group? Let's recall the definitions. A Fuchsian group $G$ is a discrete subgroup of $\operatorname{PSL}(2,\mathbb R)=\...
Christian Remling's user avatar
5 votes
2 answers
199 views

Handle decompositions subordinate to an open cover

Let $M$ be a compact smooth manifold and let $\{U_i\}_{i\in I}$ be an open cover. We say a handle decomposition of $M$ is subordinate to the open cover if each handle is contained in a $U_i$. Do such ...
Stefan Friedl's user avatar
9 votes
0 answers
159 views

Is there a closed aspherical manifold with infinitely many symmetries and without essential immersed tori?

The precise question is the following: Is there a closed aspherical manifold $M$ of dimension $n\geq 3$ such that Out($\pi_1(M)$) is infinite and $\pi_1(M)$ does not contain $\mathbb Z \times \mathbb ...
Bruno Martelli's user avatar
11 votes
2 answers
517 views

Knots having the same Alexander module which are not S-equivalent

As is discussed in this answer, S-equivalence class can be regarded as the Alexander module plus Blachfield pairing, an isomorphism of some duals of Alexander modules. There are examples of knots ...
Tetsuya Ito's user avatar
6 votes
0 answers
299 views

Mapping class group of non-orientable three manifold

I do not work in topology, but for some reason we need to know the mapping class group of certain non-orientable 3 manifolds. We found answers online for a lot of orientable manifolds. But we still ...
Singularity's user avatar
3 votes
1 answer
150 views

Slice-ribbon conjecture in other 3-manifolds

There is some notion of what it means for a knot $K\hookrightarrow M$ to be "slice." In particular, we may ask, for example, that there is a topologically embedded disk in $M\times[0,1]$ ...
boink's user avatar
  • 245
8 votes
1 answer
349 views

Finite two-relator groups and quotients of knot groups

Let $G$ be a one-relator group $\langle A \mid R = 1 \rangle$. Then clearly $G$ is finite if and only if it is cyclic of finite order, i.e. can be given by a presentation $\langle a \mid a^n = 1 \...
Carl-Fredrik Nyberg Brodda's user avatar
24 votes
1 answer
862 views

The congruence subgroup property for mapping class groups and a conjecture of Grothendieck

This question is about a link between an open question in low-dimensional topology and a conjecture of Grothendieck, proved by Mochizuki. Let's start by stating them. Recall that a subgroup $K$ of a ...
HJRW's user avatar
  • 25k
10 votes
1 answer
443 views

Analytic continuation gives a covering space (and not just a local homeomorphism)

Let $\mathcal{G}$ be the space of germs of holomorphic functions defined on open subsets of $\mathbb{C}$, topologized in the usual way. There is a natural map $p\colon \mathcal{G} \rightarrow \mathbb{...
Paul's user avatar
  • 111
5 votes
0 answers
120 views

Can every orientation preserving homeomorphism of a manifold isotoped to be identity on a locally flat embedded disk?

Let $M$ be a connected (topological) oriented $m$-manifold (say without boundary), and let $\operatorname{Homeo}^+(M)$ be the group of orientation preserving homeomorphisms $M \to M$. Is it true that ...
Cihan's user avatar
  • 1,726
3 votes
0 answers
93 views

Finiteness of non-orientable 3-manifolds with the same orientable two-fold cover

Given a compact, orientable and boundary incompressible 3-manifold $M$. Suppose that either $M$ is closed, or $\partial M$ consists of tori. For which non-orientable 3-manifolds $N$, the orientable ...
YC Su's user avatar
  • 605
0 votes
0 answers
65 views

Approximating curves using only line sections and arcs

Given a curve $C$, I need to construct another curve $C'$ approximating $C$ under the following constraints: (1) $C'$ needs to be smooth, (2) $C'$ is composed of only line sections and arcs, (3) $C'$ ...
lchen's user avatar
  • 367
10 votes
0 answers
139 views

Space of thick ending laminations

Let $\Sigma$ be a compact closed connected oriented surface of genus $g>1$. Klarreich proved that the space of ending laminations $\mathcal{EL}(\Sigma)$ is the ideal boundary of the curve complex $...
Ian Agol's user avatar
  • 68.9k
9 votes
1 answer
401 views

Cohomological gap in arithmetic groups

$\DeclareMathOperator\SL{SL}$For the sake of this question, let's say that a group $G$ of finite cohomological dimension $n$ has a cohomological gap if for some $0 < i < n$ there is no subgroup $...
HASouza's user avatar
  • 423
8 votes
1 answer
352 views

Can I endow the following 3-manifold with a hyperbolic metric?

Consider the following three-dimensional topology. Start with $S^3$ and drill out four unlinked tori as shown in the picture. Then, fill in the gaps with the same tori but with their longitudes and ...
Holomaniac's user avatar
5 votes
3 answers
286 views

On a metrized $n$-dimensional manifold $X$, does every $x \in X$ have a small ball $B_\delta(x)$ that is homeomorphic to $\mathbb R^n$?

Suppose that $X$ is an $n$-dimensional topological manifold that is also metrizable, and hence equipped with some metric that induces the topology. For every point $x \in X$, let $B_\delta(x)$ be the ...
shuhalo's user avatar
  • 5,327
4 votes
1 answer
268 views

Seifert surfaces of fibered knots

Given a fibered knot $K\subseteq S^3$, does every genus-minimizing Seifert surface appear as the fiber of a bundle $S^3\setminus K\to S^1$?
mrburch's user avatar
  • 197
2 votes
0 answers
82 views

Is isoperimetric hypersurface unique up to homeomorphism?

Is there a Riemannian structure on $\mathbb{R}^n $with two non homeomorphic compact hypersurfaces $M,N$ such that both satisfy the isoperimetric inequality. I precisely meanthe following: $$\...
Ali Taghavi's user avatar
3 votes
1 answer
100 views

Representation of Lie groups inducing a quasi-isometric embedding of their symmetric spaces

Let $G_{1}$ and $G_{2}$ be connected semisimple real Lie groups with no compact factors and finite center and let $K_{1}$ and $K_{2}$ denote some fixed choice of their maximal compact subgroups, ...
Aleksander Skenderi's user avatar
5 votes
2 answers
221 views

$\mathbb{CP}(2)$ from gluing boundary of 4-ball

Many manifolds can be obtained from gluing the boundary of a ball. For example, $\mathbb{RP}(2)$ is obtained from gluing the two edges of a bi-gon (2-ball). Or, lens spaces are obtained from a 3-cell ...
Andi Bauer's user avatar
  • 3,001
4 votes
1 answer
230 views

The complement of a properly embedded annulus in a handlebody is a handlebody

Suppose $H_g$ is a genus $g$, orientable handlebody. Suppose $A\subset H_g$ is properly embedded ($\partial H_g \cap A = \partial A$, a transverse intersection), non-$\partial$-parallel annulus. It ...
luthien's user avatar
  • 421
4 votes
0 answers
154 views

Is there a notion of "locally flat" for CW complexes?

A submanifold $X^n\subset Y^m$ is locally flat if each point $x\in X$ has a neighborhood $U\subset Y$ so that $(U,U\cap X)\simeq (\Bbb R^m, \Bbb R^n)$ with the standard embedding $\Bbb R^n\...
M. Winter's user avatar
  • 13.6k
3 votes
1 answer
161 views

How to properly define a slice knot (or a locally flat disk)?

A knot $K\subset\Bbb S^3=\partial \Bbb D^4$ is said to be (topolopgically) slice if there is a locally flat disk $D\subset\Bbb D^4$ with $\partial D=D\cap \Bbb S^3=K$. As far as I understand, locally ...
M. Winter's user avatar
  • 13.6k