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14 votes
2 answers
1k views

If every definable class admits a group structure, must global choice hold?

It is a remarkable fact, due to Hajnal and Kertész and explained very well in this MathOverflow answer by user Ashutosh, that the axiom of choice is equivalent to the assertion that every nonempty set ...
Joel David Hamkins's user avatar
8 votes
0 answers
148 views

What is this quotient of the free product?

Previously asked at MSE. The construction here can generalize to arbitrary algebras (in the sense of universal algebra) in the same signature with the only needed tweak being the replacement of "...
Noah Schweber's user avatar
3 votes
1 answer
153 views

Is having a Frobenius pair first-order expressible in the language of groups?

I am trying to figure out whether or not the following property is first-order expressible in the language of groups. $$\text{$G$ has a subgroup $H$ with which it forms a Frobenius pair $(H,G)$.}$$ My ...
Y. Tamer's user avatar
  • 133
9 votes
0 answers
275 views

Is “simplicity is elementary” still hard? (Felgner’s 1990 theorem on simple groups, and subsequent work)

I came across a reference in this MathOverflow answer to an intriguing result of Ulrich Felgner [1]: among finite non-Abelian groups, the property of being simple is first-order definable. According ...
Peter LeFanu Lumsdaine's user avatar
4 votes
1 answer
125 views

Logical generators of groups and $\mathrm{Aut}$-bases

An element $s$ of a group $G$ is a logical generator of $G$ iff every element of $G$ can be defined in the first order language of groups with $s$ as a parameter. In this case we may call $G$ a ...
Sh.M1972's user avatar
  • 2,233
8 votes
1 answer
896 views

Quantifier elimination for abelian groups

In the Wikipedia article (https://en.wikipedia.org/wiki/Quantifier_elimination#cite_note-4) it is said that every abelian group has quantifier elimination property and a long old paper of W. Szmielew ...
Sh.M1972's user avatar
  • 2,233
7 votes
1 answer
143 views

Is there a pseudofinite group with a quantifier-free instance of the order property?

Recall that a group $G$ is pseudofinite if every first-order sentence $\varphi$ (in the language of groups) satisfied in $G$ is also satisfied in some finite group. Also recall that an instance of the ...
James E Hanson's user avatar
12 votes
2 answers
583 views

Do there exist acyclic simple groups of arbitrarily large cardinality?

Recall that a group $G$ is acyclic if its group homology vanishes: $H_\ast(G; \mathbb Z) = 0$. Equivalently, $G$ is acyclic iff the space $BG$ is acyclic, i.e. $\tilde H_\ast(BG;\mathbb Z) = 0$. In ...
Tim Campion's user avatar
  • 63.9k
8 votes
2 answers
585 views

Is the equational theory of groups axiomatized by the associative law?

Consider the class of groups in the signature {*}. Is the equational theory of that class axiomatized by the associative law? I asked this on math stack exchange but I didn't receive a satisfactory ...
user107952's user avatar
  • 2,023
6 votes
2 answers
186 views

What can the approximation of a group by some class be used for?

Recall the following concept due to Malcev and Gromov. Let $C$ be some class of groups. A group $G$ is said to be approximable by the class $C$ if for every finite symmetric subset $F\subset G$ ...
Leo's user avatar
  • 163
17 votes
2 answers
2k views

Why are model theorists so fond of definable groups?

My PhD was on so called "pure" model theory, and my advisor was not very much interested in applications of model theory to algebra. Now I feel the need to fill in the gap, and I'd like to educate ...
huurd's user avatar
  • 1,031
0 votes
0 answers
147 views

Groups implementable by finite field

I'm interested in finding all groups for which the group operation (and inverse map) may be implemented using finite field arithmetic. I've done some searching and have come across "algebraic groups",...
user135066's user avatar
7 votes
0 answers
177 views

Countable elementary sub-structure of the automorphism group of the binary rooted tree

Let $G$ be the automorphism group of the binary rooted tree. The downward Löwenheim-Skolem theorem states that G has a countable elementary sub-structure. My question is whether such sub-structure ...
Mustafa Gokhan Benli's user avatar
2 votes
1 answer
190 views

Logic article on first-order invariants of abelian groups

I remember reading an article published in the 1970s by a Polish mathematician describing the first-order invariants of a torsion-free abelian group. I do not recollect the author's name, the title of ...
Phill Schultz's user avatar
9 votes
1 answer
276 views

First order formulas for finite groups and invariant theory

Let $G$ be a finite group, and let $K$ be a field of characteristic zero. Let $\phi(x_1,\ldots,x_n)$ be a first order formula in the language of group theory (so $\phi$ can be for example something of ...
Ehud Meir's user avatar
  • 5,039
6 votes
2 answers
706 views

Non-trivial problems about the trivial group

Is there any non-trivial problem (maybe open problem) about the trivial group? I asked already a question about the Laws characterizing the trivial group. There is a description of such laws. As ...
Sh.M1972's user avatar
  • 2,233
8 votes
1 answer
312 views

Elementary extensions of direct product

I apologize if this question is elementary: Let $A$, $B$, and $A^{\prime}$ be groups such that $A^{\prime}$ is an elementary extension of $A$. Is it true that $A^{\prime}\times B$ is an elementary ...
Sh.M1972's user avatar
  • 2,233
12 votes
2 answers
621 views

Eliminating constant in Rado graph

Let $R$ denote the Rado graph, and let $c$ be a fixed vertex. Question 1. Is the structure obtained by extending $R$ by the constant $c$ interpretable in $R$ without parameters? By interpretable I ...
Szymon Toruńczyk's user avatar
12 votes
0 answers
468 views

A question concerning model theory of groups

Several days ago, Professor Martin Bridson gave a very nice talk in my department. Some questions concerning his talk came into my brain Since I am neither a model theorist nor a algebraist, I am not ...
喻 良's user avatar
  • 4,201
9 votes
1 answer
695 views

Extending an infinite simple group

Maybe the question does not fit here. Yesterday in my logic course, I presented a nice example about an application of model theory to group theory. The example is due to Hodges and as following: For ...
喻 良's user avatar
  • 4,201
2 votes
1 answer
330 views

Algebras admitting quantifier elimination

I apologize if this question is meaningless or trivial: What are examples of Algebras admitting quantifier elimination? Especially are there Groups admitting quantifier elimination? I need to say ...
Sh.M1972's user avatar
  • 2,233
25 votes
1 answer
3k views

A preprint of Sela concerning the work of Kharlampovich-Miyasnikov

Yesterday, Z. Sela published a preprint in arXiv which claims that the solution of Olga Kharlampovich and Alexi Miyasnikov for the Tarski problem on decidablity of the first order theories of free ...
Sh.M1972's user avatar
  • 2,233
0 votes
3 answers
185 views

Negated varieties and their relatively free algebras

During the past days, I asked some questions in order to gain a clear understanding of the notion of "free algebras". I suppose that the question below is the most clear image of the concept I have ...
Sh.M1972's user avatar
  • 2,233
5 votes
3 answers
309 views

The existence of an algebra whose set of identities and first order theory are equivalent

Is there an algebra $A$ (for example a group) such that $Th(A)$ is logically equivalent to $id(A)$? In other words, is there an algebra $A$ such that $$ Mod(Th(A))=Var(A)? $$ Clearly finite algebras ...
Sh.M1972's user avatar
  • 2,233
2 votes
4 answers
555 views

relatively free groups in $Var(S_3)$

Suppose $S_3$ is the symmetric group of order 6. Which elements of the variety $Var(S_3)$ are relatively free? This question is related to my previous question Relatively free algebras in a variety ...
Sh.M1972's user avatar
  • 2,233
11 votes
1 answer
1k views

Cherlin's "Main Conjecture"

Cherlin's "Main Conjecture" from his 1979 paper "Groups of Small Morley Rank" is the following: Every simple $\omega$-stable group is an algebraic group over an algebraically closed field. Zilber was ...
James Freitag's user avatar