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14 votes
4 answers
1k views

Obtain any 3-manifold from repeating surgeries on knots in $S^3$

In Witten's “QFT and Jones Polynomials” paper, page 383, it states that: "It is a not too deep result that every 3-manifold can be obtained from or reduced to $S^3$ (or any other desired 3-manifold) ...
miss-tery's user avatar
  • 755
12 votes
4 answers
1k views

Elementary proof that knot complements are path-connected

The complement of any (topological) knot is path-connected. More precisely, if $K$ is a subset of $\mathbb{R}^3$ (or $S^3$) homeomorphic to $S^1$, then $\mathbb{R}^3\setminus K$ (or $S^3\setminus K$) ...
Mark Grant's user avatar
  • 35.9k
10 votes
1 answer
207 views

The knot $K\subset \Bbb S^3$ is smoothly slice, but the disc $D\subset \Bbb D^4$ is only locally flat. Can $D$ be smoothed?

Suppose I am given a smoothly slice knot $K\subset\Bbb S^3$. But I am only given a locally flat disc $D\subset \Bbb D^4$ with boundary $K$. Question: Is there a smooth disc $D'\subset\Bbb D^4$ with ...
M. Winter's user avatar
  • 13.6k
3 votes
1 answer
161 views

How to properly define a slice knot (or a locally flat disk)?

A knot $K\subset\Bbb S^3=\partial \Bbb D^4$ is said to be (topolopgically) slice if there is a locally flat disk $D\subset\Bbb D^4$ with $\partial D=D\cap \Bbb S^3=K$. As far as I understand, locally ...
M. Winter's user avatar
  • 13.6k
3 votes
1 answer
292 views

Can a closed trefoil appear as a space-time "cut" of an open trefoil?

An open trefoil is a trefoil tied in an infinitely long line. An open trefoil that is at rest in (flat) space, in space-time is a knotted hypersurface. Different observers in space-time have ...
Chris's user avatar
  • 75
3 votes
0 answers
106 views

A link of four 2-tori $T^2$ in $S^3 \times S^1 \# S^2 \times S^2 \# S^2 \times S^2$

Step 1: We glue two sets of complement space of $D^2\times T^2$ out of the 4-sphere $S^4$, through their $T^3$ boundary to obtain a new 4-manifold: $$(S^4 \smallsetminus D^2\times T^2) \cup (S^4 \...
wonderich's user avatar
  • 10.5k
2 votes
1 answer
166 views

What is the most symmetric configuration of four 2-surfaces linked in $S^4$?

What are some of the most symmetric configurations of four 2-surfaces linked in the 4-dimensional sphere $S^4$? To make a lower-dimensional analogy, recall that in 3-dimensional sphere $S^3$, we can ...
wonderich's user avatar
  • 10.5k
1 vote
1 answer
91 views

When is a 2-bridge knot hyperbolic?

It is known that 2-bridge knots in $S^3$ can be classified by the Schubert form. My question is: which 2-bridge knots are hyperbolic? (Do we have a complete classification for hyperbolicity in 2-...
YC Su's user avatar
  • 605
0 votes
1 answer
277 views

Are knot invariants topological invariants? [closed]

I am a bit confused about terminology considering topology and knot theory. A topological invariant is considered to be a topological property that does not change under a homeomorphism of the space. ...
Jake B.'s user avatar
  • 1,465
0 votes
1 answer
210 views

Questions on the proof Lemma 4.5 GTM 175, Lickorish

I am reading GTM 175 An introduction to knot theory by Lickorish and have some questions on the proof of Lemma 4.5 given. For (a), it says "Suppose that $C$ is amongst the $n$ components of $F\...
user174967's user avatar