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14 votes
3 answers
2k views

How should I think about the Grothendieck-Springer alteration?

Given a simple complex Lie algebra $\mathfrak{g}$, recall the Springer resolution of its nilpotent cone $\widetilde{\mathcal{N}}\to \mathcal{N}$. Several times I have seen someone explaining Springer ...
Spencer Leslie's user avatar
5 votes
1 answer
675 views

Is it possible to describe the action of the Weyl group on the cohomology of the fibers of the Grothendieck-Springer resolution?

I am confused about the following: can one describe the action of the Weyl group on the cohomology of each fiber of the Grothendieck-Springer resolution? I only need the case of ${\mathfrak sl}_n$. ...
Yellow Pig's user avatar
  • 2,964
2 votes
1 answer
227 views

Component group of stabilizer group of a nilpotent element

Let $G$ be a semisimple complex algebraic group, and $\mathfrak{g}$ be its Lie algebra. $G$ acts on $\mathfrak{g}$ by adjoint action. Let $x$ be an nilpotent element in $\mathfrak{g}$, and $G(x)\...
fool rabbit's user avatar
2 votes
0 answers
180 views

Are parabolic Springer fibers equal dimensional?

Let $G$ be a simple algrbraic group ( of type BCDEFG ) over the complex number $\mathbb{C}$, let $P$ be a parabolic subgroup of $G$, suppose we have a resolution of singularities $\mu: T^*(G/P)\to \...
fool rabbit's user avatar