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2 votes
1 answer
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If $S\subseteq A^*$ is separating, does $S$ also separate $M(A)$?

Let $A$ be a non-unital $C^*$-algebra. Let $S\subseteq A^*$ be a set of continuous functionals that separates the points of $A$. Every element $\omega \in A^*$ extends uniquely to a strictly ...
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2 votes
1 answer
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$(\iota \otimes f)(X) = 0$ for all $f \in B^*$ implies $X=0$

Let $A$ and $B$ be $C^*$-algebras. Given $f \in B^*$, we can form the right slice map $$\iota \otimes f: A \otimes B \to A: a \otimes b \mapsto af(b)$$ which extends uniquely to a bounded linear map $$...
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4 votes
1 answer
225 views

Direct sum of multiplier algebras

Consider a collection of $C^*$-algebras $\{A_i\}_{i \in I}$. We can form the direct sum $$\bigoplus_{i \in I}^{c_0} A_i:= \left\{(a_i)_{i \in I} \in \prod_{i\in I} A_i: \lim_{i \in I} \|a_i\| = 0\...
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3 votes
1 answer
476 views

Strict topology on the multiplier algebra

Let $A$ be a $C^*$-algebra. Let $M(A)$ be its multiplier $C^*$-algebras. The strict topology on $M(A)$ is given by $$x_\lambda \to x \iff \forall a\in A: (\|x_\lambda a-xa\| + \|ax_\lambda - ax\| \to ...
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