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Inductive/Projective Limits of Topological Algebras

It is common to form inductive/projective limits of Banach/Frechet spaces in order to come up with natural topologies for common vector spaces. For instance, For $k \ge 0$ and $K_n$ compact ...
user68620's user avatar
7 votes
1 answer
362 views

Nonexpansive multi-valued maps in $\ell^2$

Let $C$ be a nonempty bounded closed convex subset, say the unit ball, of $\ell^2(\mathbb{N})$. Let $T: C\to 2^C$ be a map such that $T(x)$ is nonempty closed for each $x$, and that $$D(Tx,Ty)\le \|x-...
TCL's user avatar
  • 744
7 votes
0 answers
294 views

Applications of Banach space homology

There is a well-developed theory of Banach space homology. What are some of its useful applications to Banach space theory and which important questions can one answer using it? In other words, how ...
Andromeda's user avatar
  • 175
7 votes
0 answers
124 views

The bidual of the space of divergence-free vector fields

Consider the Banach space $L_1(\mathbb R^n, \mathbb R^n)$ of integrable vector fields $(n>1$) together with its subspace $N$ formed by those vectors fields whose divergence (computed in the ...
Tomasz Kania's user avatar
  • 11.3k
7 votes
0 answers
248 views

Isometries on the unit sphere

Suppose that $X$ and $Y$ are two Banach spaces, $S_{X}$ and $S_{Y}$ their unit spheres, and $f$ an onto isometry between $S_X$ and $S_Y$. Does it follow that $X$ and $Y$ are isometric?
Markus's user avatar
  • 1,361
7 votes
0 answers
177 views

Does this ideal in $B(L_1)$ have a (bounded) right approximate identity?

I will take a roundabout way to defining this ideal, because (a) this route is how my collaborators and I came to it (b) this alternative definition, rather than the standard one, may suggest a ...
Yemon Choi's user avatar
  • 25.8k
7 votes
0 answers
327 views

Status of two Banach space theory open problems posted by Pełczyński

In the book 'Open Problems in the Geometry and Analysis of Banach Spaces', I am interested in the following two problems. Problem $1$: Let $X$ be a separable infinite-dimensional Banach space that is ...
Idonknow's user avatar
  • 623
7 votes
0 answers
200 views

Equivalent strictly convex norms in spaces of small density

Can one construct in ZFC a Banach space of density character $\omega_1$ that does not have an equivalent strictly convex norm? Maybe one may apply some kind of a Löwenheim–Skolem-type argument to a ...
Tomasz Kania's user avatar
  • 11.3k
7 votes
0 answers
183 views

Is there a quotient of $c_0$ without the approximation property?

The famous example of Enflo of a Banach space without the approximation property is actually a subspace of $c_0$. Is there a quotient of $c_0$ without the approximation property? This would follow if ...
user136256's user avatar
7 votes
0 answers
559 views

The Banach space of bounded functions with countable support

Let $X$ be a set of cardinality $\aleph_1$ and consider the Banach space $\ell_\infty^c(X)$ of all scalar-valued bounded functions on $X$ which are non-zero only for countably many elements of $X$ ...
Tomasz Kania's user avatar
  • 11.3k
7 votes
0 answers
293 views

Complex interpolation of a Banach space and its antidual when the space has a basis

Given a complex Banach space $X$ and its antidual $\hat X^*$, it is possible in some cases to apply the complex interpolation method, and get as $(X,\hat X^*)_{1/2}$ a Hilbert space. See [F. Watbled, ...
M.González's user avatar
  • 4,461
7 votes
0 answers
708 views

Minkowski's Inequality for Integrals in Orlicz spaces

EDIT: I have changed the question to have less parameters, fitting it into the context of Orlicz spaces. Suppose $f:[0,\infty)\to[0,\infty)$ is convex and increasing, $f^{-1}:[0,\infty)\to[0,\infty)$...
Daniel Spector's user avatar
7 votes
0 answers
4k views

Explicit element of $(\ell^{\infty})^* - \ell^1$? [duplicate]

Possible Duplicate: What’s an example of a space that needs the Hahn-Banach Theorem? It is well known that the dual of $\ell^{\infty}$ properly contains $\ell^1$ (over $\mathbb{N}$, say). ...
Akhil Mathew's user avatar
  • 25.6k
6 votes
3 answers
2k views

reflexive banach space

I want to ask this non-expert question: What does it mean geometrically for a Banach space to be reflexive? Well, we could say a Banach space is reflexive iff unit ball is weakly compact. Or some ...
alpx's user avatar
  • 351
6 votes
3 answers
3k views

Why isn't the theorem of approximation applicable in Banach spaces?

Let X be a Hilbert space, A a convex, closed subset of X. Then there exists for every x in X exactly one best approximation in A, that is there exists a y in A such that || x-y || = d(x,A) = inf { || ...
Linda Raabe's user avatar
6 votes
2 answers
4k views

Question about Schauder bases in C([0,1]).

I would like to check a statement about Schauder bases in $C([0,1])$ to be sure that I don't lie to my students on Monday. The statement(s) that I would like to check are: The family of monomials $\{...
Andrew Stacey's user avatar
6 votes
3 answers
852 views

Are nuclear operators closed under extensions?

Given $X_i, Y_i$ Banach spaces, $f_j, g_j, T_i$ bounded linear operators for $i=1,2,3$ and $j=1,2$. We have the following diagram $\require{AMScd}$ \begin{CD} 0 @>>> X_1 @>f_1>> X_2 ...
santker heboln's user avatar
6 votes
3 answers
427 views

Point-wise limit of finite valued functions

Let $X$ be a second countable topological vector space. Does there exist any sequence of finite valued functions $f_n\colon X\to X$ converging point-wise to the identity mapping on $X$?
ABB's user avatar
  • 4,058
6 votes
3 answers
2k views

Space of compact operators

I am interested in the Banach space $\mathcal{K}=\mathcal{K}(\ell^2)$ of compact operators on $\ell^2$, however my questions can be stated for any $\mathcal{K}(E)$, where $E$ is an arbitrary Banach ...
Tomasz Kania's user avatar
  • 11.3k
6 votes
3 answers
3k views

Non-empty resolvent set, then operator closed?

On Hilbert spaces, the following is true: Let $T$ be a densely-defined linear operator with non-empty resolvent set, then $T$ is closed. The obvious proof I see to show this uses explicitly the ...
gipom's user avatar
  • 115
6 votes
2 answers
749 views

Transpose of unbounded operators between Banach spaces.

Let $X$ and $Y$ be Banach spaces, and let $L : X \rightarrow Y$ be a unbounded operator with dense domain $\operatorname{dom}(L)$. We can then talk about the transposed operator $L' : \operatorname{...
shuhalo's user avatar
  • 5,327
6 votes
2 answers
1k views

Closed, complemented subspaces of $l^1(X)$ when $X$ is uncountable

... are all isomorphic to $l^1$ on some other index set. At least, that much I "know" from 2nd-hand sources, since the original proof is apparently in a paper of Köthe from the 1930s 1960s (in ...
Yemon Choi's user avatar
  • 25.8k
6 votes
2 answers
548 views

When is it $C(X)$?

Suppose that $\tilde{X}$ is a compact space. If $C(\tilde{X})$ is isometrically isomorphic to the second dual of a Banach space, does there exist a locally compact space $X$ such that $C(\tilde{X})=...
Bob's user avatar
  • 306
6 votes
1 answer
618 views

Whether Krein-Milman property implies Radon-Nikodym property

A Banach space is said to have Krein-Milman property (KMP in short) if every closed bounded convex set of it is a closed convex hull of its extreme points. Eg. Any reflexive space has KMP, $\ell_1$ ...
Tanmoy Paul's user avatar
6 votes
1 answer
270 views

Approximation property counterexamples? (Also: relation to tensor products)

I remember reading somewhere (but unfortunately, I've forgotten where it was) that the canonical map from the (completed) projective tensor product of two Banach spaces to the (completed) injective ...
Jeff Egger's user avatar
6 votes
2 answers
735 views

Tensor product space with projective norm is incomplete

Ryan says in his book "Introduction to Tensor Products of Banach Spaces"(pg. 17) that for Banach spaces $X$ and $Y$, $X\otimes Y$ equipped with projective norm is not complete unless $X$ and $Y$ are ...
CSH's user avatar
  • 163
6 votes
2 answers
3k views

Closed convex bounded sets are weakly compact for which spaces?

It is known that for all reflexive Banach spaces, closed convex bounded sets are weakly compact (compact for the weak topology). What is the general class of topological vector spaces for which this ...
Jon-S's user avatar
  • 549
6 votes
2 answers
282 views

The Calkin representation for Banach spaces

Let $X$ be an infinite dimensional Banach space. Let $\Lambda_{0}$ be the set of all finite dimensional subspaces of $X$ directed by the inclusion $\subseteq$. For each $\alpha\in \Lambda_{0}$, let $...
Dongyang Chen's user avatar
6 votes
3 answers
2k views

Generalized Hardy-Littlewood-Sobolev Inequality

The Hardy-Littlewood-Sobolev Inequality says that $$\text{for $p,q,r\in (1,+\infty)$ such that }\quad 1-\frac1p+1-\frac1q=1-\frac1r,\tag {$\sharp$} $$ $$ \exists C, \forall u\in L^p(\mathbb R^n),\...
Bazin's user avatar
  • 16.2k
6 votes
3 answers
1k views

Is the set of the absolutely continuous functions a Borel set of the space of the continuous functions?

Does anyone knows whether the set of the absolutely continous functions $F :[0,1]\to \mathbb{R}^d$ of the form $$F(t)= a + \int_0^tf(s) ds$$ where $f$ is an integrable function is a Borel set of the ...
Theluze's user avatar
  • 125
6 votes
1 answer
404 views

Unique preduals up to (nonisometric) isomorphism?

It's well known that there are Banach spaces which has a unique isometric predual-- for example, any von Neumann algebra. As other questions on here (for example, Isomorphisms of Banach Spaces ) ...
Matthew Daws's user avatar
  • 18.7k
6 votes
2 answers
3k views

Dense inclusions of Banach spaces and their duals

This seems like a really simple question, but I'm struggling with it. Let $X$ be a separable Banach space, $H$ be a separable Hilbert space, and suppose $i : H \hookrightarrow X$ is a dense, ...
Tom LaGatta's user avatar
  • 8,512
6 votes
1 answer
381 views

Convolution with semigroup: does this belong to the Sobolev space $W^{1,1}$?

Let $X$ be a Banach space, $T(t)$ be a strongly continuous semigroup on $X$, and $f\in L^1(0,\tau;X)$. It has been implied that the integral $$v(t)=\int_0^t T(t-s)f(s)ds,\quad t\in [0,\tau]$$ is not ...
Saj_Eda's user avatar
  • 395
6 votes
1 answer
826 views

Non-reflexive Banach space s.t. X,X*,X**,... are separable

Is there an infinite-dimensional Banach space $X$, which is not reflexive, such that all the spaces $X,X^{\ast},X^{\ast\ast}, X^{\ast\ast\ast},\dots$ are separable?
Jens Reinhold's user avatar
6 votes
1 answer
353 views

Sequential continuity of linear operators

Let $u\colon L\to M$ be a linear map of locally convex linear topological vector spaces. Assume that $u$ is sequentually continuous, i.e. maps convergent sequences to convergent ones. (This notion is ...
asv's user avatar
  • 21.8k
6 votes
2 answers
426 views

Ultrapowers of operators

Can we prove that for each infinite dimensional Banach space $X$ and any free ultrafilter (possibly over uncountable set of indices) $\mathcal{U}$ the obvious embedding $$({\mathcal{L}(X)})_{\mathcal{...
Slavoj Žižek's user avatar
6 votes
1 answer
335 views

Existence of pairwise quasi-complementary but not complementary subspaces

Let $𝑋$ be an infinite-dimensional Banach space (complex or real). A subspace of $𝑋$ means a closed linear submanifold. Subspaces $M$ and $N$ of $X$ are quasi-complementary if $M\cap N=\{0\}$ and $M+...
Janko Bracic's user avatar
6 votes
2 answers
458 views

Subspaces of $\ell_p$ ($1<p<\infty$, $p\neq 2$) not isomorphic to $\ell_p$

Is it possible to show the existence of an infinite dimensional closed subspace of $\ell_p$ ($1<p<\infty$, $p\neq 2$), not isomorphic to $\ell_p$, in an elementary way? For $1<p<q<2$,...
M.González's user avatar
  • 4,461
6 votes
2 answers
240 views

Continuity of a differential of a Banach-valued holomorphic map

Originally posted on MSE. Let $U$ be an open set in $\mathbb{C}^{n}$ let $F$ be a Banach space (in my case even a dual Banach space), and let $\varphi:U\to F$ be a holomorphic map. I seem to be able ...
erz's user avatar
  • 5,529
6 votes
1 answer
237 views

Radon-Nikodym property in Diestel & Uhl: a definition clarification

I posted the following question on MSE originally because, not being research-level, it seemed more appropriate for that site. However, there was no activity for it on MSE and I feel that it certainly ...
JWP_HTX's user avatar
  • 201
6 votes
1 answer
267 views

Unconditionally convergent series in $\ell_2$ consisting of $\ell_1$-small vectors

For a function $x:\omega\to\mathbb R$ let $|x|$ denote the function $|x|:\omega\to[0,\infty)$, $|x|:n\mapsto|x(n)|$. It is well-know that a series $\sum_{n\in\omega}r_n$ of real numbers converges ...
Taras Banakh's user avatar
  • 41.8k
6 votes
2 answers
509 views

A question on Grothendieck space

A Banach space $X$ is said to be Grothendieck if the weak and the weak* convergence of sequences in $X^{*}$ coincide. I have the following two questions. Question 1. A Banach space $X$ is Grothendieck ...
Dongyang Chen's user avatar
6 votes
1 answer
377 views

quick question about renorming quasi-Banach spaces into p-Banach spaces

I have a quick question which is probably supposed to be obvious, but for some reason I just don't see it: How does one re-norm a quasi-Banach space to produce a $p$-Banach space ($0<p\leq 1$) ...
Ben W's user avatar
  • 1,591
6 votes
1 answer
450 views

Is each compact metric space a subset of a compact absolute 1-Lipschitz retract?

A metric space $X$ is called an absolute $L$-Lipschitz retract if for any metric space $Y$ containing $X$ there exists a Lipschitz retraction $r:Y\to X$ with Lipschitz constant $Lip(r)\le L$. ...
Taras Banakh's user avatar
  • 41.8k
6 votes
1 answer
238 views

Extending a weak*-converging sequence onto a superspace

Let $X$ be a real Banach space and $Y\subset X$ be a (closed) subspace of $X$. Assume that a sequence $y_n^*\in S_{Y^*}$ weak*-converges to some $y^*\in S_{Y*}$. (Here $S_{Y^*}$ stands for the dual ...
Miroslav Bacak's user avatar
6 votes
1 answer
223 views

Is the space of vectorial functions that are Dunford integrable complete?

Let $X$ a Banach Space and $(\Omega, \Sigma, \mu)$ a measure space. A function $F:\Omega\rightarrow X$ is Dunford integrable if $x^\ast\circ F$ is $\mu$-integrable for every $x^\ast\in X^\ast$. The ...
Husaí Vázquez's user avatar
6 votes
2 answers
405 views

$\|T\|_2 \le \sqrt{\|T\|_1\|T\|_\infty}$

Let $T$ be a linear operator acting on a finite-dimensional real or complex vector space. As a direct consequence (or rather a particular case) of the Riesz-Thorin theorem, we have $$ \|T\|_2 \le \...
Seva's user avatar
  • 23k
6 votes
1 answer
364 views

A question about uniformly bounded semigroups

Let $A$ be an unbounded linear operator of domain $D(A)$ defined on a Banach space $X$. Suppose that $A$ generates a $C_0$-semigroup $T(t)$ which is uniformly bounded. I would like to know if there ...
driss-alamilouati's user avatar
6 votes
1 answer
2k views

Existence of injective operators with dense range

Given two separable (infinite dimensional) Banach spaces $X$ and $Y$, it is not difficult to show that there exists an injective (bounded linear) operator $T:X\to Y$ with range dense in $Y$. See S. ...
M.González's user avatar
  • 4,461
6 votes
1 answer
273 views

Quasi-reflexive spaces which are not isometric to dual spaces

My question may sound weird and I have no deep motivation behind it other than curiosity. As is well-known, quasi-reflexive spaces have the Radon-Nikodym property hence their balls have lots of ...
Prawem_Kaduka's user avatar

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