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2 votes
0 answers
172 views

Lattice paths avoiding holes

Consider lattice paths from $(0,0)$ to $(2n,2n)$ with steps $N=(0,1)$ and $E=(1,0)$ avoiding the points $(2i-1,2i-1)$ for all $1\leq i\leq n$. There are Catalan many $C_{2n}=\frac1{2n+1}\binom{4n}{2n}$...
T. Amdeberhan's user avatar
1 vote
0 answers
100 views

Super Catalan (super ballot) numbers

We refer to this article by Ira Gessel. In section 6, page 10, equation (28), the Super Catalan numbers are defined as $$S(m,n)=\frac{(2m)!(2n)!}{m!n!(m+n)!}.$$ On page 12, equation (31), there goes ...
T. Amdeberhan's user avatar
4 votes
0 answers
205 views

Non-crossing and crossing bijection in higher genus

This is a follow-up question of my SO post I'll briefly mention it here. So given a $n$ cycle say $(1,2,\ldots,n)$, what are the monotonic 2 -tuples, of the form $(a,b)(c,d)$, monotonicity in on the ...
GGT's user avatar
  • 685
2 votes
1 answer
141 views

Counting monomials and $q$-Catalan polynomials

Define $N(F)$ to be the number of monomials of a multi-variable polynomial $F$. For example $N(x^2y+3xy-y^5)=3$. If $\mathbf{x}=(x_1,\dots,x_n)$ and $F_n(\mathbf{x})=\prod_{k=1}^n(x_1+\cdots+x_k)$ ...
T. Amdeberhan's user avatar
4 votes
1 answer
221 views

Reference for a definition of Catalan numbers

The $l$-th Catalan number ${2l\choose l}\frac{1}{l+1}$ is equal to the number of sequences $s_0,\ldots,s_{l+1}$ of length $l+2$ with the following properties: (1) $s_0=s_{l+1}=1$ and $s_1,\ldots,s_l$ ...
Roland Bacher's user avatar
5 votes
1 answer
347 views

Counting monomials and the Catalan numbers

Given a multi-variable polynomial $F$, denote the number of monomials by $N(F)$. Take for instance, \begin{align*}N(x(x+y)+(x+y)^2-(x-y)^2)=N(x^2+5xy)&=2 \qquad \text{and} \\ N((x+z)(x+y)^2)=N(x^3 ...
T. Amdeberhan's user avatar
2 votes
1 answer
199 views

Sequence of monotone tuples and permutation condition for rotation

I was doing some counting in $S_n$ symmetric group I encountered the following problem, which also someway related to central factorial number. So given a $n$ cycle say $(1,2,\ldots,n)$, what are the ...
GGT's user avatar
  • 685
0 votes
1 answer
148 views

What is this numerically-generated function?

This question is an "outgrowth" of https://math.stackexchange.com/questions/4380919/ which led to a numerically-generated two-parameter function $f_b(n)$, where $b$ is the number base $2,3,4,...
eigengrau's user avatar
  • 103
6 votes
1 answer
281 views

Another generalization of parity of Catalan numbers

Recently, a question by T. Amdeberhan gathered up many enjoyable proofs that a Catalan number $C_n$ is odd if and only if $n=2^r-1$. Noam D. Elkies' answer considered $F=\sum_{n=0}^\infty C_n x^{n+1}$....
user196574's user avatar
7 votes
1 answer
608 views

Reciprocity for fans of bounded Dyck paths

This is a continuation of some questions asked by Johann Cigler: Number of bounded Dyck paths with "negative length" and Number of bounded Dyck paths with negative length as Hankel ...
Sam Hopkins's user avatar
  • 24.2k
13 votes
1 answer
564 views

Coincidences between average Catalan tableaux

There are Catalan number $C_n$ of standard Young tableaux of shape $(n,n)$, which we view as $2\times n$ matrices. Denote by $P_n$ the average of these matrices: $$ P_n \, := \, \frac{1}{C_n} \, \...
Igor Pak's user avatar
  • 17k
4 votes
1 answer
597 views

genus zero permutation and noncrossing partition

Question Let $g$ to be an element of permutation group $S_n$, and $\tau = (1,2,3,\cdots,n)$ is the circular permutation. $g$ and $\tau g$ have $n+1$ cycles in total(fixed point is also a cycle), ...
anecdote's user avatar
  • 165
3 votes
1 answer
366 views

A recurrence relation on Catalan numbers

In the classical problem of bracketing $n$ numbers, I know the response is $C_{n-1}$. I find this $$C_{n-1}=\sum_{i=1}^{\left\lfloor\frac{n}{2}\right\rfloor}(-1)^{i+1}\binom{n-i}{i}C_{n-1-i}$$ but I ...
Joan Tarrasso's user avatar