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36 votes
1 answer
2k views

On a remark of Tait on FLT for the exponent 3

This is one of those recreational questions that aren't really about research. I found a curious remark in an old volume of American Mathematical Monthly (1922) which I'll quote below: In the ...
Gjergji Zaimi's user avatar
27 votes
4 answers
11k views

Is there an elementary way to find the integer solutions to $x^2-y^3=1$?

I gave this problem to my undergraduate assistant, as I saw that Euler had originally solved it (although I am having trouble finding his proof). After working on it for two weeks, we boiled the hard ...
Pace Nielsen's user avatar
  • 18.7k
13 votes
3 answers
3k views

Solving the quartic equation $r^4 + 4r^3s - 6r^2s^2 - 4rs^3 + s^4 = 1$

I'm working on solving the quartic Diophantine equation in the title. Calculations in maxima imply that the only integer solutions are \begin{equation} (r,s) \in \{(-3, -2), (-2, 3), (-1, 0), (0, -1),...
11 votes
1 answer
619 views

Diophantine equation $3^a+1=3^b+5^c$

This is not a research problem, but challenging enough that I've decided to post it in here: Determine all triples $(a,b,c)$ of non-negative integers, satisfying $$ 1+3^a = 3^b+5^c. $$
hookah's user avatar
  • 1,096
11 votes
1 answer
625 views

A congruence conjecture regarding $(r-s)^4-1 \equiv 0\!\pmod{4r^2s}$

Is the following conjecture true? Conjecture. If $r > s \ge 1$ are relatively prime integers such that \begin{equation} (r-s)^4-1 \equiv 0\!\pmod{4r^2s}, \tag{1} \end{equation} then $r-s = 1$ ...
Kieren MacMillan's user avatar
7 votes
3 answers
2k views

Solution to a Diophantine equation

Find all the non-trivial integer solutions to the equation $$\frac{a}{b+c}+\frac{b}{a+c}+\frac{c}{a+b}=4.$$
var's user avatar
  • 403
3 votes
1 answer
372 views

Is there an easy proof of this equation related to simultaneous Pell equations?

Working with the famous Baker-Davenport system of simultaneous Pell equations \begin{align} 3x^2-2 &= y^2, & 8x^2-7 &= z^2, \qquad(\star) \end{align} I am left, after a series of ...
Kieren MacMillan's user avatar
2 votes
2 answers
647 views

A Pell like equation

If one takes in general $(\star)\, \,x^2-dy^2=C$ where $d$, $C$ in $\mathbb{N}$. Taking $d=w^2p^2+p$ with $w\in \mathbb{Q}\ge 1$ and $p\in \mathbb{Z}$ which is verified (explained later), for the ...
Toni Mhax's user avatar
  • 785
1 vote
0 answers
500 views

A trivial application of Wilson's theorem to Brocard's Problem

Proposition: Let $W(1)$ be the set of all Wilson primes of order $1$ and suppose $n=p-1,$ where $p$ is a prime such that $p\notin W(1)$, then there are no integer solutions to the equation $$n!+1=m^2$$...
Maaz-ul-Haq's user avatar
0 votes
0 answers
183 views

A certain Pell Equation

Recently I came up with a positive solution $((x,y)\neq (\pm 1;0))$ to this diophantine equation $$ x^2-\left(w^2(2^{n-2}p)^2+2^n(2^{n-2}p)\right)y^2=1,\qquad n\geq 2, $$ where all variables are in $ ...
Toni Mhax's user avatar
  • 785
-2 votes
1 answer
168 views

Diophantine equation $10^n-a^3-b^3=c^2$

Consider the Diophantine equation: $10^n-a^3-b^3=c^2$, for $a$, $b$, $c$, and $n$ positive. Has this equation infinitely many solutions?
Enzo Creti's user avatar