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Integral formula of quantum dilogarithm

In the paper"Level N Teichmüller TQFT and Complex Chern-Simons Theory" arXiv:1612.06986, the authors study the quantum dilogarithm function: \begin{equation} \mathrm{D}_{\rm b}(x,n)=\prod_{...
color's user avatar
  • 109
3 votes
0 answers
115 views

On a functional equation of Mahler?

Recently, I was trying to introduce the concept of natural boundaries to a fellow math student, and what greater way to do this than using an example? In particular, I tried to use as an illustration, ...
Prelude's user avatar
  • 131
1 vote
0 answers
203 views

Construction of weight function to satisfy condition on given functional

Consider the following function : $$F(z) = \omega(z){\sin^2\left(\frac{c\Gamma(z)}{z}\right)}$$ Here, $\omega(z)$ is a weight we are going to consider The following two conditions should meet for $\...
bambi's user avatar
  • 375
3 votes
0 answers
646 views

On properties on a certain functional

Consider the following function: $$F(z) = \omega(z)\sin^2\left(\frac{c\Gamma(z)}{z}\right)$$ Here, $\omega(z)$ is a weight we have to construct and $c$ is a constant. The following three conditions ...
bambi's user avatar
  • 375
1 vote
0 answers
78 views

Related to derivative of Modified Bessel I function wrt the order

I recently met some problems related to the modified Bessel I funtions. Let $I(\nu,x):=I_\nu(x)$, and $I'_\nu(\nu,x):=\dfrac{\partial}{\partial \nu}I(\nu,x)$. Using maple, it seems that $Re(\dfrac{I'...
Wiener Schmidt's user avatar
1 vote
2 answers
437 views

Analytical predicate for integers over complex numbers

A complex number $z$ is an integer if and only if $\sin(\pi z)=0$. It follows that a complex number $z$ is an integer if and only $\sin^2(\pi z) = 0$. So for a real analytic function $f$ and any real ...
Stephan Wehner's user avatar
38 votes
2 answers
13k views

What, exactly, has Louis de Branges proved about the Riemann Hypothesis?

I know this is a dangerous topic which could attract many cranks and nutters, but: According to Wikipedia [and probably his own website, but I have a hard time seeing exactly what he's claiming] Louis ...
Zen Harper's user avatar
  • 1,990